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Chapter 12 – Acid-Base Chemistry

Introduction

The terms acid and base have been used for several hundred years. Acids were substances that had a sour taste, were corrosive, and reacted with substances called bases. Substances that had a bitter taste, made skin slippery on contact, and reacted with acids were called bases. However, these simple definitions had to be refined as the chemical properties of acids and bases became better understood. The first chemical definition of acids and bases was made by Svante Arrhenius. An Arrhenius acid is a substance that produces H1+ ions when it is dissolved in water, and an Arrhenius base is a substance that produces OH1– ions when dissolved in water. In this theory, an acid ionizes in water much as an ionic substance, and the equilibrium constant for the reaction is called the acid ionization constant. For example, the ionization of the Arrhenius acid HCl in water is represented as follows:
HCl H1+ + Cl1−
Neutralization is the reaction of an acid and a base to produce water and a salt.
HCl + NaOH H2O + NaCl
NaCl is a salt. Note that the cation of a salt is derived from the base and the anion from the acid. Arrhenius acid-base theory is very limited because its definitions are restricted to behavior in water. Consequently, broader definitions for these very important classes of compounds were developed. In this chapter, we examine the Lewis and the Brønsted-Lowry theories of acid-base chemistry. The Lewis theory is the broadest and is discussed first.

12.1 Lewis Acids and Bases

Introduction

The broadest definition of acids and bases is that of Lewis. By this definition, a large number of reactions can be classified as acid-base reactions. In this section, we introduce Lewis acids and bases and the use of curved arrows to show the mechanism of a Lewis acid-base reaction. These topics will be used again in Chapter 13, Organic Chemistry.

Prerequisites

Objectives

12.1-1. Definitions

A Lewis acid-base reaction converts a lone pair on a base and an empty orbital on an acid into a covalent bond.
The product of a Lewis acid-base reaction is a covalent bond between the acid and the base. Both bonding electrons come from the base, so it is a coordinate covalent bond. A curved arrow from the lone pair to the atom with the empty orbital is used to show that the lone pair will become the bonding pair between the two atoms.
Figure 12.1

12.1-2. Lewis Acids and Bases

Lewis Bases

The strength of the base depends upon the electron density in the region of the lone pair, the greater the electron density the stronger the base. Consequently, the strength of a base depends upon the groups around the lone pair. For example, consider the relative base strengths of the following, which are basic due to the lone pairs on the oxygen atom.
CH3O1− > HO1− > ClO1−
CH3O1– is the strongest base because the CH3 group pushes electron density onto the oxygen atom. ClO1– is the weakest because the electronegative chlorine atom removes electron density from the oxygen.
lewis bases
Figure 12.2: Examples of Lewis Bases
The top row of Figure 12.2 shows some Lewis bases that are molecules. In each case the lone pair resides on a nitrogen or oxygen atom, a common occurrence in Lewis bases that are molecules. Anions are also Lewis basic. The chloride anion is a very weak Lewis base, while the hydrogen sulfide ion (HS1–) and the acetate ion (C2H3O21–) are common weak Lewis bases.

Lewis Acids

Lewis acids are often more difficult to identify. The following should help.
lewis acids
Figure 12.3: Examples of Lewis Acids
The Lewis acidic sites in Figure 12.3, each of which contains less than four electron regions, are shown in red. AlCl3 is electron deficient because aluminum has only six valence electrons. Molecules with electron deficient atoms are strong Lewis acids. SO3 and CO2 are not electron deficient, but the central atom in each has less than four electron regions (three around S and two around C), so they are Lewis acids. Their acidity is strengthened by positive formal charge. Cations such as Ag1+ and H1+ that have fairly low-energy empty orbitals are also good Lewis acids.

12.1-3. Lewis Acidity and Basicity and Orbital Energy

The bond between two atoms is covalent only when the interacting orbitals have similar energies because large energy separations favor ionic bonds. Thus, the formation of a coordinate covalent bond in a Lewis acid-base reaction is facilitated when the energy of the empty orbital of the Lewis acid is close to that of the lone pair of the Lewis base. The energies of lone pairs are typically lower than those of empty orbitals, so the strongest interactions occur when the energy of the lone pair is high for a lone pair and the energy of the empty orbital is low for an empty orbital. For example, consider the cases of Na1+ and Ag1+ as shown in the figure. The energy of the empty orbital of Ag1+ is much lower than that of Na1+; i.e., the energy of the empty orbital of Ag1+ is low for an empty orbital. Thus, the empty orbital on Ag1+ is sufficiently close to that of the lone pair on the Br1– ion that the Ag–Br bond is covalent. However, the energy of the empty orbital on Na1+ is so high that the Na–Br bond is ionic. Thus, Ag1+ is a sufficiently strong Lewis acid to react with Br1– ion, but the acidity of Na1+ is so weak that it does not. Indeed, Na1+ is such a weak Lewis acid (its orbitals are so high in energy) that it does not function as an acid in aqueous solutions. In general, H1+ and cations of metals with high effective nuclear charge (metals such as Ag and Pb that lie low and to the right of the periodic table) have empty orbitals that are relatively low in energy, so they are Lewis acidic, but the cations of metals on the left side of the periodic table are such weak Lewis acids that their acidity can be ignored in most cases. We conclude the following.
Strong Lewis acids have low-energy empty orbitals, and strong Lewis bases have high-energy lone pairs.
Figure 12.4: Lewis Acidity and Orbital Energy
The empty orbital on Ag is relatively low in energy, so it forms a covalent bond with the lone pair on Br1– ion. The empty orbital on Na1+ is very high in energy, so its bonds to anions are ionic. Therefore, Ag1+ is a much stronger Lewis acid than Na1+, which is so weak that its acidity can usually be ignored.

12.1-4. Oxidants and Acids

Oxidizing agents and Lewis acids are both characterized by empty valence orbitals that are low in energy, while reducing agents and Lewis bases both have high-energy electrons. Consequently, many Lewis acids are also oxidants and many Lewis bases are also reductants. Indeed, oxidants and Lewis acids are often defined as electron acceptors, and reductants and Lewis bases as electron donors. The obvious question becomes, "What determines whether electrons are transferred or shared when a lone pair comes into contact with an empty orbital?" As has been the case so often in our study of chemistry, the answer lies in their relative energies: electrons do whatever is most efficient at increasing their electrical potential in order to lower their energy. If the energy of the empty orbital is lower than that of the lone pair, the electrons simply transfer from the reductant to the more positive electrical potential on the oxidant in a redox reaction. However, if the empty orbital is at higher energy, the electrons lower their energy by forming a covalent bond between an acid and a base, which increases their electrical potential by exposing them to part of the nuclear charge on the acid. The example of H1+, which is both an oxidant and an acid, is considered in Figure 12.5. If H1+ encounters a zinc atom, it behaves as an oxidant and accepts the higher energy electrons from the reductant zinc. However, electrons will not flow from a Br1– ion to the higher energy orbital on H1+, so the lone pair on Br1– ion lowers its energy by forming an H–Br covalent bond. Br1– is a base in the presence of H1+, but it is a reductant in the presence of something like Cl2 that has an empty orbital at lower energy (2 Br1– + Cl2 Br2 + 2 Cl1–).
Figure 12.5: Protons as Oxidants and Reductants
(a) H1+ is an oxidizing agent in the presence of Zn because the electrons on Zn are higher in energy; i.e., the electrons transfer to lower orbitals; (b) H1+ is an acid in the presence of Br1– because the lone pair on Br1– is lower in energy; i.e., the electrons are shared with higher orbitals.

12.1-5. Curved Arrows in Lewis Acid-Base Reactions

Curved arrows pointing from a lone pair to an atom indicate that the lone pair is converted into a bonding pair, while curved arrows pointing from a bond to an atom are used to show that a bonding pair is converted into a lone pair on the atom.
Curved arrows always start on an electron pair and end on an atom, but their meaning depends upon whether the electron pair is a lone pair or a bonding pair.
Start of a
Curved Arrow
End of a
Curved Arrow
Reactant Product Effect
lone pair on atom B atom A The lone pair becomes an A–B bond.
A–B bonding pair atom A The A–B bond becomes a lone pair on atom A.
Table 12.1
Curved arrows will be used extensively in this chapter and the next chapter to explain the mechanisms of Lewis acid-base reactions.

12.1-6. Examples of Metals as Lewis Acids

Ag1+ ions have relatively low-energy empty orbitals, so they are good Lewis acids. Cl1– ions have lone pairs, so they are Lewis bases. In Figure 12.6a, a curved arrow from Cl1– to Ag1+ is used to show the conversion of a lone pair on the Cl1– ion into the AgCl bond in this Lewis acid-base reaction.
Figure 12.6a: Metal Ions as Lewis Acids: Precipitation of AgCl
Silver ions also react with ammonia. Note that the red lone pair on the nitrogen in each ammonia is converted into a red Ag–N bond in Figure 12.6b.
Figure 12.6b: Metal Ions as Lewis Acids: Formation of Ag(NH3)21+
In Figure 12.6c, the aluminum atom of AlCl3 has only six valence electrons and three electron regions surrounding it, so AlCl3 is a strong Lewis acid. Note that during this reaction, Al goes from three electron regions and sp2 hybridization to four electron regions and sp3 hybridization.
Figure 12.6c: Metal Ions as Lewis Acids: Formation of AlCl41–
The hybridization change from sp2 to sp3 results in a geometry change from trigonal planar to tetrahedral. The following animation shows the geometry change.

We conclude the following.
The number of electron groups around the Lewis acidic atom changes with the formation of a bond, which changes the geometry and hybridization of the atom.

12.1-7. Curved Arrows in a Mechanism–an Example

SO3 + H2O

The Lewis acid-base reaction between SO3 and H2O to form H2SO4 is the reaction that is the primary cause of acid rain. The oxygen atom of the water molecule contains two lone pairs, so water is a Lewis base, while the sulfur atom in SO3 has only three electron regions, which makes SO3 Lewis acidic. As shown in Figure 12.7a, a lone pair on the oxygen atom in water is shared with the sulfur atom to form a new S–O bond. Simultaneously, the the pi electrons in the S=O bond are converted into a lone pair on the oxygen (curved arrow from the bond to the atom), and the hybridization of the sulfur atom goes from sp2 to sp3 (from trigonal planar to tetrahedral).
Figure 12.7a: SO3 + H2O Mechanism: Step 1
A lone pair on water is converted to an S–O bond and the π electrons of the S=O bond are converted into a lone pair. Lone pairs on other oxygen atoms have been omitted for clarity.
The resulting structure places positive formal charge on the oxygen atom, which is eliminated by transferring a proton from that oxygen atom to one that carries negative formal charge. The proton transfer is accomplished with two acid-base reactions with the solvent. In the first, a proton is transferred from the oxygen atom with positive formal charge to a solvent molecule (water) as shown in Figure 12.7b.
Figure 12.7b: SO3 + H2O Mechanism: Step 2
A proton is transferred from the oxygen with positive formal charge to a water molecule.
In the final step, a proton is transferred from the solvent to an oxygen atom with negative formal charge as shown in Figure 12.7c. The H3O1+ produced in step 2 and the OH1– produced in this step would then undergo proton transfer reactions to produce 2 H2O. The final product has the correct structure of sulfuric acid.
Figure 12.7c: SO3 + H2O Mechanism: Step 3
A proton is transferred from a solvent molecule to an oxygen atom with negative formal charge.

12.1-8. Comparing Redox and Lewis Acid-Base Reactions

H1+ as an oxidant when electrons are higher in energy

H1+ as an acid when electrons are lower in energy

An electron pair behaves like a reducing agent when an empty orbital is much lower in energy, but like a Lewis base when the empty orbital is higher in energy.
Compare the definitions of the reactants involved in Lewis acid-base and redox reactions. The only difference between the two reaction types is that one transfers, while the other shares electrons between the two reactants.
Figure 12.8: H1+ as oxidant
Figure 12.9: H1+ as an acid

12.2 Brønsted Acids

Introduction

Although the Lewis definition is the broadest, the Brønsted-Lowry (or simply Brønsted) definition is the most frequently used acid-base definition in aqueous solutions. In this section, we define Brønsted acids and bases and introduce Brønsted acid-base reactions.

Prerequisites

Objectives

12.2-1. Brønsted Definition

Brønsted acid-base reactions are proton transfer reactions.
A Brønsted acid is a proton donor, a Brønsted base is a proton acceptor, and a Brønsted acid-base reaction is a proton transfer from the acid to the base. Thus, the electron pair is the point of reference in Lewis theory, while the proton is the point of reference in Brønsted theory. The Brønsted definition is a special case of the Lewis definition. In each, a base contains a lone pair that it shares with the acid to form a covalent bond. Any Brønsted base is a Lewis base and vice versa. However, a Lewis acid is any species that can accept a lone pair, but the lone pair acceptor must be a proton in the Brønsted definition, and the substance that contains the proton is a Brønsted acid.

12.2-2. Aqueous Solutions of Acids and Base

[H3O1+] dictates the acidity and [OH1–] dictates the basicity of an aqueous solution.
In the Brønsted definition, acids transfer a proton to water, which is a weak Brønsted base, to produce hydronium ions (H3O1+).
HX + H2O equilibrium arrow H3O1+ + X1−
It is the concentration of H3O1+ that dictates how acidic an aqueous solution is. Thus, if the above reaction with water is extensive, the concentration of H3O1+ is relatively high as essentially all of the HX is converted to H3O1+. Such acids are strong acids. If its reaction with water is not extensive,the concentration of H3O1+ is relatively low as only a small portion of the acid is converted into H3O1+, and such acids are called weak acids. Similar considerations can be made for bases. It is the hydroxide ion concentration that determines the basicity of an aqueous solution. Thus, a strong base, such as KOH, is one that is converted extensively into hydroxide ions in water: KOH K1+ + OH1–. A weak base, such as fluoride ion, reacts only slightly with water to produce hydroxide ions:
F1− + H2O equilibrium arrow HF + OH1−.

12.2-3. Acids and Bases are Electrolytes

Strong acids and bases are strong electrolytes, while weak acids and bases are weak electrolytes.
If HX is a strong acid, then it is converted completely into H3O1+ and X1– ions in water. The presence of these ions makes the acid a strong electrolyte. However, if HX does not react completely with water, then only small concentrations of the ions are produced. In this case, HX is a weak electrolyte. Similarly, strong bases are strong electrolytes and weak bases are weak electrolytes. Recall from Section 10.5 that electricity is conducted through a solution of an electrolyte but not through a solution of a nonelectrolyte. Indeed, the brightness of the light is indicative of the ion concentration in solution. Consider the following possibilities for an acid or base.
The light bulb does not glow, so there are no ions in solution. The fact that HX produces no ions in solution indicates that HX is a nonelectrolyte. An aqueous solution is represented as HX to show that the molecules do not ionize in water.
The light shines brightly, which means that the concentration of H3O1+ ions in solution is relatively high. Acids that ionize completely in water to produce high concentrations of H3O1+ ions are called strong acids. An aqueous solution is represented as H3O1+ + X1– to show that the molecules ionize completely in water.
The light shines, so HX is an electrolyte, but the intensity of the light is much less than for a strong acid. The dimness of the light indicates that the H3O1+ ion concentration is low. Thus, only a fraction of the HX molecules in water ionize. Acids that ionize only partially in water are called weak acids. An aqueous solution is represented as HX because HX is the predominant species in solution.
Table 12.2: Determining the Relative Concentrations of H3O1+ Ions in a 0.1 M of HX

12.2-4. Examples

pure H2O Water is a nonelectrolyte and represented as H2O. There are ions in water, but their concentrations are very small.
0.10 M HNO3 Nitric acid is a strong acid, and its aqueous solution is represented as H3O1+(H1+) + NO31–. The following reaction is so extensive that there are essentially no nitric acid molecules in solution. Recall that extensive reactions are expressed with single arrows as in the following.

HNO3 + H2O H3O1+ + NO31–
0.10 M KOH KOH ionizes completely in water and is a strong electrolyte. It is a strong base because one of the ions that it produces is the OH1– ion. Thus, aqueous KOH is written as K1+ + OH1–.
0.10 M CH3OH CH3OH is a nonelectrolyte. It is neither an acid nor a base—it is an alcohol (wood alcohol). An aqueous solution of methanol is written as CH3OH.
0.10 M HNO2 The light bulb glows dimly, so nitrous acid is a weak acid and its aqueous solutions are represented as HNO2, not as hydronium ion and nitrite ion, to show the predominant form. The following reaction is not extensive (only about 5% of the HNO2 molecules react), so double arrows are used.

HNO2 + H2O equilibrium arrow H3O1+ + NO21–
0.10 M NH3 The light bulb glows dimly, so NH3 is a weak electrolyte. About 1% of the ammonia molecules react with water to produce ions, so an aqueous solution is represented as NH3 molecules, not as the ions. Double arrows are used in the reaction.

NH3 + H2O equilibrium arrow NH41+ + OH1–

The proton is transferred from water to ammonia, so NH3 is a weak base.
Table 12.3

12.2-5. Brønsted Acids

An acidic proton must be bound to an electronegative atom, which is oxygen in most acids that contain an oxygen atom.
In order for HX to be acidic, the H–X bond must break to produce H1+ and X1– ions, but that can happen only if it is a polar bond. Thus, a hydrogen atom must be covalently bound to a highly electronegative atom to be acidic. There are a great number of compounds with hydrogen atoms covalently bound to atoms that are not very electronegative, but these compounds are not Brønsted acids. The most common examples are organic compounds because the C–H bond is not polar (C and H have very similar electronegativities). For example, the C–H bonds in CH4 do not produce H1+ when they break, so CH4 cannot be a Brønsted acid. The H–Cl bond is very polar, so breaking the H–Cl bond does produce H1+ ions, which makes HCl a Brønsted acid.
Acidic protons are usually written first in the formula of acids to indicate that they are acidic.
For example, the chemical formulas of the hydrogen sulfate ion and perchloric acid are written as HSO41– and HClO4 to demonstrate that they are acids, while the formulas of methane and ammonia are written CH4 and NH3 to indicate that they have no acidic protons. However, writing the formulas this way can be misleading because it often places the proton next to an atom to which it is not bound. The acidic protons in HSO41– and HClO4 are both attached to oxygen atoms. Acetic acid is written HC2H3O2 to indicate that it is an acid that has only one acidic proton. Once again, the acidic proton is also bound to an oxygen atom, not the carbon, while the other hydrogen atoms are attached to the carbon and are not acidic. Consequently, acetic acid is often written as CH3COOH, which indicates an O–H bond and better represents the true structure of the acid. Similarly, H2SO4 contains two O–H bonds but no S–H bonds.
Figure 12.10: Only Protons Bound to Highly Electronegative Atoms are Acidic
Acetic acid contains three hydrogen atoms bound to carbon that are not acidic because carbon is not highly electronegative and the C–H bond is not polar. It also contains one hydrogen atom attached to highly electronegative oxygen that is acidic because the O–H bond is very polar.

12.2-6. Binary Acids and Oxoacids

Binary Acids

Binary acids have a proton and only one other element. HCl, HBr, and HI are strong acids, but HF is a weak acid. Note: these acids plus NH41+, H2S, and H–CN are the only acids that we deal with that do not have O–H bonds.
Figure 12.11: Some Binary Acids

Oxoacids

Most acidic protons are bound to an oxygen atom. Such acids are called oxoacids. The acidic protons are shown in blue in Figure 12.12.
Figure 12.12: Some Common Oxoacids

Naming Acids

12.2-7. Binary Acids

The pure compounds that produce binary acids are named using the rules outlined in Section 4.6 until they are dissolved in water. For example, HCl is hydrogen chloride and H2S is hydrogen sulfide. However, when these substances are dissolved in water, they produce acidic solutions that are named in the following manner.
Formula Name as Pure Substance Formula Name as Aqueous Solution
HF(g) hydrogen fluoride HF(aq) hydrofluoric acid
HCl(g) hydrogen chloride HCl(aq) hydrochloric acid
HI(g) hydrogen iodide Hl(aq) hydroiodic acid
HCN(g) hydrogen cyanide HCN(aq) hydrocyanic acid
H2S(g) hydrogen sulfide H2S(aq) hydrosulfuric acid
Table 12.4: Names of Some Common Binary Acids

12.2-8. Polyatomic Acids

Polyatomic acids are derived from polyatomic ions and are named by If the acid is also an ion, its name is unchanged. For example, the HPO42– and H2PO41– ions are the monohydrogen phosphate ion and dihydrogen phosphate ion, respectively. In an older, but still common, method, ions with acidic protons are named by using the prefix 'bi' instead of the word 'hydrogen.' Thus, HSO41– is either hydrogen sulfate or bisulfate.
Ion Formula Ion Name Acid Formula Acid Name
C2H3O21– acetate ion HC2H3O2 acetic acid
SO32– sulfite ion H2SO3 sulfurous acid
SO42– sulfate ion H2SO4 sulfuric acid
NO21– nitrite ion HNO2 nitrous acid
NO31– nitrate ion HNO3 nitric acid
ClO1– hypochlorite ion HClO hypochlorous acid
ClO21– chlorite ion HClO2 chlorous acid
ClO31– chlorate ion HClO3 chloric acid
ClO41– perchlorate ion HClO4 perchloric acid
PO43– phosphate ion H3PO4 phosphoric acid
Table 12.5: Acids Derived from Polyatomic Anions

12.2-9. Acid Naming Exercise

Exercise 12.1:

Name the following acids.
H2CO3 o_carbonic acid_s The CO32– ion is the carbonate ion, so the acid is carbonic acid.
HCO31– o_hydrogen carbonate ion_s Acids that are ions are named as the ion, so HCO31– is the hydrogen carbonate ion. Note that "bicarbonate ion" is also used.
Write formulas for the following acids. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
selenous acid o_H_2SeO_3_s The -ous ending tells us that the acid is derived from a polyatomic ion with an -ite ending; i.e., the acid is derived from the selenite ion. Selenium is a Group 6A nonmetal, so its chemical properties are expected to be similar to those of sulfur. The sulfite ion is SO32–, so selenite is SeO32– and selenous acid is H2SeO3. It contains two O-H bonds.
hydroselenic acid o_H_2Se_s The name starts with hydro, so this is a binary acid of H and Se. Se is in Group 6A, so it is expected to form a –2 anion, which requires two protons. Hydroselenic acid is H2Se.

12.3 Brønsted Acid-Base Reactions

Introduction

Brønsted acid-base reactions all involve transferring a single proton from the acid to the base. In this section, we see how to predict the products of a Brønsted acid-base reaction.

Objectives

12.3-1. Conjugate Base

The conjugate base of an acid is formed by removing one, and only one, proton from the acid.
After the acid loses a proton, it becomes a base because the species it becomes can gain the proton back. The loss of a single proton converts an acid into its conjugate base. It is important to realize that an acid and its conjugate base differ by one, and only one proton. All Brønsted reactions involve the transfer of a single proton. Thus, the acid is always converted to it conjugate base in a Brønsted reaction. The charge on the conjugate base is always lower than that on the acid by one because the acid loses H1+.
Exercise 12.2:

Use the above definition to determine the conjugate base of each of the following.(Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
NH3 o_NH_2^1-_s The conjugate base is formed by removing a single H1+.
NH3 NH21– + H1+
NH21– is the conjugate base of NH3.
H2O o_OH^1-_s The conjugate base is formed by removing a single H1+.
H2O OH1– + H1+
OH1– is the conjugate base of H2O.
HSO31– o_SO_3^2-_s The conjugate base is formed by removing a single H1+.
HSO31– SO32– + H1+
SO32– is the conjugate base of HSO31–.
HC2H3O2 o_C_2H_3O_2^1-_s The conjugate base is formed by removing a single H1+.
HC2H3O2 C2H3O21– + H1+
C2H3O21– is the conjugate base of HC2H3O2.

12.3-2. Conjugate Acid

The conjugate acid of a base is formed by adding one proton to the base.
After the base gains a proton, it becomes an acid because the species it becomes can donate the proton back. The gain of a single proton converts a base into its conjugate acid. All Brønsted reactions involve the transfer of a single proton. Thus, the base is always converted into its conjugate acid in a Brønsted reaction. The charge on the conjugate acid is always greater than that on the base by one because the base gains H1+. A base and an acid that differ by one, and only one proton, are said to be a conjugate acid-base pair.
Exercise 12.3:

Determine the conjugate acid of each of the following.(Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
NH3 o_NH_4^1+_s The conjugate acid is formed by gaining a single H1+.
NH3 + H1+ NH41+
NH41+ is the conjugate acid of NH3.
H2O o_H_3O^1+_s The conjugate acid is formed by gaining a single H1+.
H2O + H1+ H3O1+
H3O1+ is the conjugate acid of H2O.
HSO31– o_H_2SO_3_s The conjugate acid is formed by gaining a single H1+.
HSO31– + H1+ H2SO3
H2SO3 is the conjugate acid of HSO31–.
CO32– o_HCO_3^1-_s The conjugate acid is formed by gaining a single H1+.
CO32– + H1+ HCO31–
HCO31– is the conjugate acid of CO32–.

12.3-3. Brønsted Acid-Base Reactions

The chemical equation for a Brønsted acid-base reaction consists of two conjugate acid-base pairs and nothing else.
Brønsted acid-base reactions convert the reacting acid into its conjugate base and the reacting base into its conjugate acid. The chemical equation for a Brønsted acid-base reaction consists of two conjugate acid-base pairs and nothing else. Consider the following proton transfer reaction: HCN + NH3 CN1– + NH41+. The proton transfer converts the reacting acid (HCN) into its conjugate base (CN1–) and the reacting base (NH3) into its conjugate acid (NH41+). The products of an acid-base reaction are also an acid and a base, so the substances on the right of the chemical equation also react to produce those on the left: CN1– + NH41+ HCN + NH3. In this particular reaction, the probability that a collision between the acid and the base results in an acid-base reaction is about the same in either direction. The fact that the back reaction is important is demonstrated with the use of double arrows in the chemical equation: HCN + NH3 equilibrium arrow CN1– + NH41+.

12.4 Extent of Proton Transfer

Introduction

Not all acids and bases react very well with one another, and the degree to which they do react is referred to as the extent of proton transfer. If the extent of proton transfer is great, the reaction is usually written with a single arrow, but if the transfer is not extensive, the reaction is written with double arrows.

Prerequisites

Objectives

12.4-1. Comparing Conjugate Acid-Base Strengths

The weaker an acid is, the stronger is its conjugate base.
The strength of an acid is related to the ease with which it donates its proton to become its conjugate base, and the strength of a base is related to its ability to accept a proton to become its conjugate acid. If A1– is a strong base, then it must bind a proton strongly when it forms HA, and if its proton is bound strongly, then HA must be a weak acid. We conclude that the strength of a base varies inversely with the strength of its conjugate acid, i.e., strong acids have weak conjugate bases and vice versa. Consider the following acid-base reaction.
HA + B1− equilibrium arrow A1− + HB
If HA is the stronger of the two acids, then A1– must be the weaker of the two bases due to the inverse relationship between conjugate acid-base strengths. This means that the stronger acid is always on the same side of the chemical equation as the stronger base. Similarly, the weaker acid and base are also on the same side of the equation. Consequently, there are only three possible combinations in Brønsted acid-base reactions:

12.4-2. Extent as a Function of Relative Acid Strengths

If the reacting acid is the stronger acid, then the reacting base is the stronger base, and the reaction is extensive.
If the acid strengths are comparable then the concentrations of substances on both sides of the equilibrium are comparable.
If the reacting acid is much weaker than the produced acid then little product is formed.

12.4-3. Relative Acid Strength Exercise

Exercise 12.4:

Solutions containing equal concentrations of HA, A1–, HB, and B1– are mixed. After reaction, the resulting solution is composed almost exclusively of HA and B1– determine relative acid and base strengths.
    Which is the stronger acid?
  • HA No, the stronger acid loses it proton to become its conjugate base. The solution has H-A but not A1–, so HA is not a strong acid.
  • A1– No, A1– is not an acid.
  • HB Correct, HB reacts to produce a solution of its conjugate base, B1–, so it gave up its proton readily, which makes it the stronger acid.
  • B1– No, B1- is not an acid.
    Which is the weaker base?
  • HA No, HA is not a base.
  • A1– No, A1– has reacted with HB to produce HA, so it is not the weaker base.
  • HB No, HB is not a base.
  • B1– Correct. B1– does not react with HA, to produce HB, so it is the weaker base. Note that the concentration of the weaker base is higher than that of its conjugate acid because the weaker base does not react while the conjugate acid does.
    Which is the stronger base?
  • HA No, HA is not a base.
  • A1– Correct, A1– has reacted with HB to produce HA, so it is the stronger base. Note that the concentration of a stronger base is much less than that of its conjugate acid, because a strong base reacts to produce its conjugate acid, but the conjugate acid does not react to produce its conjugate base.
  • HB No, HB is not a base.
  • B1– No, B1– does not react with HA, to produce HB, so it is the weaker base. Note that the concentration of the weaker base is higher than that of its conjugate acid because the weaker base does not react while the conjugate acid does.
    Which is the weaker acid?
  • HA Correct, HA does not react, so it is the weaker acid.
  • A1– No, A1– is not an acid.
  • HB HB reacts, so it is the stronger acid.
  • B1– No, B1– is not an acid.

12.4-4. Equilibrium Constant Expression

The equilibrium mixture is always dominated by the weaker acid and base.
We now examine the equilibrium mixture that results from mixing equal amounts of HA and B1– as a function of the relative acid strengths of HA and HB.
Chemical Equation: HA + B1− equilibrium arrow A1− + HB
Equilibrium Constant Expression: K =
[A1−][HB]
[HA][B1−]

HA >> HB; K >> 1

Stronger Acid   Stronger Base   Weaker Base   Weaker Acid
HA  +  B1–    A1–  +  HB

At equilibrium, [A1–][HB] >> [HA][B1–], so K >> 1, consistent with an extensive reaction. Note: A1– is the weaker base and HB is the weaker acid!

HA ~ HB; K ~ 1

Acid   Base   Base   Acid
HA  +  B1–  equilibrium arrow  A1–  +  HB

[A1–][HB] ~ [HA][B1–] at equilibrium, so K ~ 1 when the reacting and produced acids are of similar strengths.

HA << HB; K << 1

Weaker Acid   Weaker Base   Stronger Base   Stronger Acid
HA  +  B1–  equilibrium arrow  A1–  +  HB

At equilibrium, [HA][B1–] >> [A1–][HB], so K << 1, consistent with a reaction that in not extensive. Note that HA is the weaker acid and B1– is the weaker base. In each case where the acid strengths are much different, the product of the equilibrium concentrations of the weaker acid and base are always much greater than the product of the concentrations of the stronger acid and base. That is, the equilibrium mixture is dominated by the weaker acid and base.

12.4-5. Single vs. Double Arrows

Single arrows are sometimes used to indicate that a reaction is extensive. We arbitrarily assume that K > 1000 for such reactions.
When K >> 1, the amount of product formed can be determined without use of the equilibrium constant because the equilibrium concentration of at least one of the reactants will be negligible. Reactions of this type are frequently written with single arrows () rather than the double equilibrium arrows to emphasize that the reverse reaction occurs only to a negligible extent. Although the value of K at which the reverse reaction can be ignored varies with the concentrations of the reactants, we will use a value of ~1000 in our discussions. Thus, a single arrow can be used for reactions in which
K > ~1000.
If
K < 1000,
the reverse reaction cannot be ignored, and the value of K must be used when determining the amount of product that is formed. Equations for reactions of this type should be written with double arrows (equilibrium arrow) to emphasize the importance of the reverse reaction. An example of each case is provided in the following table.
HF + ClO1− F1− + HOCl
K =
[F1−][HOCl]
[HF][OCl1−]
= 2 × 104
K >> 1 so,
  • The reaction (or proton transfer) is extensive.
  • The reacting acid (HF) is a much stronger acid than the produced acid (HClO).
  • The equilibrium concentrations of F1– and HClO are much greater than those of HF + OCl1–.
  • The reaction is frequently written with a single arrow.
HF + NO21− equilibrium arrow F1− + HNO2
K =
[F1−][HNO2]
[HF][NO21−]
= 2
K ~ 1 so,
  • The reaction is not extensive in either direction.
  • The strengths of the reacting and produced acids are comparable.
  • The equilibrium concentrations of reactants and products are similar.
  • The reaction is written with double arrows.
HCN + F1− equilibrium arrow CN1− + HF
K =
[CN1−][HF]
[HCN][F1−]
= 6 × 10−7
K << 1 so,
  • The forward reaction is not extensive, but the reverse reaction is.
  • The reacting acid (HCN) is much weaker than the produced acid (HF).
  • The equilibrium concentrations of HF and F1– are much greater than those of CN1– and HF.
  • The reaction is written with double arrows.
Table 12.6

12.4-6. Proton Transfer Exercise

Exercise 12.5:

Consider the following acid-base equilibrium. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
HOCl + CN1– equilibrium arrow OCl1– + HCN    K ~ 100
stronger acid o_HOCl_s K > 1, so the reacting acid (HOCl) is stronger than the produced acid.
stronger base o_CN^1-_s K > 1, so the reacting base is stronger than the produced base. The reacting base is CN1–.
weaker base o_OCl^1-_s The conjugate base of the stronger acid is the weaker base, so OCl1– is the weaker base.
weaker acid o_HCN_s The conjugate acid of the stronger base is the weaker base, so HCN is the weaker acid.

Acid-Base Reactions Involving Water

12.4-7. The Role of Water

All of the remaining acid-base reactions in this chapter occur in water, which can act as both as an acid and a base. Thus, the reaction with water is an important consideration in acid-base chemistry. The general reaction of an acid and water can be represented as the following.
HA + H2O equilibrium arrow A1− + H3O1+

12.4-8. Strong Acids in Water

Strong acids are represented as H3O1+ in acid-base reactions in water.
The strong acids are those that are stronger than H3O1+. Thus, their reaction with water is one where the reacting acid is stronger than the produced acid, i.e., the reaction is so extensive that it is usually written with a single arrow. The common strong acids are HClO4, HCl, HBr, HI, HNO3, and H2SO4. Hydronium ion is the strongest acid that can exist in water because any acid stronger than hydronium reacts extensively with the water to produce hydronium ion. This effect is known as the leveling effect because the strengths of the strong acids are all leveled to that of hydronium ion. Due to the leveling effect, strong acids are all represented by H3O1+ in acid-base reactions in water. The conjugate bases of the strong acids are all too weak to react as Brønsted bases in aqueous solution. Thus, the ClO41–, Cl1–, Br1–, I1–, and NO31– ions should be treated as spectator ions in aqueous Brønsted acid-base reactions. The HSO41– does not react as a Brønsted base in water, but it can react as a weak acid. Hydrochloric acid, which is an aqueous solution of HCl, is a strong acid, but there are essentially no HCl molecules in hydrochloric acid solution because the above reaction is so extensive. Hydronium ion is a strong acid, but chloride ion is such a weak Brønsted base that it can be ignored in Brønsted acid-base reactions. Consequently, hydrochloric acid is represented as H3O1+ + Cl1– ions in aqueous solutions.
strong acid reaction
Figure 12.13

12.4-9. Weak Acids in Water

Weak acids are represented by the formula of the acid not by H3O1+ in acid-base reactions.
Weak acids are those acids weaker than H3O1+. Thus, their reaction with water is one in which the produced acid is stronger than the reacting acid, i.e., the following reaction is not extensive.
HA + H2O equilibrium arrow A1− + H3O1+
The reverse reaction between hydronium ion and the conjugate base of the weak acid is the extensive reaction, so
K < 1.
The reactions are written with double arrows to emphasize the importance of the back reaction. The concentration of HA is much greater than that of A1– or H3O1+ in a solution of a weak acid. Consequently, weak acids are represented by the formula of the acid not by H3O1+ in acid-base reactions. The example of hydrofluoric acid is considered below.
weak acid reaction
Figure 12.14
The hydronium ion is a much stronger acid than HF, so the reverse reaction is much more extensive than the forward reaction. Consequently, K < 1, and very little HF reacts. Less than 10% of the HF molecules in a typical HF solution react to produce H3O1+ ions, so the solution is represented by HF not by H3O1+.

12.4-10. Bases in Water

All anions are bases because an anion can always accept a proton.
Water is also used as the reference acid in determining relative base strengths. The reaction of a base (A1–, the conjugate base of HA) with water can be represented as follows: A1– + H2O equilibrium arrow HA + OH1–. O2– and NH21– are strong bases. However, OH1– is the strongest base that can exist in water because the above reaction is extensive when A1– is a strong base. Metal hydroxides are the most common strong bases. All anions are bases because an anion can always accept a proton. However some bases are molecular and the common example of ammonia is considered below.
NH3 + H2O equilibrium arrow NH41+ + OH1−
The above reaction is not extensive in the forward direction, which is demonstrated with the use of double arrows, because ammonia is a weak base. Only about 1% of NH3 molecules in a typical aqueous solution react with water to produce NH41+ + OH1–, so an aqueous solution of ammonia is represented as NH3.

12.5 Acid and Base Strengths

Introduction

We have now seen that the extent of an acid-base reaction depends upon the relative strengths of the reacting and produced acids. In this section, we show how the relative strengths of acids are measured and tabulated.

Prerequisites

Objectives

12.5-1. Bond Strengths

Knowledge of the relative acid strengths of the reacting and produced acids allow us to predict the extent of reaction, so we now examine the factors that dictate those strengths. The acid strength of HA is related to the ease with which the H–A bond is broken. If the H–A bond is weaker, then HA gives up the proton more easily and is a stronger acid, but if the bond is stronger, then it does not give up the proton as readily and is a weaker acid. Other factors being equal, we can conclude the following.
If the H–A bond is strong, then HA is a weak acid.
Exercise 12.6:

List the acids HF, HCl, and HBr in order of increasing acid strength given that
DHF = 565 kJ/mol, DHCl = 431 kJ/mol, and DHBr = 366 kJ/mol.
(Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
o_HF_s Other factors being the same, acid strength should increase the order of decreasing bond strength. The HBr bond is the weakest, and HBr is the strongest acid. The HF bond is the strongest bond, and HF is the weakest acid. Consequently, the following is the order of increasing acid strength:
HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
    <    
o_HCl_s Other factors being the same, acid strength should increase the order of decreasing bond strength. The HBr bond is the weakest, and HBr is the strongest acid. The HF bond is the strongest bond, and HF is the weakest acid. Consequently, the following is the order of increasing acid strength:
HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
    <    
o_HBr_s Other factors being the same, acid strength should increase the order of decreasing bond strength. The HBr bond is the weakest, and HBr is the strongest acid. The HF bond is the strongest bond, and HF is the weakest acid. Consequently, the following is the order of increasing acid strength:
HF < HCl < HBr.
HF is a weak acid, while both HCl and HBr are strong acids.
List the conjugate bases in order of increasing base strength. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
o_Br^1-_s The base strength of B1– increases as the strength of the H-B bond increases. Thus, F1– ion is the strongest base because it forms the strongest bond to hydrogen, and Br1– is the weakest base because the H-Br bond is the weakest of the three bonds. The following is the order of increasing base strength:
Br1– < Cl1– < F1–.
    <    
o_Cl^1-_s The base strength of B1– increases as the strength of the H-B bond increases. Thus, F1– ion is the strongest base because it forms the strongest bond to hydrogen, and Br1– is the weakest base because the H-Br bond is the weakest of the three bonds. The following is the order of increasing base strength:
Br1– < Cl1– < F1–.
    <    
o_F^1-_s The base strength of B1– increases as the strength of the H-B bond increases. Thus, F1– ion is the strongest base because it forms the strongest bond to hydrogen, and Br1– is the weakest base because the H-Br bond is the weakest of the three bonds. The following is the order of increasing base strength:
Br1– < Cl1– < F1–.

12.5-2. Bond Breaking

Bond energies are not sufficient to explain relative acid strengths because the tabulated values are for the bonds in the gas phase, not in solution. In addition, the bonding pair is divided between the bound atoms to produce atoms, not ions. The bond energy process is compared to the solution process for HF, HCl, and CH4 in Figures 12.15a and 12.15b.
Each atom retains one electron when HF bond is broken; each atom retains one electron when HCl bond is broken; each atom retains one electron when CH bond is broken.
Figure 12.15a: Two Ways to Break Bonds–Gas Phase
In the gas phase, the bonding pair is split so that each atom gets one electron to produce atoms, not ions.
Both bonding electrons remain on F when HF behaves like an acid; both bonding electrons remain on Cl when HCl behaves like an acid; C-H bond is not acidic because it is not polar.
Figure 12.15b: Two Ways to Break Bonds–Solution Phase
In the solution phase, the bonding pair remains on the more electronegative atom to produce ions, not atoms.
Note that the H–C bond is not polar, so it cannot break to produce ions, which is why hydrogen atoms attached to carbon are not acidic. We conclude that the hydrogen atom must be attached to an atom that is more electronegative than carbon in order to be acidic.

12.5-3. Electronegativity

Breaking the H–A bond in an acid-base reaction produces the ions, and ion formation is favored by large electronegativity differences between the bound atoms. Thus, acid strengths also increase as the electronegativity of the atom to which the hydrogen is bound increases.
Exercise 12.7:

You are given the following compounds and the bond energies of the bonds to hydrogen.

HF HCl CH4
DHF = 565 kJ/mol DHCl = 431 kJ/mol DCH = 413 kJ/mol

Fill in the following. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
strongest of the three acids o_HCl_s The H-Cl and C-H bonds have comparable strengths that are substantially lower than the H-F bond energy. Thus, either the H-Cl or CH4 is predicted to the strongest acid. However, the H-Cl bond is polar, while the C-H bond is not. Consequently, the C-H bond is not acidic and HCl is the strongest acid of the three compounds. Note that HF is more polar than HCl, but both bonds are very polar, so the bond energy difference dominates in this case.
weakest acid o_CH_4_s The C-H bond is not polar, so forming H1+ ions is very difficult. Thus, C-H bonds are not acidic even though they are weaker than some of the bonds in relatively strong acids! CH4 is the weakest acid of the three compounds. The fact that the C-H bonds are not acidic is indicated by the fact that the hydrogen atoms are not written first in the formula.

12.5-4. Oxoacid Strengths

Oxoacids are acids in which the acidic hydrogen is attached to an oxygen atom. The strength of the oxoacid H–O–X depends upon the strength of the H–O bond. Anything that withdraws electron density from the H–O bond, weakens the bond and makes the acid stronger. Thus, the strength of the acid increases with increases in the electronegativity or oxidation state of X. In Table 12.7, we consider four compounds with the general X–OH, where X = H, CH3, Cl, and ClO. There are two lone pairs and a proton on the oxygen atom, so XOH can function as either an acid or a base depending upon the properties of X.
HOH H–O–H (water) is both a very weak acid and a very weak base. In fact its acid and base strengths are equal.
HOCH3 CH3 groups are electron donating, so the oxygen atom is more electron rich than in water. Consequently, CH3OH is a better base than water. Alternatively, the added electron density in the O–H bond strengthens the bond, which makes CH3OH a weaker acid than water.
HOCl Cl is electron withdrawing and is more electronegative than H. Removing electron density from OH has two effects: the oxygen is not as electron rich, so HOCl is a weaker base, and the O–H bond is weakened, so HOCl is a stronger acid. Thus, HOCl is a stronger acid and weaker base than water.
HOClO OClOH (HClO2) is the strongest acid and weakest base in this group. This is because the additional oxygen atom removes even more electron density than the single Cl, so it is a stronger acid than HOCl. Alternatively, the oxidation state of Cl goes from +1 in HClO to +3 in HClO2. The increase in oxidation state withdraws electron density from OH, which makes it a weaker base and a stronger acid.
Table 12.7

12.5-5. Example

Exercise 12.8:

Use the following rules to determine whether each of the reactions is extensive or not.
  • Extensive acid-base reactions occur when the reacting acid and base are much stronger than the produced acid and base.
  • The stronger oxoacid is the one in which the central atom is more electronegative and/or in the higher oxidation state.
    HSO41– + H2SO3 equilibrium arrow H2SO4 + HSO31–
  • extensive No, the oxidation state of the sulfur is +4 in H2SO3, and +6 in H2SO4, so H2SO4 is the stronger acid. The produced acid is stronger than the reacting acid, so the reaction is not extensive.
  • not extensive The oxidation state of the sulfur is +4 in H2SO3, and +6 in H2SO4, so H2SO4 is the stronger acid. The produced acid is stronger than the reacting acid, so the reaction is not extensive.
    H3PO4 + H2AsO41– equilibrium arrow H2PO41– + H3AsO4
  • extensive The oxidation states of phosphorus and arsenic are the same, but phosphorus is more electronegative than arsenic, so the reacting acid (H3PO4) is stronger than the produced acid (H3AsO4). Consequently, the reaction is extensive.
  • not extensive No, the oxidation states of phosphorus and arsenic are the same, but phosphorus is more electronegative than arsenic, so the reacting acid (H3PO4) is stronger than the produced acid (H3AsO4). Consequently, the reaction is extensive.

12.6 Acid Dissociation Constant, Ka

Introduction

The extent of an acid-base reaction depends upon the strengths of the reacting and produced acids, and the acid dissociation constants of the acids give us those relative strengths.

Prerequisites

Objectives

12.6-1. Arrhenius Definition

Arrhenius acids ionize in water rather than react with it. Consequently, H1+ is produced rather than H3O1+.
An Arrhenius acid is a substance that contains H atoms and produces H1+ in water, and an Arrhenius base is a substance that contains OH and produces OH1– in water. All Arrhenius acids and bases are also Brønsted acids and bases, but the Brønsted definition is slightly broader, so not all Brønsted acids and bases are classified as Arrhenius acids and bases. For example, NH3 is a Brønsted base but not an Arrhenius base. Arrhenius acids "ionize" in water to produce H1+ rather than react with it to produce H3O1+.
HA equilibrium arrow H1+ + A1−
The extent of the reaction is dictated by the strength of the acid and is measured by the equilibrium constant, which is called the acid dissociation or acid ionization constant and given the symbol Ka.
Ka =
[H1+][A1−]
[HA]

12.6-2. Brønsted Ka

The dissociation constant of an acid, Ka, is the equilibrium constant for the reaction of the acid with water.

Brønsted Definition of Acid Strength

Brønsted acids do not dissociate in water, they react with it, so the equilibrium reaction becomes
HA + H2O equilibrium arrow H3O1+ + A1–.
The equilibrium constant for the reaction is the following.
Ka =
[H3O1+][A1−]
[HA]
Water is the solvent and considered to be a pure liquid, so it enters the equilibrium expression as 1 (one). Note that this is the same dissociation constant (Ka) as given for Arrhenius acids except that H3O1+ appears instead of H1+, but H3O1+ and H1+ are just two way of representing the same species in the two different theories. The important thing to remember is that acids with large Ka values are stronger than acids with smaller Ka values, regardless of whether the acid is treated as an Arrhenius acid or as a Brønsted acid. HCl is a strong acid (Ka >> 1). There are essentially no HCl molecules in a 0.1 M solution of HCl. The reverse reaction can be ignored when calculating the concentration of H3O1+ or Cl1– because Ka is so large. Consequently, the reaction is usually indicated with a single arrow.
HCl + H2O H3O1+ + Cl1−     Ka =
[H3O1+][Cl1−]
[HCl]
= >> 1
HClO is a weak acid. In a 0.1 M solution of HClO, [H3O1+] = 10–4 M. The reverse reaction is important in determining the concentrations of H1+ and Cl1–, so the double equilibrium arrows are used when writing the Ka equation.
HClO + H2O equilibrium arrow H3O1+ + ClO1−     Ka =
[H3O1+][ClO1−]
[HClO]
= 3.5 × 10−8
H2SO3 is a weak diprotic (contains two protons) acid. In a 0.1 M solution of H2SO3, [H3O1+] = 0.04 M. The importance of the reverse reaction is indicated with the double arrows. Note that only one proton is removed in the Ka equation. The conjugate base of H2SO3 is HSO31–, which is also an acid with its own Ka (1.0 × 10–7).
H2SO3 + H2O equilibrium arrow H3O1+ + HSO31−     Ka =
[H3O1+][HSO31−]
[H2SO3]
= 1.5 × 10−2
HS1– is a very weak acid. In a 0.1 M solution of HS1–, [H3O1+] = 10–7 M.
HS1− + H2O equilibrium arrow H3O1+ + S2−     Ka =
[H3O1+][S2−]
[HS1−]
= 1.3 × 10−13
Hydronium ion is the strongest acid that can exist in water. HCl is a stronger acid, but it cannot exist in water because it reacts so extensively with the water.
H3O1+ + H2O equilibrium arrow H2O + H3O1+     Ka =
[H3O1+]
[H3O1+]
= 1

12.6-3. Determining K for an Acid-Base Reaction

The equilibrium constant for an acid-base reaction equals the acid dissociation constant of the reacting acid divided by that of the produced acid.
The equilibrium constant for any acid-base reaction can be determined from the Ka values of the reacting and produced acids as shown in Equation 12.1.
( 12.1 )
K =
Ka of reacting acid
Ka of produced acid
Equilibrium Constant, K
Recall that we are using the general guideline that acid-base reactions in which K > ~1000 are so extensive that the back reaction can be ignored in calculations, and they can be written with single arrows. This means that the reacting acid must be about 1000 times stronger than the produced acid if an acid-base reaction is considered to be so extensive that the back reaction can be ignored in calculations.

12.6-4. Determining K Exercise

Exercise 12.9:

Use the following Ka values to answer the questions.

Acid Ka
HF 7.2 × 10–4
HNO2 4.0 × 10–4
NH41+ 5.6 × 10–10
HCN 4.0 × 10–10

What is the strongest acid? (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
o_HF_s The acid with the largest Ka is HF, so it is the strongest acid.

What is the acid with the strongest conjugate base? (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
o_HCN_s The acid with the smallest Ka is HCN, so it is the weakest acid. Conjugate base strengths are opposite the acid strengths, so F1– ion would be the weakest base and CN1– ion the strongest base.

Are the following reactions extensive enough to be expressed with single arrows?
    HCN + NH3 equilibrium arrow CN1– + NH41+
  • Yes We can use the Ka values to see that NH41+ ion, the produced acid, is a stronger acid than HCN, the reacting acid, so the reaction is not extensive.
    K =
    4.0 × 10−10
    5.6 × 10−10
    = 0.71
  • No
    HF + CN1– equilibrium arrow F1– + HCN
  • Yes
  • No Ka(HF) >> Ka(HCN), so this reaction is extensive.
    K =
    7.2 × 10−4
    4.0 × 10−10
    = 1.8 × 106

    K >> 103, so essentially all of one reactant will be consumed and the chemical equation could be written with a single arrow.

12.6-5. Predicting Extent Exercise

Exercise 12.10:

Use the following Ka values to determine the equilibrium constant for the reaction of each of the acids with ClO1– and indicate whether a single arrow can be used to describe the reaction.

Acid Ka Base
HF 7.2 × 10–4 F1–
H2S 1.0 × 10–7 HS1–
HClO 3.5 × 10–8 ClO1–
HCN 4.0 × 10–10 CN1–
HS1– 1.3 × 10–13 S2–

HF
K = 2.1e4___ HF + ClO1– F1– + HClO
Reacting acid is HF. Produced acid is HClO.
K =
Ka(HF)
Ka(HClO)
=
7.2e−04
3.5e−08
= 2.1e+04
H2S
K = 2.9___ H2S + ClO1– equilibrium arrow HS1– + HClO
Reacting acid is H2S. Produced acid is HClO.
K =
Ka(H2S)
Ka(HClO)
=
1.0e−07
3.5e−08
= 2.9
  • equilibrium arrow K > 1000, so the reverse reaction is negligible and a single arrow can be used.
  • K > 1, but K < 1000. H2S is a stronger acid than HClO, but it is not much stronger. Consequently, a double arrow better describes the equilibrium mixture.
  • equilibrium arrow
HCN
K = 1.1e-2___ HCN + ClO1– equilibrium arrow CN1– + HClO
Reacting acid is HCN. Produced acid is HClO.
K =
Ka(HCN)
Ka(HClO)
=
4.0e−10
3.5e−08
= 1.1e−02
HS1–
K = 3.7e-6___ HS1– + ClO1– equilibrium arrow S2– + HClO
Reacting acid is HS1–. Produced acid is HClO.
K =
Ka(HS1−)
Ka(HClO)
=
1.3e−13
3.5e−08
= 3.7e−06
  • K < 1, so a double arrow should be used to describe the equilibrium mixture. However, K is not very small, so non-negligible amounts of the products will be in an equilibrium mixture.
  • equilibrium arrow
  • K < < 1, so a double arrow should be used to describe the equilibrium mixture. Indeed, K is so small that the amount of product in an equilibrium mixture is negligible.
  • equilibrium arrow K < < 1, so a double arrow should be used to describe the equilibrium mixture. Indeed, K is so small that the amount of product in an equilibrium mixture is negligible.

12.7 Solutions of Weak Bases

Introduction

Water is also an acid, so it can react with weak bases to produce hydroxide ion and the conjugate acid of the weak base.

12.7-1. Most Anions are Weak Bases

Weak bases react with water to produce hydroxide ion and their conjugate acid.
Consider the reaction of hypochlorite ion, a weak base, with water: ClO1– + H2O(l) equilibrium arrow HClO(aq) + OH1–. The reaction of a base with water breaks an O–H bond in water in a process called hydrolysis. Most weak bases are found as salts, so salts such as KClO, NaF, KCN, and LiNO2 all form basic solutions in water because their anions react with water to produce hydroxide ion.

12.8 Acid Base Table

Introduction

Acid-base reactions are extensive when the reacting acid is stronger than the produced acid. Acid strengths are measured by the acid dissociation constants for the acids. Combining these two facts, we can now write equations for acid-base reactions and determine if they are extensive.

Objectives

12.8-1. Using an Acid-Base Table Video

The Acid-Base Table

12.8-2. Using the Acid-Base Table to Write Chemical Equations

Using the Acid-Base Table for Chemical Equations

12.8-3. Acid-Base Table

Acid base reactions are extensive when the reacting acid is stronger than the produced acid, and the relative acid strengths can be deduced from the acid dissociation constants. Consequently, tables of acids and their Ka values are common. The acid-base table used in the text includes the acid, its Ka, and its conjugate base. Thus, both the reactants and the products of an acid-base reaction can be found in the table. The acid-base table used in this text is given in the Acid-Base Table resource. It lists the acids in the left column, their Kas in the center column, and their conjugate bases in the right column. Acid strengths decrease and base strengths increase going down the table. This arrangement puts the strongest acid (HClO4) in the upper left corner and the strongest base (O2– ion) in the lower right corner. Therefore, consider the following.
Acid-base reactions are extensive when the reacting acid is above (stronger than) the produced acid in the table.
The following examples show how the relative positions of the acid and base allow us to predict whether an acid-base reaction is extensive. HA is a stronger acid than HB, so it lies above HB in the acid-base table. B1– is a stronger base than A1–, so it lies below A1– in the acid-base table.
relationships of acids and bases on an acid-base table
Figure 12.16a: Reactivity from the Relative Positions of Reactants and Products
Reaction of the stronger acid (HA) with the stronger base (B1–) is favorable (K > 1). Note that this arrangement guarantees that the reacting acid is stronger than the produced acid. If the reacting acid is well above the reacting base (or produced acid), the reaction is so extensive that it can be written with a single arrow. For example,
HF + OH1– F1– + H2O.
relationship of strong acid and strong base on an acid-base table
Figure 12.16b: Reactivity from the Relative Positions of Reactants and Products
Reaction of the weaker acid (HB) with the weaker base (A1–) is not extensive. Note that the reacting acid is below (weaker than) the produced acid. Only a small fraction of the acid is converted to its conjugate base (B1–), and only a small fraction of the base is converted to its conjugate acid (HA). The back reaction of the stronger acid and base is important in determining the concentrations of B1– and HA, so the net equation is usually written with double arrows. For example, HCN + F1–equilibrium arrow CN1– + HF.
relationship of weak acid and weak base on an acid-base table
Figure 12.16c: Reactivity from the Relative Positions of Reactants and Products

12.8-4. Acid-Base Table Examples

We now use the acid-base table to write chemical equations for the acid-base reactions that result when the following solutions are mixed and use Equation 12.1
K =
Ka of reacting acid
Ka of produced acid
to determine their equilibrium constants. We use the relative positions of the reactants in the table and the equilibrium constants to indicate whether the reactions are extensive. Remember that the acid strengths increase going up the table, but base strengths increase going down the table. View the Acid-Base Table resource.

Hydrogen chloride gas is bubbled into water.

The relative reactant positions and their Ka values from the table in the resources are given in Figure 12.17a. Note that the reactant is hydrogen chloride, not hydrochloric acid, so the reacting acid is HCl. The reacting base is then water. The products of the reaction are Cl1–, the conjugate base of the reacting acid, and H3O1+, the conjugate acid of the reacting base. The acid is above the base, so we expect a favorable reaction. Note that the Ka values of the strong acids are given simply as << 1 because they are so large that they cannot be determined accurately. We use Equation 12.1
K =
Ka of reacting acid
Ka of produced acid
to determine that the value of the equilibrium constant is very large, so a single arrow should be used. Thus, dissolving
HCl(g)
in water produces hydrochloric acid, which is a solution of hydronium and chloride ions.
Figure 12.17a

Solutions of hydrocyanic acid and potassium nitrite are mixed.

We identify HCN as the reacting acid, K1+ as a spectator ion, and the NO21– ion as the reacting base. The reactants and their Ka values as determined from the acid-base table are given in Figure 12.17b. The reacting acid is below the reacting base, so little proton transfer is expected. Using Equation 12.1
K =
Ka of reacting acid
Ka of produced acid
, we determine that the equilibrium constant is only 1.0 × 10–6, so very little product would form and double arrows would have to be used in the chemical equation.
Figure 12.17b

A solution of potassium hypochlorite is added to hydrochloric acid.

We identify the K1+ ion as a spectator ion and the ClO1– ion as the reacting base. HCl is leveled to H3O1+ + Cl1– in water, so H3O1+ is the reacting acid, while Cl1– is also a spectator ion. We retrieve the reacting acid and base from the acid-base table as shown in Figure 12.17c. The acid is well above the base, so an extensive proton transfer is expected, and using Equation 12.1
K =
Ka of reacting acid
Ka of produced acid
, we determine that K = 2.9 × 107. Thus, the reaction can be written with a single arrow.
Figure 12.17c

Ammonia is added to water.

We identify NH3 as the reacting base and H2O as the reacting acid. The relative positions and Ka values of the reactants as given in the acid-base table are shown in Figure 12.17d. The base is well above the acid, so little proton transfer is expected. Indeed, K = 1.8 × 10–5 for the reaction, so double arrows should be used for the reaction of this weak base with water.
Figure 12.17d

Hydrofluoric acid is added to a solution of potassium hydrogen sulfide.

HF is the reacting acid and K1+ is a spectator ion. The HS1– ion has a proton and is an anion, so it can behave as either and acid or a base, but the HF will not react with another acid, so HS1– is the reacting base in this reaction. The acid is above the base so the transfer is favorable with an equilibrium constant of 7.2 × 103, so a single arrow can be used in the net equation to show that essentially all of at least one of the reactants disappears.
Figure 12.17e

12.8-5. Identifying the Reactants

Identifying the reacting species is the first thing you must do when writing the net ionic equation for an acid-base equation. Remember the following:
Exercise 12.11:

Indicate how the reacting acids and bases would be represented in the net ionic equations for the acid-base reactions that occur when solutions of the following are mixed. Refer to the Acid-Base Table resource. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
nitric acid and potassium sulfide
acid o_H_3O^1+_s Nitric acid is above H3O1+ on the acid-base table, so it is a strong acid. Consequently, nitric acid is found in solution as H3O1+ + NO3O31– ions. H3O1+ is the acid. Nitric acid is HNO3, but it is a strong acid.
base o_S^2-_s The anion, S2– is the base, and the potassium ion is a spectator ion. Bases are usually anions. Anions with charges greater than –1 are usually fairly strong bases.
ammonium chloride and sodium cyanide
acid o_NH_4^1+_s Ammonium ion is a weak acid, and the chloride ion is a spectator ion because it is the conjugate base of a strong acid. A Brønsted acid must have a proton! Although the proton is usually written first in the formula of the acid, there is one acid where it is never written first.
base o_CN^1-_s The cyanide anion, CN1–, is the base, and the sodium ion is a spectator.
sodium carbonate and hydrofluoric acid
acid o_HF_s HF is a weak acid, so it must be written as the molecular formula.
base o_CO_3^2-_s Carbonate ion, CO32–, is the base, and sodium ion is a spectator.
ammonia and perchloric acid
acid o_H_3O^1+_s Perchloric acid is a strong acid (It is above H3O1+ in the Acid-Base Table.), so it is represented by H3O1+.
base o_NH_3_s Ammonia is a weak base.

12.8-6. Net Equations

Exercise 12.12:

Use the Acid-Base Table resource to write net equations for the reactions described below. Use a single arrow to indicate that a reaction is extensive and double arrows to indicate that it is not. Assume that a reaction is extensive only when the reacting acid is at least 1000 times stronger than the produced acid. That is, use a single arrow if the following is true.
  • Ka(reacting acid) > 1000 × Ka(produced acid)
Indicate the extent of the reaction by choosing the single or double arrows. (Indicate any subscripted characters with an underscore (_) and any superscripted characters with a carat (^). For example, NH_4^1+ for NH41+.)
Barium hydroxide and nitric acid are mixed.
o_H_3O^1+_s H3O1+ + OH1– H2O + H2O (acid 1)
    +    
o_OH^1-_s H3O1+ + OH1– H2O + H2O (base 2)
  • equilibrium arrow H3O1+ + OH1– H2O + H2O
o_H_2O_s H3O1+ + OH1– H2O + H2O (base 1)
    +    
o_H_2O_s H3O1+ + OH1– H2O + H2O (acid 2)
Sodium acetate and hydrochloric acid are mixed.
o_H_3O^1+_s H3O1+ + C2H3O21– H2O + HC2H3O2 (acid 1)
    +    
o_C_2H_3O_2^1-_s H3O1+ + C2H3O21– H2O + HC2H3O2 (base 2)
  • equilibrium arrow H3O1+ + C2H3O21– H2O + HC2H3O2
o_H_2O_s H3O1+ + C2H3O21– H2O + HC2H3O2 (base 1)
    +    
o_HC_2H_3O_2_s H3O1+ + C2H3O21– H2O + HC2H3O2 (acid 2)
Sodium hydroxide and hydrofluoric acid are mixed.
o_HF_s HF + OH1– F1– + H2O (acid 1)
 + 
o_OH^1-_s HF + OH1– F1– + H2O (base 2)
  • equilibrium arrow HF + OH1– F1– + H2O
o_F^1-_s HF + OH1– F1– + H2O (base 1)
    +    
o_H_2O_s HF + OH1– F1– + H2O (acid 2)
Ammonium chloride and sodium cyanide are mixed.
o_NH_4^1+_s NH41+ + CN1– equilibrium arrow NH3 + HCN (acid 1)
    +    
o_CN^1-_s NH41+ + CN1– equilibrium arrow NH3 + HCN (base 2)
  • NH41+ + CN1– equilibrium arrow NH3 + HCN
  • equilibrium arrow
o_NH_3_s NH41+ + CN1– equilibrium arrow NH3 + HCN (base 1)
    +    
o_HCN_s NH41+ + CN1– equilibrium arrow NH3 + HCN (acid 2)
Ammonium chloride and sodium fluoride are mixed.
o_NH_4^1+_s NH41+ + F1– equilibrium arrow NH3 + HF (acid 1)
    +    
o_F^1-_s NH41+ + F1– equilibrium arrow NH3 + HF (base 2)
  • NH41+ + F1– equilibrium arrow NH3 + HF
  • equilibrium arrow
o_NH_3_s NH41+ + F1– equilibrium arrow NH3 + HF (base 1)
    +    
o_HF_s NH41+ + F1– equilibrium arrow NH3 + HF (acid 2)

12.9 pH and pKa

Introduction

The hydronium ion concentration is an important property of an aqueous solution, but it can be very small, so it is often given on the p-scale to avoid writing exponents.

Objectives

12.9-1. The Ion Product Constant of Water

Water is both a very weak acid and a very weak base, so it can react with itself.
H2O + H2O equilibrium arrow H3O1+ + OH1−
Remember that water is the solvent and is treated as a pure liquid, so it enters the equilibrium expression as unity to produce the following equilibrium constant expression.
( 12.2 )
Kw = [H3O1+][OH1−] = 1.0 × 10−14
Ion Product of Water
The equilibrium constant for the reaction is called the ion product constant of water and given the symbol Kw. The value given for the equilibrium constant is the value at 25 °C. Equation 12.2 can be used to determine either [H3O1+] or [OH1–] if the other is known. In pure water, the hydronium and hydroxide ion concentrations are the same because they are produced in a 1:1 ratio from water. Consequently, in pure water at 25 °C, the following is true.
( 12.3 )
[H3O1+] = [OH1−] = (Kw)1/2 = 1.0 × 10−7 M
Concentrations in Pure Water
Solutions for which Equation 12.3 is valid are called neutral; solutions in which [H3O1+] > [OH1–] are called acidic; and solutions in which [H3O1+] < [OH1–] are called basic or alkaline.

12.9-2. pH

The hydronium ion concentration is an important characteristic of the solution, but it is normally a small number. To avoid the use of exponentials in discussions of hydronium ion concentrations, we define pH.
( 12.4 )
pH = −log [H3O1+]
pH Defined
The exponent of [H3O1+] is usually negative, so the sign of log [H3O1+] is usually negative. The negative sign in Equation 12.4 assures that the pH is usually positive. Because of the negative sign, a high pH implies a low hydronium ion concentration, and a low pH implies a high hydronium ion concentration. Equation 12.2
Kw = [H3O1+][OH1−] = 1.0 × 10−14
can be rearranged as follows to show how the hydronium ion concentration, and therefore the pH, of a basic solution can be determined.
( 12.5 )
[H3O1+] =
Kw
[OH1−]
=
1.0 × 10−14
[OH1−]
Equation 12.5 shows that solutions with high hydroxide ion concentrations have low hydronium ion concentrations, so a high pH also implies a high hydroxide ion concentration and a low pH implies a low hydroxide ion concentration. A neutral solution is one in which
[H3O1+] = [OH1−] = 1.0 × 10−7 M,
so the pH of a neutral solution is determined to be
pH = −log(1.0 × 10−7) = 7.0.
The hydronium ion concentration is greater in an acidic solution, so the pH of an acidic solution is less than 7.0. The hydronium ion concentration is less in a basic solution, so the pH of a basic solution is greater than 7.0. These conclusions are summarized in the following table.
Solution pH Solution Type
above 7 basic
equal to 7 neutral
below 7 acidic
Table 12.8: Solution Type Versus pH

12.9-3. Hydronium Ion Concentration Exercise

Exercise 12.13:

What is the hydronium ion concentration in the following solutions? Use e-format for exponentials:
1 × 10–4 = 1e–04.
pure water 1.0e-7___ H2O is the sole source of both H3O1+ and OH1– in pure water, and the two ions are produced in equal amounts by the reaction of water with itself. Consequently, the concentrations of the two ions must be equal, so the equilibrium constant expression for water can be written as the following.
[H3O1+][OH1–] = [H3O1+][H3O1+] = [H3O1+]2 = 1.0 × 10–14
[H3O1+] =
1.0 × 10−14
= 1.0 × 10−7 M
= [OH1–]
The hydronium ion and hydroxide ion concentrations in pure water are each 1.0 × 10–7 M. A solution in which the two ion concentrations are equal is said to be a neutral solution.
M
[OH1−] = 2.5e−04 M
4.0e-11___ We are given [OH1–]and asked for [H3O1+], so we solve Equation 12.2 as follows.
[H3O1+][PH1+] = 1.0 × 10–14
[H3O1+] =
1.0 × 10−14
[OH1−]
=
1.0 × 10−14
2.5 × 10−4
= 4.0 × 10−11 M

The hydroxide ion concentration is greater than the hydronium ion concentration, so the solution is said to be a basic solution.
M
[OH1−] = 6.2e−12 M
1.6e-03___ Solve Equation 12.2 for the following.
[H3O1+][PH1+] = 1.0 × 10–14
[H3O1+] =
1.0 × 10−14
[OH1−]
=
1.0 × 10−14
6.2 × 10−12
= 1.6 × 10−3 M

The hydronium ion concentration is greater than the hydroxide ion concentration, so the solution is said to be an acidic solution.
M

12.9-4. pH Exercises

Exercise 12.14:

What is the pH if [H3O1+] = 1.3 × 10–5 M?
4.89___ pH = –log[H3O1+]= –log(1.3 × 10–5) = –(–4.89) = +4.89
What is the pH of 0.10 M HCl?
1.0___ HCl is a strong acid, so [H3O1+] = 0.10 M.
pH = –log(0.10) = –(–1.0) = 1.0
    Pick the stronger acid given the pHs of their 0.1 M solutions.
  • The pH of 0.1 M HBrO is 4.8. X-O-H + H2O equilibrium arrow X-O1– + H3O1+
    The stronger acid is the one for which the above reaction is most extensive, i.e., the one that produces the greater amount of H3O1+. The solution with the greater [H3O1+] is the one with the lower pH, so HClO is a stronger acid than HBrO. This would be predicted because Cl is more electronegative than Br.
  • The pH of 0.1 M HClO is 4.3.
What is the pH of a 0.022 M Ba(OH)2 solution? Hint: the hydroxide ion concentration is not
0.022 M.

12.64___ Ba(OH)2 Ba + 2 OH1–
[OH1–] = 2 × Ba(OH)2 concentration = 2(0.022 M) = 0.044 M
[H3O1+] =
Kw
[OH1−]
=
1.0 × 10−14
0.044
= 2.3 × 10−13

pH = –log [H3O1+] = –log(2.3 × 10–13) = 12.64

12.9-5. pKa

A high pKa implies a weak acid.
The Ka of an acid is a commonly used property of acids because it describes the acid strength, but it is frequently given as the pKa to avoid using negative exponents in discussions of acid strength. The pKa of an acid is the negative base 10 logarithm of the Ka.
( 12.6 )
pKa = −log Ka
pKa
Acids with high pKas are weak acids because of the negative sign in the pKa definition. The following table lists some acids, their Kas and their pKas.
Acid Ka pKa
HF 7.2 × 10–4 3.14
HOCl 3.5 × 10–8 7.46
HCN 4.0 × 10–10 9.40
Table 12.9
Note that the pKa increases as the acid strength decreases.

12.9-6. pKa Exercise

Exercise 12.15:

A 0.1 M solution of which of the following acids has the higher pH?
  • phenol (pKa = 10.0)
  • HSO31– (pKa = 7.0) Both substances are acids, so the solution with the higher pH (lower hydronium ion concentration) results from the weaker acid. Phenol is the weaker acid because it has the higher pKa, so the phenol solution has the higher pH.

12.9-7. Selecting the Solution with the Lower pH Exercise

Exercise 12.16:

Indicate the solution in each pair that has the lower pH.
  • 0.10 M HNO2 The acids are identical, so the only difference is concentration. The more concentrated acid has the greater hydronium ion concentration and the lower pH.
  • 0.15 M HNO2
  • 0.10 M KF
  • 0.15 M KF Both are solutions of the same weak base, so the hydroxide ion concentration and pH increase with the concentration of the base. Thus, the less concentrated base (0.10 M KF) has the lower OH1– concentration, the greater H3O1+ concentration, and the lower pH.
  • 0.05 M benzoic acid (pKa = 4.19) The concentrations are the same, but lactic acid is a stronger acid (lower pKa), so it has the lower pH.
  • 0.05 M lactic acid (pKa = 3.85)
  • 0.1 M Ba(OH)2 Both are strong base solutions. There are two moles of hydroxide ion in each mole of Ba(OH)2, so [OH1–] = 2(0.10) = 0.20 M in the Ba(OH)2 solution, but it is only 0.15 M the KOH solution. The 0.15 M KOH has the lower hydroxide ion concentration, so it has the greater hydronium ion concentration and lower pH.
  • 0.15 M KOH

12.10 Exercises and Solutions

Select the links to view either the end-of-chapter exercises or the solutions to the odd exercises.