Chapter 12 – Acid-Base Chemistry
Introduction
The terms acid and base have been used for several hundred years. Acids were substances that had a sour taste, were corrosive, and reacted with substances called bases. Substances that had a bitter taste, made skin slippery on contact, and reacted with acids were called bases. However, these simple definitions had to be refined as the chemical properties of acids and bases became better understood. The first chemical definition of acids and bases was made by Svante Arrhenius. An Arrhenius acid is a substance that produces H1+ ions when it is dissolved in water, and an Arrhenius base is a substance that produces OH1– ions when dissolved in water. In this theory, an acid ionizes in water much as an ionic substance, and the equilibrium constant for the reaction is called the acid ionization constant. For example, the ionization of the Arrhenius acid HCl in water is represented as follows:HCl → H1+ + Cl1−
HCl + NaOH → H2O + NaCl
12.1 Lewis Acids and Bases
Introduction
The broadest definition of acids and bases is that of Lewis. By this definition, a large number of reactions can be classified as acid-base reactions. In this section, we introduce Lewis acids and bases and the use of curved arrows to show the mechanism of a Lewis acid-base reaction. These topics will be used again in Chapter 13, Organic Chemistry.Prerequisites
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•5.6 Determining Lewis Structures (Draw Lewis structures.)
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•5.4 Lewis Symbols of the Elements (Identify lone pairs in a Lewis structure.)
-
•6.1 Molecular Shapes (Determine the number of electron regions around each atom in a Lewis structure.)
Objectives
-
•Define a Lewis acid and a Lewis base.
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•Describe a Lewis acid-base reaction.
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•Identify Lewis acids and bases.
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•Explain how curved arrows are used to show the mechanism of a Lewis acid-base reaction.
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•Distinguish between an electron transfer and a Lewis acid-base reaction.
12.1-1. Definitions
A Lewis acid-base reaction converts a lone pair on a base and an empty orbital on an acid into a covalent bond.
-
•A Lewis acid is a substance that has an empty orbital that it can use to share a lone pair to form a bond.
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•A Lewis base is a substance that has a lone pair that it can share in a covalent bond.
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•A Lewis acid-base reaction is the conversion of the lone pair on the base and the empty orbital of the acid into a covalent bond between the acid and the base.
Figure 12.1
12.1-2. Lewis Acids and Bases
Lewis Bases
-
•A Lewis base must contain at least one lone pair of electrons.
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•All anions are Lewis bases, but not all Lewis bases are anions.
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•The lone pair is frequently, but not always, located on oxygen or nitrogen atoms.
-
•The strength of a base is increased by electron density.
CH3O1− > HO1− > ClO1−
Figure 12.2: Examples of Lewis Bases
Lewis Acids
Lewis acids are often more difficult to identify. The following should help.-
•A Lewis acid must be able to accommodate an additional electron region (the new bond), so, if it obeys the octet rule, a Lewis acidic atom must have less than four regions.
-
•Attack by a lone pair is facilitated by positive charge, so Lewis acidity is strengthened by positive charge.
-
•All cations are Lewis acids, but not all Lewis acids are cations.
Figure 12.3: Examples of Lewis Acids
12.1-3. Lewis Acidity and Basicity and Orbital Energy
The bond between two atoms is covalent only when the interacting orbitals have similar energies because large energy separations favor ionic bonds. Thus, the formation of a coordinate covalent bond in a Lewis acid-base reaction is facilitated when the energy of the empty orbital of the Lewis acid is close to that of the lone pair of the Lewis base. The energies of lone pairs are typically lower than those of empty orbitals, so the strongest interactions occur when the energy of the lone pair is high for a lone pair and the energy of the empty orbital is low for an empty orbital. For example, consider the cases of Na1+ and Ag1+ as shown in the figure. The energy of the empty orbital of Ag1+ is much lower than that of Na1+; i.e., the energy of the empty orbital of Ag1+ is low for an empty orbital. Thus, the empty orbital on Ag1+ is sufficiently close to that of the lone pair on the Br1– ion that the Ag–Br bond is covalent. However, the energy of the empty orbital on Na1+ is so high that the Na–Br bond is ionic. Thus, Ag1+ is a sufficiently strong Lewis acid to react with Br1– ion, but the acidity of Na1+ is so weak that it does not. Indeed, Na1+ is such a weak Lewis acid (its orbitals are so high in energy) that it does not function as an acid in aqueous solutions. In general, H1+ and cations of metals with high effective nuclear charge (metals such as Ag and Pb that lie low and to the right of the periodic table) have empty orbitals that are relatively low in energy, so they are Lewis acidic, but the cations of metals on the left side of the periodic table are such weak Lewis acids that their acidity can be ignored in most cases. We conclude the following.
Strong Lewis acids have low-energy empty orbitals, and strong Lewis bases have high-energy lone pairs.
Figure 12.4: Lewis Acidity and Orbital Energy
The empty orbital on Ag is relatively low in energy, so it forms a covalent bond with
the lone pair on Br1– ion. The empty orbital on Na1+ is very high in energy, so its bonds to anions are ionic. Therefore, Ag1+ is a much stronger Lewis acid than Na1+, which is so weak that its acidity can usually be ignored.
12.1-4. Oxidants and Acids
Oxidizing agents and Lewis acids are both characterized by empty valence orbitals that are low in energy, while reducing agents and Lewis bases both have high-energy electrons. Consequently, many Lewis acids are also oxidants and many Lewis bases are also reductants. Indeed, oxidants and Lewis acids are often defined as electron acceptors, and reductants and Lewis bases as electron donors. The obvious question becomes, "What determines whether electrons are transferred or shared when a lone pair comes into contact with an empty orbital?" As has been the case so often in our study of chemistry, the answer lies in their relative energies: electrons do whatever is most efficient at increasing their electrical potential in order to lower their energy. If the energy of the empty orbital is lower than that of the lone pair, the electrons simply transfer from the reductant to the more positive electrical potential on the oxidant in a redox reaction. However, if the empty orbital is at higher energy, the electrons lower their energy by forming a covalent bond between an acid and a base, which increases their electrical potential by exposing them to part of the nuclear charge on the acid. The example of H1+, which is both an oxidant and an acid, is considered in Figure 12.5. If H1+ encounters a zinc atom, it behaves as an oxidant and accepts the higher energy electrons from the reductant zinc. However, electrons will not flow from a Br1– ion to the higher energy orbital on H1+, so the lone pair on Br1– ion lowers its energy by forming an H–Br covalent bond. Br1– is a base in the presence of H1+, but it is a reductant in the presence of something like Cl2 that has an empty orbital at lower energy (2 Br1– + Cl2 → Br2 + 2 Cl1–).
Figure 12.5: Protons as Oxidants and Reductants
(a) H1+ is an oxidizing agent in the presence of Zn because the electrons on Zn are higher in energy; i.e., the electrons transfer to lower orbitals; (b) H1+ is an acid in the presence of Br1– because the lone pair on Br1– is lower in energy; i.e., the electrons are shared with higher orbitals.
12.1-5. Curved Arrows in Lewis Acid-Base Reactions
Curved arrows pointing from a lone pair to an atom indicate that the lone pair is converted into a bonding pair, while curved arrows pointing from a bond to an atom are used to show that a bonding pair is converted into a lone pair on the atom.
Start of a Curved Arrow |
End of a Curved Arrow |
Reactant | Product | Effect |
---|---|---|---|---|
lone pair on atom B | atom A | The lone pair becomes an A–B bond. | ||
A–B bonding pair | atom A | The A–B bond becomes a lone pair on atom A. |
Table 12.1
Curved arrows will be used extensively in this chapter and the next chapter to explain the mechanisms of Lewis acid-base reactions.
12.1-6. Examples of Metals as Lewis Acids
Ag1+ ions have relatively low-energy empty orbitals, so they are good Lewis acids. Cl1– ions have lone pairs, so they are Lewis bases. In Figure 12.6a, a curved arrow from Cl1– to Ag1+ is used to show the conversion of a lone pair on the Cl1– ion into the AgCl bond in this Lewis acid-base reaction.
Figure 12.6a: Metal Ions as Lewis Acids: Precipitation of AgCl
Figure 12.6b: Metal Ions as Lewis Acids: Formation of Ag(NH3)21+
Figure 12.6c: Metal Ions as Lewis Acids: Formation of AlCl41–
The number of electron groups around the Lewis acidic atom changes with the formation of a bond, which changes the geometry and hybridization of the atom.
12.1-7. Curved Arrows in a Mechanism–an Example
SO3 + H2O
Figure 12.7a: SO3 + H2O Mechanism: Step 1
A lone pair on water is converted to an S–O bond and the π electrons of the S=O bond are converted into a lone pair. Lone pairs on other oxygen atoms have been omitted for clarity.
Figure 12.7b: SO3 + H2O Mechanism: Step 2
A proton is transferred from the oxygen with positive formal charge to a water molecule.
Figure 12.7c: SO3 + H2O Mechanism: Step 3
A proton is transferred from a solvent molecule to an oxygen atom with negative formal charge.
12.1-8. Comparing Redox and Lewis Acid-Base Reactions
H1+ as an oxidant when electrons are higher in energy
H1+ as an acid when electrons are lower in energy
An electron pair behaves like a reducing agent when an empty orbital is much lower in energy, but like a Lewis base when the empty orbital is higher in energy.
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•Reductant: a substance that can transfer electrons to another substance. Good reducing agents are characterized by high-energy electrons.
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•Lewis base: a substance that can donate an electron pair to a covalent bond with another substance. Good Lewis bases are characterized by high-energy electron pairs.
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•Oxidant: a substance that can accept electrons from another substance. Good oxidizing agents are characterized by low-energy, empty orbitals.
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•Lewis acid: a substance that can accept an electron pair into an empty orbital to form a covalent bond. Good Lewis acids are characterized by low-energy, empty orbitals.
Figure 12.8: H1+ as oxidant
Figure 12.9: H1+ as an acid
12.2 Brønsted Acids
Introduction
Although the Lewis definition is the broadest, the Brønsted-Lowry (or simply Brønsted) definition is the most frequently used acid-base definition in aqueous solutions. In this section, we define Brønsted acids and bases and introduce Brønsted acid-base reactions.Prerequisites
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•10.5 Electrolytes (Differentiate between strong electrolytes and nonelectrolytes based upon the ability of their aqueous solutions to conduct electricity.)
Objectives
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•Write the name of an acid from its formula or the formula from its name.
12.2-1. Brønsted Definition
Brønsted acid-base reactions are proton transfer reactions.
12.2-2. Aqueous Solutions of Acids and Base
[H3O1+] dictates the acidity and [OH1–] dictates the basicity of an aqueous solution.
HX + H2O H3O1+ + X1−
F1− + H2O HF + OH1−.
12.2-3. Acids and Bases are Electrolytes
Strong acids and bases are strong electrolytes, while weak acids and bases are weak electrolytes.
The light bulb does not glow, so there are no ions in solution. The fact that HX produces no ions in solution indicates that HX is a nonelectrolyte. An aqueous solution is represented as HX to show that the molecules do not ionize in water. | |
The light shines brightly, which means that the concentration of H3O1+ ions in solution is relatively high. Acids that ionize completely in water to produce high concentrations of H3O1+ ions are called strong acids. An aqueous solution is represented as H3O1+ + X1– to show that the molecules ionize completely in water. | |
The light shines, so HX is an electrolyte, but the intensity of the light is much less than for a strong acid. The dimness of the light indicates that the H3O1+ ion concentration is low. Thus, only a fraction of the HX molecules in water ionize. Acids that ionize only partially in water are called weak acids. An aqueous solution is represented as HX because HX is the predominant species in solution. |
Table 12.2: Determining the Relative Concentrations of H3O1+ Ions in a 0.1 M of HX
12.2-4. Examples
pure H2O | Water is a nonelectrolyte and represented as H2O. There are ions in water, but their concentrations are very small. | |
0.10 M HNO3 | Nitric acid is a strong acid, and its aqueous solution is represented as H3O1+(H1+) + NO31–. The following reaction is so extensive that there are essentially no nitric acid molecules in solution. Recall that extensive reactions are expressed with single arrows as in the following. HNO3 + H2O → H3O1+ + NO31– |
|
0.10 M KOH | KOH ionizes completely in water and is a strong electrolyte. It is a strong base because one of the ions that it produces is the OH1– ion. Thus, aqueous KOH is written as K1+ + OH1–. | |
0.10 M CH3OH | CH3OH is a nonelectrolyte. It is neither an acid nor a base—it is an alcohol (wood alcohol). An aqueous solution of methanol is written as CH3OH. | |
0.10 M HNO2 | The light bulb glows dimly, so nitrous acid is a weak acid and its aqueous solutions are represented as HNO2, not as hydronium ion and nitrite ion, to show the predominant form. The following reaction is not extensive (only about 5% of the HNO2 molecules react), so double arrows are used. HNO2 + H2O H3O1+ + NO21– |
|
0.10 M NH3 | The light bulb glows dimly, so NH3 is a weak electrolyte. About 1% of the ammonia molecules react with water to produce ions, so an aqueous solution is represented as NH3 molecules, not as the ions. Double arrows are used in the reaction. NH3 + H2O NH41+ + OH1– The proton is transferred from water to ammonia, so NH3 is a weak base. |
Table 12.3
12.2-5. Brønsted Acids
An acidic proton must be bound to an electronegative atom, which is oxygen in most acids that contain an oxygen atom.
Acidic protons are usually written first in the formula of acids to indicate that they are acidic.
Figure 12.10: Only Protons Bound to Highly Electronegative Atoms are Acidic
Acetic acid contains three hydrogen atoms bound to carbon that are not acidic because carbon is not highly electronegative and the C–H bond is not polar. It also contains one hydrogen atom attached to highly electronegative oxygen that is acidic because the O–H bond is very polar.
12.2-6. Binary Acids and Oxoacids
Binary Acids
Binary acids have a proton and only one other element. HCl, HBr, and HI are strong acids, but HF is a weak acid. Note: these acids plus NH41+, H2S, and H–CN are the only acids that we deal with that do not have O–H bonds.-
•Note that HCN is not a binary acid because it contains atoms from three different elements. However, HCN is a gas and its name (hydrogen cyanide) ends in -ide, so it is treated as a binary compound.
Figure 12.11: Some Binary Acids
Oxoacids
Most acidic protons are bound to an oxygen atom. Such acids are called oxoacids. The acidic protons are shown in blue in Figure 12.12.
Figure 12.12: Some Common Oxoacids
Naming Acids
12.2-7. Binary Acids
The pure compounds that produce binary acids are named using the rules outlined in Section 4.6 until they are dissolved in water. For example, HCl is hydrogen chloride and H2S is hydrogen sulfide. However, when these substances are dissolved in water, they produce acidic solutions that are named in the following manner.-
•Replace hydrogen with hydro.
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•Change the -ide ending to -ic.
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•Add the word acid.
Formula | Name as Pure Substance | Formula | Name as Aqueous Solution | |
---|---|---|---|---|
HF(g) | hydrogen fluoride | HF(aq) | hydrofluoric acid | |
HCl(g) | hydrogen chloride | HCl(aq) | hydrochloric acid | |
HI(g) | hydrogen iodide | Hl(aq) | hydroiodic acid | |
HCN(g) | hydrogen cyanide | HCN(aq) | hydrocyanic acid | |
H2S(g) | hydrogen sulfide | H2S(aq) | hydrosulfuric acid |
Table 12.4: Names of Some Common Binary Acids
12.2-8. Polyatomic Acids
Polyatomic acids are derived from polyatomic ions and are named by-
•changing the -ate ending of the polyatomic ion to -ic or
-
•changing the -ite ending of the polyatomic ion to -ous and
-
•adding the word acid.
Ion Formula | Ion Name | Acid Formula | Acid Name | |
---|---|---|---|---|
C2H3O21– | acetate ion | HC2H3O2 | acetic acid | |
SO32– | sulfite ion | H2SO3 | sulfurous acid | |
SO42– | sulfate ion | H2SO4 | sulfuric acid | |
NO21– | nitrite ion | HNO2 | nitrous acid | |
NO31– | nitrate ion | HNO3 | nitric acid | |
ClO1– | hypochlorite ion | HClO | hypochlorous acid | |
ClO21– | chlorite ion | HClO2 | chlorous acid | |
ClO31– | chlorate ion | HClO3 | chloric acid | |
ClO41– | perchlorate ion | HClO4 | perchloric acid | |
PO43– | phosphate ion | H3PO4 | phosphoric acid |
Table 12.5: Acids Derived from Polyatomic Anions
12.2-9. Acid Naming Exercise
Exercise 12.1:
Name the following acids.
H2CO3
o_carbonic acid_s
The CO32– ion is the carbonate ion, so the acid is carbonic acid.
HCO31–
o_hydrogen carbonate ion_s
Acids that are ions are named as the ion, so HCO31– is the hydrogen carbonate ion. Note that "bicarbonate ion" is also used.
Write formulas for the following acids. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
selenous acid
o_H_2SeO_3_s
The -ous ending tells us that the acid is derived from a polyatomic ion with an -ite ending; i.e., the acid is derived from the selenite ion. Selenium is a Group 6A nonmetal, so its chemical properties are expected to be similar to those of sulfur. The sulfite ion is SO32–, so selenite is SeO32– and selenous acid is H2SeO3. It contains two O-H bonds.
hydroselenic acid
o_H_2Se_s
The name starts with hydro, so this is a binary acid of H and Se. Se is in Group 6A, so it is expected to form a –2 anion, which requires two protons. Hydroselenic acid is H2Se.
12.3 Brønsted Acid-Base Reactions
Introduction
Brønsted acid-base reactions all involve transferring a single proton from the acid to the base. In this section, we see how to predict the products of a Brønsted acid-base reaction.Objectives
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•Identify the conjugate base of an acid.
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•Identify the conjugate acid of a base.
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•Describe a Brønsted acid-base reaction in terms of the proton transfer.
12.3-1. Conjugate Base
The conjugate base of an acid is formed by removing one, and only one, proton from the acid.
Exercise 12.2:
Use the above definition to determine the conjugate base of each of the following.(Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
NH3
o_NH_2^1-_s
The conjugate base is formed by removing a single H1+.
NH3 → NH21– + H1+
NH21– is the conjugate base of NH3.
NH3 → NH21– + H1+
NH21– is the conjugate base of NH3.
H2O
o_OH^1-_s
The conjugate base is formed by removing a single H1+.
H2O → OH1– + H1+
OH1– is the conjugate base of H2O.
H2O → OH1– + H1+
OH1– is the conjugate base of H2O.
HSO31–
o_SO_3^2-_s
The conjugate base is formed by removing a single H1+.
HSO31– → SO32– + H1+
SO32– is the conjugate base of HSO31–.
HSO31– → SO32– + H1+
SO32– is the conjugate base of HSO31–.
HC2H3O2
o_C_2H_3O_2^1-_s
The conjugate base is formed by removing a single H1+.
HC2H3O2 → C2H3O21– + H1+
C2H3O21– is the conjugate base of HC2H3O2.
HC2H3O2 → C2H3O21– + H1+
C2H3O21– is the conjugate base of HC2H3O2.
12.3-2. Conjugate Acid
The conjugate acid of a base is formed by adding one proton to the base.
Exercise 12.3:
Determine the conjugate acid of each of the following.(Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
NH3
o_NH_4^1+_s
The conjugate acid is formed by gaining a single H1+.
NH3 + H1+ → NH41+
NH41+ is the conjugate acid of NH3.
NH3 + H1+ → NH41+
NH41+ is the conjugate acid of NH3.
H2O
o_H_3O^1+_s
The conjugate acid is formed by gaining a single H1+.
H2O + H1+ → H3O1+
H3O1+ is the conjugate acid of H2O.
H2O + H1+ → H3O1+
H3O1+ is the conjugate acid of H2O.
HSO31–
o_H_2SO_3_s
The conjugate acid is formed by gaining a single H1+.
HSO31– + H1+ → H2SO3
H2SO3 is the conjugate acid of HSO31–.
HSO31– + H1+ → H2SO3
H2SO3 is the conjugate acid of HSO31–.
CO32–
o_HCO_3^1-_s
The conjugate acid is formed by gaining a single H1+.
CO32– + H1+ → HCO31–
HCO31– is the conjugate acid of CO32–.
CO32– + H1+ → HCO31–
HCO31– is the conjugate acid of CO32–.
12.3-3. Brønsted Acid-Base Reactions
The chemical equation for a Brønsted acid-base reaction consists of two conjugate acid-base pairs and nothing else.
12.4 Extent of Proton Transfer
Introduction
Not all acids and bases react very well with one another, and the degree to which they do react is referred to as the extent of proton transfer. If the extent of proton transfer is great, the reaction is usually written with a single arrow, but if the transfer is not extensive, the reaction is written with double arrows.Prerequisites
Objectives
-
•Write the chemical equation for the reaction of a strong acid, a weak acid, or a weak base with water.
12.4-1. Comparing Conjugate Acid-Base Strengths
The weaker an acid is, the stronger is its conjugate base.
HA + B1− A1− + HB
-
1stronger acid + stronger base → weaker base + weaker acid
-
2reacting and produces acids of comparable strengths and reacting and produced bases of comparable strengths
-
3weaker acid + weaker base → stronger base + stronger acid
12.4-2. Extent as a Function of Relative Acid Strengths
If the reacting acid is the stronger acid, then the reacting base is the stronger base, and the reaction is extensive.
-
•Forward Reaction: stronger acid + stronger base is extensive.
-
•Reverse Reaction: weaker acid + weaker base produces little of the stronger acid and base.
-
•Equilibrium: almost exclusively the weaker acid and base, which are the products in this reaction type.
-
•A single arrow typically used to indicate that very little of the limiting reactant is present at equilibrium.
If the acid strengths are comparable then the concentrations of substances on both sides of the equilibrium are comparable.
-
•Forward Reaction: moderate acid + moderate base produces moderate amounts of products.
-
•Reverse Reaction: moderate acid + moderate base produces moderate amounts of reactants.
-
•Equilibrium: moderate amounts of all species.
-
•All species present in significant amounts at equilibrium, so reaction is not extensive and double arrows should be used.
If the reacting acid is much weaker than the produced acid then little product is formed.
-
•Forward Reaction: weaker acid + weaker base produces little of the stronger base and stronger acid.
-
•Reverse Reaction: stronger acid + stronger base react extensively to produce weaker acid and base.
-
•Equilibrium: almost exclusively the weaker acid and base, which are the reactants in this reaction type.
-
•Little product, but some product is formed as there is some reaction, and double arrows would have to be used when writing the chemical equation.
12.4-3. Relative Acid Strength Exercise
Exercise 12.4:
Solutions containing equal concentrations of HA, A1–, HB, and B1– are mixed. After reaction, the resulting solution is composed almost
exclusively of HA and B1– determine relative acid and base strengths.
-
Which is the stronger acid?
-
-
-
-
-
Which is the weaker base?
-
-
-
-
-
Which is the stronger base?
-
-
-
-
-
Which is the weaker acid?
-
-
-
-
12.4-4. Equilibrium Constant Expression
The equilibrium mixture is always dominated by the weaker acid and base.
Chemical Equation: HA + B1− A1− + HB
Equilibrium Constant Expression: K =
[A1−][HB] |
[HA][B1−] |
HA >> HB; K >> 1
Stronger Acid | Stronger Base | Weaker Base | Weaker Acid | |||
---|---|---|---|---|---|---|
HA | + | B1– | → | A1– | + | HB |
At equilibrium, [A1–][HB] >> [HA][B1–], so K >> 1, consistent with an extensive reaction. Note: A1– is the weaker base and HB is the weaker acid!
HA ~ HB; K ~ 1
Acid | Base | Base | Acid | |||
HA | + | B1– | A1– | + | HB |
[A1–][HB] ~ [HA][B1–] at equilibrium, so K ~ 1 when the reacting and produced acids are of similar strengths.
HA << HB; K << 1
Weaker Acid | Weaker Base | Stronger Base | Stronger Acid | |||
---|---|---|---|---|---|---|
HA | + | B1– | A1– | + | HB |
At equilibrium, [HA][B1–] >> [A1–][HB], so K << 1, consistent with a reaction that in not extensive. Note that HA is the weaker acid and B1– is the weaker base. In each case where the acid strengths are much different, the product of the equilibrium concentrations of the weaker acid and base are always much greater than the product of the concentrations of the stronger acid and base. That is, the equilibrium mixture is dominated by the weaker acid and base.
12.4-5. Single vs. Double Arrows
Single arrows are sometimes used to indicate that a reaction is extensive. We arbitrarily assume that K > 1000 for such reactions.
K > ~1000.
If K < 1000,
the reverse reaction cannot be ignored, and the value of K must be used when determining the amount of product that is formed. Equations for reactions of this type should be written with double arrows () to emphasize the importance of the reverse reaction. An example of each case is provided in the following table.
HF + ClO1− → F1− + HOCl |
K =
|
K >> 1 so,
|
||
HF + NO21− F1− + HNO2 |
K =
|
K ~ 1 so,
|
||
HCN + F1− CN1− + HF |
K =
|
K << 1 so,
|
Table 12.6
12.4-6. Proton Transfer Exercise
Exercise 12.5:
Consider the following acid-base equilibrium. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
HOCl + CN1– OCl1– + HCN K ~ 100
stronger acid
o_HOCl_s
K > 1, so the reacting acid (HOCl) is stronger than the produced acid.
stronger base
o_CN^1-_s
K > 1, so the reacting base is stronger than the produced base. The reacting base is CN1–.
weaker base
o_OCl^1-_s
The conjugate base of the stronger acid is the weaker base, so OCl1– is the weaker base.
weaker acid
o_HCN_s
The conjugate acid of the stronger base is the weaker base, so HCN is the weaker acid.
Acid-Base Reactions Involving Water
12.4-7. The Role of Water
All of the remaining acid-base reactions in this chapter occur in water, which can act as both as an acid and a base. Thus, the reaction with water is an important consideration in acid-base chemistry. The general reaction of an acid and water can be represented as the following.HA + H2O A1− + H3O1+
-
•Strong acids: Strong acids react extensively with water. In order for the reaction to be extensive, HA must be a stronger acid than H3O1+. In other words, any acid stronger than hydronium ion is considered to be a strong acid.
-
•Weak acids: Weak acids do not react extensively with water. Thus, weak acids are weaker acids than H3O1+ ions.
12.4-8. Strong Acids in Water
Strong acids are represented as H3O1+ in acid-base reactions in water.
Figure 12.13
12.4-9. Weak Acids in Water
Weak acids are represented by the formula of the acid not by H3O1+ in acid-base reactions.
HA + H2O A1− + H3O1+
K < 1.
The reactions are written with double arrows to emphasize the importance of the back reaction. The concentration of HA is much greater than that of A1– or H3O1+ in a solution of a weak acid. Consequently, weak acids are represented by the formula of the acid not by H3O1+ in acid-base reactions. The example of hydrofluoric acid is considered below.
Figure 12.14
12.4-10. Bases in Water
All anions are bases because an anion can always accept a proton.
-
•Strong Bases: A1– is a strong base if the above reaction is extensive, which is the case when the base is a stronger base than hydroxide ion.
-
•Weak Bases: A1– is a weaker base than hydroxide ion, so it does not react extensively with water.
NH3 + H2O NH41+ + OH1−
12.5 Acid and Base Strengths
Introduction
We have now seen that the extent of an acid-base reaction depends upon the relative strengths of the reacting and produced acids. In this section, we show how the relative strengths of acids are measured and tabulated.Prerequisites
Objectives
-
•Relate acid strength of HA to the strength of the H–A bond.
-
•Explain why the acid strength of HA also depends upon the electronegativity of A.
-
•Predict the stronger of two acids with comparable bond strengths from the electronegativity of the atom to which the H is bound.
-
•Rate the relative strengths a series of oxoacids (HOX) based on the electron withdrawing or donating abilities of X.
12.5-1. Bond Strengths
Knowledge of the relative acid strengths of the reacting and produced acids allow us to predict the extent of reaction, so we now examine the factors that dictate those strengths. The acid strength of HA is related to the ease with which the H–A bond is broken. If the H–A bond is weaker, then HA gives up the proton more easily and is a stronger acid, but if the bond is stronger, then it does not give up the proton as readily and is a weaker acid. Other factors being equal, we can conclude the following.
If the H–A bond is strong, then HA is a weak acid.
Exercise 12.6:
List the acids HF, HCl, and HBr in order of increasing acid strength given that
DHF = 565 kJ/mol, DHCl = 431 kJ/mol, and DHBr = 366 kJ/mol.
(Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
o_HF_s
Other factors being the same, acid strength should increase the order of decreasing bond strength. The HBr bond is the weakest, and HBr is the strongest acid. The HF bond is the strongest bond, and HF is the weakest acid. Consequently, the following is the order of increasing acid strength:
HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
< HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
o_HCl_s
Other factors being the same, acid strength should increase the order of decreasing bond strength. The HBr bond is the weakest, and HBr is the strongest acid. The HF bond is the strongest bond, and HF is the weakest acid. Consequently, the following is the order of increasing acid strength:
HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
< HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
o_HBr_s
Other factors being the same, acid strength should increase the order of decreasing bond strength. The HBr bond is the weakest, and HBr is the strongest acid. The HF bond is the strongest bond, and HF is the weakest acid. Consequently, the following is the order of increasing acid strength:
HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
List the conjugate bases in order of increasing base strength. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
o_Br^1-_s
The base strength of B1– increases as the strength of the H-B bond increases. Thus, F1– ion is the strongest base because it forms the strongest bond to hydrogen, and Br1– is the weakest base because the H-Br bond is the weakest of the three bonds. The following is the order of increasing base strength:
Br1– < Cl1– < F1–.
< Br1– < Cl1– < F1–.
o_Cl^1-_s
The base strength of B1– increases as the strength of the H-B bond increases. Thus, F1– ion is the strongest base because it forms the strongest bond to hydrogen, and Br1– is the weakest base because the H-Br bond is the weakest of the three bonds. The following is the order of increasing base strength:
Br1– < Cl1– < F1–.
< Br1– < Cl1– < F1–.
o_F^1-_s
The base strength of B1– increases as the strength of the H-B bond increases. Thus, F1– ion is the strongest base because it forms the strongest bond to hydrogen, and Br1– is the weakest base because the H-Br bond is the weakest of the three bonds. The following is the order of increasing base strength:
Br1– < Cl1– < F1–.
Br1– < Cl1– < F1–.
12.5-2. Bond Breaking
Bond energies are not sufficient to explain relative acid strengths because the tabulated values are for the bonds in the gas phase, not in solution. In addition, the bonding pair is divided between the bound atoms to produce atoms, not ions. The bond energy process is compared to the solution process for HF, HCl, and CH4 in Figures 12.15a and 12.15b.
Figure 12.15a: Two Ways to Break Bonds–Gas Phase
In the gas phase, the bonding pair is split so that each atom gets one electron to produce atoms, not ions.
Figure 12.15b: Two Ways to Break Bonds–Solution Phase
In the solution phase, the bonding pair remains on the more electronegative atom to produce ions, not atoms.
12.5-3. Electronegativity
Breaking the H–A bond in an acid-base reaction produces the ions, and ion formation is favored by large electronegativity differences between the bound atoms. Thus, acid strengths also increase as the electronegativity of the atom to which the hydrogen is bound increases.
Exercise 12.7:
You are given the following compounds and the bond energies of the bonds to hydrogen.
HF | HCl | CH4 |
DHF = 565 kJ/mol | DHCl = 431 kJ/mol | DCH = 413 kJ/mol |
Fill in the following. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
strongest of the three acids
o_HCl_s
The H-Cl and C-H bonds have comparable strengths that are substantially lower than the H-F bond energy. Thus, either the H-Cl or CH4 is predicted to the strongest acid. However, the H-Cl bond is polar, while the C-H bond is not. Consequently, the C-H bond is not acidic and HCl is the strongest acid of the three compounds. Note that HF is more polar than HCl, but both bonds are very polar, so the bond energy difference dominates in this case.
weakest acid
o_CH_4_s
The C-H bond is not polar, so forming H1+ ions is very difficult. Thus, C-H bonds are not acidic even though they are weaker than some of the bonds in relatively strong acids! CH4 is the weakest acid of the three compounds. The fact that the C-H bonds are not acidic is indicated by the fact that the hydrogen atoms are not written first in the formula.
12.5-4. Oxoacid Strengths
Oxoacids are acids in which the acidic hydrogen is attached to an oxygen atom. The strength of the oxoacid H–O–X depends upon the strength of the H–O bond. Anything that withdraws electron density from the H–O bond, weakens the bond and makes the acid stronger. Thus, the strength of the acid increases with increases in the electronegativity or oxidation state of X.-
•If X is highly electronegative, it withdraws electron density of the O–H bond, which weakens the bond and makes the acid stronger. Thus, H2SO4 is a stronger acid than H2SeO4 because S is more electronegative than Se.
-
•The ability of X to withdraw electron density from the O–H bond also increases as its oxidation state increases. Thus, H2SO4 is a stronger acid than H2SO3 because the oxidation state of S is higher in H2SO4.
HOH | H–O–H (water) is both a very weak acid and a very weak base. In fact its acid and base strengths are equal. |
HOCH3 | CH3 groups are electron donating, so the oxygen atom is more electron rich than in water. Consequently, CH3OH is a better base than water. Alternatively, the added electron density in the O–H bond strengthens the bond, which makes CH3OH a weaker acid than water. |
HOCl | Cl is electron withdrawing and is more electronegative than H. Removing electron density from OH has two effects: the oxygen is not as electron rich, so HOCl is a weaker base, and the O–H bond is weakened, so HOCl is a stronger acid. Thus, HOCl is a stronger acid and weaker base than water. |
HOClO | OClOH (HClO2) is the strongest acid and weakest base in this group. This is because the additional oxygen atom removes even more electron density than the single Cl, so it is a stronger acid than HOCl. Alternatively, the oxidation state of Cl goes from +1 in HClO to +3 in HClO2. The increase in oxidation state withdraws electron density from OH, which makes it a weaker base and a stronger acid. |
Table 12.7
12.5-5. Example
Exercise 12.8:
Use the following rules to determine whether each of the reactions is extensive or not.
-
•Extensive acid-base reactions occur when the reacting acid and base are much stronger than the produced acid and base.
-
•The stronger oxoacid is the one in which the central atom is more electronegative and/or in the higher oxidation state.
-
HSO41– + H2SO3 H2SO4 + HSO31–
-
-
-
H3PO4 + H2AsO41– H2PO41– + H3AsO4
-
-
12.6 Acid Dissociation Constant, Ka
Introduction
The extent of an acid-base reaction depends upon the strengths of the reacting and produced acids, and the acid dissociation constants of the acids give us those relative strengths.Prerequisites
-
•9.11-2. Examples of Equilibrium Constant Expressions (Write the equilibrium constant expression for a reaction that involves both aqueous solutes liquid water.)
-
•9.11 Equilibrium and the Equilibrium Constant
Objectives
-
•Write the acid dissociation constant expression for an Arrhenius acid and the chemical equation to which it applies.
-
•Rate the relative acid strengths of series of Arrhenius acids given their acid dissociation constants.
-
•Write the acid dissociation constant expression for a Brønsted acid and the chemical equation to which it applies.
-
•Rate the relative acid strengths of series of Brønsted acids given their acid dissociation constants.
-
•Determine the equilibrium constant for an acid-base reaction from the acid dissociation constants of the reacting and produced acids.
12.6-1. Arrhenius Definition
Arrhenius acids ionize in water rather than react with it. Consequently, H1+ is produced rather than H3O1+.
HA H1+ + A1−
Ka =
[H1+][A1−] |
[HA] |
12.6-2. Brønsted Ka
The dissociation constant of an acid, Ka, is the equilibrium constant for the reaction of the acid with water.
Brønsted Definition of Acid Strength
Brønsted acids do not dissociate in water, they react with it, so the equilibrium reaction becomesHA + H2O H3O1+ + A1–.
The equilibrium constant for the reaction is the following.
Ka =
[H3O1+][A1−] |
[HA] |
HCl + H2O → H3O1+ + Cl1− Ka =
= >> 1
[H3O1+][Cl1−] |
[HCl] |
HClO + H2O H3O1+ + ClO1− Ka =
= 3.5 × 10−8
[H3O1+][ClO1−] |
[HClO] |
H2SO3 + H2O H3O1+ + HSO31− Ka =
= 1.5 × 10−2
[H3O1+][HSO31−] |
[H2SO3] |
HS1− + H2O H3O1+ + S2− Ka =
= 1.3 × 10−13
[H3O1+][S2−] |
[HS1−] |
H3O1+ + H2O H2O + H3O1+ Ka =
= 1
[H3O1+] |
[H3O1+] |
12.6-3. Determining K for an Acid-Base Reaction
The equilibrium constant for an acid-base reaction equals the acid dissociation constant of the reacting acid divided by that of the produced acid.
12.6-4. Determining K Exercise
Exercise 12.9:
Use the following Ka values to answer the questions.
Acid | Ka |
---|---|
HF | 7.2 × 10–4 |
HNO2 | 4.0 × 10–4 |
NH41+ | 5.6 × 10–10 |
HCN | 4.0 × 10–10 |
What is the strongest acid? (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
What is the acid with the strongest conjugate base? (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
o_HF_s
The acid with the largest Ka is HF, so it is the strongest acid.
What is the acid with the strongest conjugate base? (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
o_HCN_s
The acid with the smallest Ka is HCN, so it is the weakest acid. Conjugate base strengths are opposite the acid strengths, so F1– ion would be the weakest base and CN1– ion the strongest base.
Are the following reactions extensive enough to be expressed with single arrows?
-
HCN + NH3 CN1– + NH41+
-
K =
= 0.714.0 × 10−10 5.6 × 10−10 -
-
HF + CN1– F1– + HCN
-
-
K =
= 1.8 × 1067.2 × 10−4 4.0 × 10−10
K >> 103, so essentially all of one reactant will be consumed and the chemical equation could be written with a single arrow.
12.6-5. Predicting Extent Exercise
Exercise 12.10:
Use the following Ka values to determine the equilibrium constant for the reaction of each of the acids with ClO1– and indicate whether a single arrow can be used to describe the reaction.
Acid | Ka | Base |
---|---|---|
HF | 7.2 × 10–4 | F1– |
H2S | 1.0 × 10–7 | HS1– |
HClO | 3.5 × 10–8 | ClO1– |
HCN | 4.0 × 10–10 | CN1– |
HS1– | 1.3 × 10–13 | S2– |
HF
K =
2.1e4___
HF + ClO1– → F1– + HClO
Reacting acid is HF. Produced acid is HClO.
Reacting acid is HF. Produced acid is HClO.
K =
=
= 2.1e+04
Ka(HF) |
Ka(HClO) |
7.2e−04 |
3.5e−08 |
H2S
K =
2.9___
H2S + ClO1– HS1– + HClO
Reacting acid is H2S. Produced acid is HClO.
Reacting acid is H2S. Produced acid is HClO.
K =
=
= 2.9
Ka(H2S) |
Ka(HClO) |
1.0e−07 |
3.5e−08 |
HCN
K =
1.1e-2___
HCN + ClO1– CN1– + HClO
Reacting acid is HCN. Produced acid is HClO.
Reacting acid is HCN. Produced acid is HClO.
K =
=
= 1.1e−02
Ka(HCN) |
Ka(HClO) |
4.0e−10 |
3.5e−08 |
HS1–
K =
3.7e-6___
HS1– + ClO1– S2– + HClO
Reacting acid is HS1–. Produced acid is HClO.
Reacting acid is HS1–. Produced acid is HClO.
K =
=
= 3.7e−06
Ka(HS1−) |
Ka(HClO) |
1.3e−13 |
3.5e−08 |
12.7 Solutions of Weak Bases
Introduction
Water is also an acid, so it can react with weak bases to produce hydroxide ion and the conjugate acid of the weak base.12.7-1. Most Anions are Weak Bases
Weak bases react with water to produce hydroxide ion and their conjugate acid.
12.8 Acid Base Table
Introduction
Acid-base reactions are extensive when the reacting acid is stronger than the produced acid. Acid strengths are measured by the acid dissociation constants for the acids. Combining these two facts, we can now write equations for acid-base reactions and determine if they are extensive.Objectives
-
•Predict whether an acid-base reactions is extensive based on the positions of the acid and base in the acid-base table.
-
•Identify the reactants to be used in a net equation for an acid-base reaction.
-
•Use the acid base table to write equations for acid-base reactions and to determine the equilibrium constant for the reaction.
-
•Decide whether an acid-base reaction is better represented with a single or a double arrow.
12.8-1. Using an Acid-Base Table Video
The Acid-Base Table
12.8-2. Using the Acid-Base Table to Write Chemical Equations
Using the Acid-Base Table for Chemical Equations
12.8-3. Acid-Base Table
Acid base reactions are extensive when the reacting acid is stronger than the produced acid, and the relative acid strengths can be deduced from the acid dissociation constants. Consequently, tables of acids and their Ka values are common. The acid-base table used in the text includes the acid, its Ka, and its conjugate base. Thus, both the reactants and the products of an acid-base reaction can be found in the table. The acid-base table used in this text is given in the Acid-Base Table resource. It lists the acids in the left column, their Kas in the center column, and their conjugate bases in the right column. Acid strengths decrease and base strengths increase going down the table. This arrangement puts the strongest acid (HClO4) in the upper left corner and the strongest base (O2– ion) in the lower right corner. Therefore, consider the following.
Acid-base reactions are extensive when the reacting acid is above (stronger than) the produced acid in the table.
Figure 12.16a: Reactivity from the Relative Positions of Reactants and Products
HF + OH1– → F1– + H2O.
Figure 12.16b: Reactivity from the Relative Positions of Reactants and Products
Figure 12.16c: Reactivity from the Relative Positions of Reactants and Products
12.8-4. Acid-Base Table Examples
We now use the acid-base table to write chemical equations for the acid-base reactions that result when the following solutions are mixed and use Equation 12.1K =
to determine their equilibrium constants. We use the relative positions of the reactants in the table and the equilibrium constants to indicate whether the reactions are extensive. Remember that the acid strengths increase going up the table, but base strengths increase going down the table. View the Acid-Base Table resource.
Ka of reacting acid |
Ka of produced acid |
Hydrogen chloride gas is bubbled into water.
The relative reactant positions and their Ka values from the table in the resources are given in Figure 12.17a. Note that the reactant is hydrogen chloride, not hydrochloric acid, so the reacting acid is HCl. The reacting base is then water. The products of the reaction are Cl1–, the conjugate base of the reacting acid, and H3O1+, the conjugate acid of the reacting base. The acid is above the base, so we expect a favorable reaction. Note that the Ka values of the strong acids are given simply as << 1 because they are so large that they cannot be determined accurately. We use Equation 12.1K =
to determine that the value of the equilibrium constant is very large, so a single arrow should be used. Thus, dissolving Ka of reacting acid |
Ka of produced acid |
HCl(g)
in water produces hydrochloric acid, which is a solution of hydronium and chloride ions.
Figure 12.17a
Solutions of hydrocyanic acid and potassium nitrite are mixed.
We identify HCN as the reacting acid, K1+ as a spectator ion, and the NO21– ion as the reacting base. The reactants and their Ka values as determined from the acid-base table are given in Figure 12.17b. The reacting acid is below the reacting base, so little proton transfer is expected. Using Equation 12.1K =
, we determine that the equilibrium constant is only 1.0 × 10–6, so very little product would form and double arrows would have to be used in the chemical equation.
Ka of reacting acid |
Ka of produced acid |
Figure 12.17b
A solution of potassium hypochlorite is added to hydrochloric acid.
We identify the K1+ ion as a spectator ion and the ClO1– ion as the reacting base. HCl is leveled to H3O1+ + Cl1– in water, so H3O1+ is the reacting acid, while Cl1– is also a spectator ion. We retrieve the reacting acid and base from the acid-base table as shown in Figure 12.17c. The acid is well above the base, so an extensive proton transfer is expected, and using Equation 12.1K =
, we determine that K = 2.9 × 107. Thus, the reaction can be written with a single arrow.
Ka of reacting acid |
Ka of produced acid |
Figure 12.17c
Ammonia is added to water.
We identify NH3 as the reacting base and H2O as the reacting acid. The relative positions and Ka values of the reactants as given in the acid-base table are shown in Figure 12.17d. The base is well above the acid, so little proton transfer is expected. Indeed, K = 1.8 × 10–5 for the reaction, so double arrows should be used for the reaction of this weak base with water.
Figure 12.17d
Hydrofluoric acid is added to a solution of potassium hydrogen sulfide.
HF is the reacting acid and K1+ is a spectator ion. The HS1– ion has a proton and is an anion, so it can behave as either and acid or a base, but the HF will not react with another acid, so HS1– is the reacting base in this reaction. The acid is above the base so the transfer is favorable with an equilibrium constant of 7.2 × 103, so a single arrow can be used in the net equation to show that essentially all of at least one of the reactants disappears.
Figure 12.17e
12.8-5. Identifying the Reactants
Identifying the reacting species is the first thing you must do when writing the net ionic equation for an acid-base equation. Remember the following:-
•Strong acids are written as H3O1+ and weak acids as the formula of the acid.
-
•Most bases and a few acids are anions, but they are usually found as salts. However, the cation is usually a spectator ion in these cases. Thus, the base in a solution of KF is the F1– ion.
-
•NH41+ is an acid, but it is normally found as a salt. Be careful with the anion because anions are also bases. If the anion is the conjugate base of a strong acid, it is a spectator ion in an acid-base reaction, otherwise, the anion may be a reactive base.
-
•Anions with acidic protons, such as HSO3–, are amphiprotic. They behave like acids in the presence of bases, but they function as bases in the presence of acids.
Exercise 12.11:
Indicate how the reacting acids and bases would be represented in the net ionic equations for the acid-base reactions that occur when solutions of the following are mixed. Refer to the Acid-Base Table resource. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
nitric acid and potassium sulfide
acid
o_H_3O^1+_s
Nitric acid is above H3O1+ on the acid-base table, so it is a strong acid. Consequently, nitric acid is found in solution as H3O1+ + NO3O31– ions. H3O1+ is the acid.
Nitric acid is HNO3, but it is a strong acid.
base
o_S^2-_s
The anion, S2– is the base, and the potassium ion is a spectator ion.
Bases are usually anions. Anions with charges greater than –1 are usually fairly strong bases.
ammonium chloride and sodium cyanide
acid
o_NH_4^1+_s
Ammonium ion is a weak acid, and the chloride ion is a spectator ion because it is the conjugate base of a strong acid.
A Brønsted acid must have a proton! Although the proton is usually written first in the formula of the acid, there is one acid where it is never written first.
base
o_CN^1-_s
The cyanide anion, CN1–, is the base, and the sodium ion is a spectator.
sodium carbonate and hydrofluoric acid
acid
o_HF_s
HF is a weak acid, so it must be written as the molecular formula.
base
o_CO_3^2-_s
Carbonate ion, CO32–, is the base, and sodium ion is a spectator.
ammonia and perchloric acid
acid
o_H_3O^1+_s
Perchloric acid is a strong acid (It is above H3O1+ in the Acid-Base Table.), so it is represented by H3O1+.
base
o_NH_3_s
Ammonia is a weak base.
12.8-6. Net Equations
Exercise 12.12:
Use the Acid-Base Table resource to write net equations for the reactions described below. Use a single arrow to indicate that a reaction is extensive and double arrows to indicate that it is not. Assume that a reaction is extensive only when the reacting acid is at least 1000 times stronger than the produced acid. That is, use a single arrow if the following is true.
-
•Ka(reacting acid) > 1000 × Ka(produced acid)
Barium hydroxide and nitric acid are mixed.
o_H_3O^1+_s
H3O1+ + OH1– → H2O + H2O
(acid 1)
+
o_OH^1-_s
H3O1+ + OH1– → H2O + H2O
(base 2)
o_H_2O_s
H3O1+ + OH1– → H2O + H2O
(base 1)
+
o_H_2O_s
H3O1+ + OH1– → H2O + H2O
(acid 2)
Sodium acetate and hydrochloric acid are mixed.
o_H_3O^1+_s
H3O1+ + C2H3O21– → H2O + HC2H3O2
(acid 1)
+
o_C_2H_3O_2^1-_s
H3O1+ + C2H3O21– → H2O + HC2H3O2
(base 2)
o_H_2O_s
H3O1+ + C2H3O21– → H2O + HC2H3O2
(base 1)
+
o_HC_2H_3O_2_s
H3O1+ + C2H3O21– → H2O + HC2H3O2
(acid 2)
Sodium hydroxide and hydrofluoric acid are mixed.
o_HF_s
HF + OH1– → F1– + H2O
(acid 1)
+
o_OH^1-_s
HF + OH1– → F1– + H2O
(base 2)
o_F^1-_s
HF + OH1– → F1– + H2O
(base 1)
+
o_H_2O_s
HF + OH1– → F1– + H2O
(acid 2)
Ammonium chloride and sodium cyanide are mixed.
o_NH_4^1+_s
NH41+ + CN1– NH3 + HCN
(acid 1)
+
o_CN^1-_s
NH41+ + CN1– NH3 + HCN
(base 2)
o_NH_3_s
NH41+ + CN1– NH3 + HCN
(base 1)
+
o_HCN_s
NH41+ + CN1– NH3 + HCN
(acid 2)
Ammonium chloride and sodium fluoride are mixed.
o_NH_4^1+_s
NH41+ + F1– NH3 + HF
(acid 1)
+
o_F^1-_s
NH41+ + F1– NH3 + HF
(base 2)
o_NH_3_s
NH41+ + F1– NH3 + HF
(base 1)
+
o_HF_s
NH41+ + F1– NH3 + HF
(acid 2)
12.9 pH and pKa
Introduction
The hydronium ion concentration is an important property of an aqueous solution, but it can be very small, so it is often given on the p-scale to avoid writing exponents.Objectives
-
•Write the expression for the ion product constant of water and give its value at 25 °C.
-
•Determine the hydronium (or hydroxide) ion concentration in aqueous solution given the hydroxide (or hydronium) ion concentration.
-
•Define pKa and determine relative acid strengths based on the acid pKa.
12.9-1. The Ion Product Constant of Water
Water is both a very weak acid and a very weak base, so it can react with itself.H2O + H2O H3O1+ + OH1−
12.9-2. pH
The hydronium ion concentration is an important characteristic of the solution, but it is normally a small number. To avoid the use of exponentials in discussions of hydronium ion concentrations, we define pH. The exponent of [H3O1+] is usually negative, so the sign of log [H3O1+] is usually negative. The negative sign in Equation 12.4 assures that the pH is usually positive. Because of the negative sign, a high pH implies a low hydronium ion concentration, and a low pH implies a high hydronium ion concentration. Equation 12.2Kw = [H3O1+][OH1−] = 1.0 × 10−14
can be rearranged as follows to show how the hydronium ion concentration, and therefore the pH, of a basic solution can be determined.
Equation 12.5 shows that solutions with high hydroxide ion concentrations have low hydronium ion concentrations, so a high pH also implies a high hydroxide ion concentration and a low pH implies a low hydroxide ion concentration. A neutral solution is one in which [H3O1+] = [OH1−] = 1.0 × 10−7 M,
so the pH of a neutral solution is determined to be pH = −log(1.0 × 10−7) = 7.0.
The hydronium ion concentration is greater in an acidic solution, so the pH of an acidic solution is less than 7.0. The hydronium ion concentration is less in a basic solution, so the pH of a basic solution is greater than 7.0. These conclusions are summarized in the following table.
Solution pH | Solution Type |
---|---|
above 7 | basic |
equal to 7 | neutral |
below 7 | acidic |
Table 12.8: Solution Type Versus pH
12.9-3. Hydronium Ion Concentration Exercise
Exercise 12.13:
[H3O1+][PH1+] = 1.0 × 10–14
[H3O1+] =
=
= 4.0 × 10−11 M
The hydroxide ion concentration is greater than the hydronium ion concentration, so the solution is said to be a basic solution. M
[H3O1+][PH1+] = 1.0 × 10–14
[H3O1+] =
=
= 1.6 × 10−3 M
The hydronium ion concentration is greater than the hydroxide ion concentration, so the solution is said to be an acidic solution. M
What is the hydronium ion concentration in the following solutions? Use e-format for exponentials:
1 × 10–4 = 1e–04.
pure water
1.0e-7___
H2O is the sole source of both H3O1+ and OH1– in pure water, and the two ions are produced in equal amounts by the reaction of water with itself. Consequently, the concentrations of the two ions must be equal, so the equilibrium constant expression for water can be written as the following.
[H3O1+][OH1–] = [H3O1+][H3O1+] = [H3O1+]2 = 1.0 × 10–14
[H3O1+] =
= 1.0 × 10−7 M = [OH1–]
The hydronium ion and hydroxide ion concentrations in pure water are each 1.0 × 10–7 M. A solution in which the two ion concentrations are equal is said to be a neutral solution. M
[H3O1+][OH1–] = [H3O1+][H3O1+] = [H3O1+]2 = 1.0 × 10–14
[H3O1+] =
1.0 × 10−14 |
The hydronium ion and hydroxide ion concentrations in pure water are each 1.0 × 10–7 M. A solution in which the two ion concentrations are equal is said to be a neutral solution. M
[OH1−] = 2.5e−04 M
4.0e-11___
We are given [OH1–]and asked for [H3O1+], so we solve Equation 12.2 as follows.[H3O1+][PH1+] = 1.0 × 10–14
[H3O1+] =
1.0 × 10−14 |
[OH1−] |
1.0 × 10−14 |
2.5 × 10−4 |
The hydroxide ion concentration is greater than the hydronium ion concentration, so the solution is said to be a basic solution. M
[OH1−] = 6.2e−12 M
1.6e-03___
Solve Equation 12.2 for the following.[H3O1+][PH1+] = 1.0 × 10–14
[H3O1+] =
1.0 × 10−14 |
[OH1−] |
1.0 × 10−14 |
6.2 × 10−12 |
The hydronium ion concentration is greater than the hydroxide ion concentration, so the solution is said to be an acidic solution. M
12.9-4. pH Exercises
Exercise 12.14:
What is the pH if [H3O1+] = 1.3 × 10–5 M?
4.89___
pH = –log[H3O1+]= –log(1.3 × 10–5) = –(–4.89) = +4.89
What is the pH of 0.10 M HCl?
1.0___
HCl is a strong acid, so [H3O1+] = 0.10 M.
pH = –log(0.10) = –(–1.0) = 1.0
pH = –log(0.10) = –(–1.0) = 1.0
-
Pick the stronger acid given the pHs of their 0.1 M solutions.
-
The stronger acid is the one for which the above reaction is most extensive, i.e., the one that produces the greater amount of H3O1+. The solution with the greater [H3O1+] is the one with the lower pH, so HClO is a stronger acid than HBrO. This would be predicted because Cl is more electronegative than Br. -
What is the pH of a 0.022 M Ba(OH)2 solution? Hint: the hydroxide ion concentration is not
0.022 M.
12.64___
Ba(OH)2 → Ba + 2 OH1–
[OH1–] = 2 × Ba(OH)2 concentration = 2(0.022 M) = 0.044 M
[H3O1+] =
=
= 2.3 × 10−13
pH = –log [H3O1+] = –log(2.3 × 10–13) = 12.64
[OH1–] = 2 × Ba(OH)2 concentration = 2(0.022 M) = 0.044 M
[H3O1+] =
Kw |
[OH1−] |
1.0 × 10−14 |
0.044 |
pH = –log [H3O1+] = –log(2.3 × 10–13) = 12.64
12.9-5. pKa
A high pKa implies a weak acid.
Acid | Ka | pKa |
---|---|---|
HF | 7.2 × 10–4 | 3.14 |
HOCl | 3.5 × 10–8 | 7.46 |
HCN | 4.0 × 10–10 | 9.40 |
Table 12.9
Note that the pKa increases as the acid strength decreases.
12.9-6. pKa Exercise
Exercise 12.15:
A 0.1 M solution of which of the following acids has the higher pH?
12.9-7. Selecting the Solution with the Lower pH Exercise
Exercise 12.16:
Indicate the solution in each pair that has the lower pH.