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Seager Fundamentals of GOB 1e (Homework)

James Finch

Chemistry - College, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 5 / 18

Due : Friday, February 1, 2030 00:00 EST

Last Saved : n/a Saving...  ()

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2/2 0/2 0/1 –/2 –/4 3/3 0/1 –/1 –/1 0/1
Total
5/18 (27.8%)

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1. 2/2 points  |  Previous Answers SeaFundGOB1 1.5.E.033. My Notes
Question Part
Points
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1 2
1/1 1/1
3/100 4/100
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2/2
 
    This question uses numerical grading without significant figures enforced.
One foot is approximately equal to 30.5 cm. Express this length in millimeters and meters.
length = Correct: Your answer is correct. seenKey

305

 mm Correct! length = Correct: Your answer is correct. seenKey

0.305

 m Correct!


Solution or Explanation
Convert one foot to meters, and then use the relationship 1 m = 1000 mm to convert to millimeters.
1 foot
30.5 cm
1 foot
1 m
100 cm
 = 0.305 m
0.305 m
1000 mm
1 m
 = 305 mm
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2. 0/2 points  |  Previous Answers SeaFundGOB1 1.5.E.041. My Notes
Question Part
Points
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1 2
0/1 0/1
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0/2
 
    This question uses numerical grading with significant figures enforced.
The weather report says the temperature is 89°F.
(a)
What is this temperature on the Celsius scale?
WebAssign will check your answer for the correct number of significant figures. Incorrect: Your answer is incorrect. seenKey

32

 °C ⨯ Recall the conversion factor from the Fahrenheit to the Celsius scale:
°C = 
5
9
 
°F − 32
(b)
What is this temperature on the Kelvin scale?
WebAssign will check your answer for the correct number of significant figures. Incorrect: Your answer is incorrect. seenKey

305

 K ⨯ Recall the conversion factor from the Celsius to the Kelvin scale:
K = 273 + °C


Solution or Explanation
(a)
What is this temperature on the Celsius scale?
°C = 
5
9
 
°F − 32
 
 = 
5
9
 
89°F − 32
 = 
5
9
 (57)
 = 31.67°C ≅ 32°C
(b)
What is this temperature on the Kelvin scale?
K = 273 + °C
 = 273 + 31.67°C
 = 304.67 K ≅ 305 K
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3. 0/1 points  |  Previous Answers SeaFundGOB1 1.6.E.044. My Notes
Question Part
Points
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1
0/1
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0/1
 
    This question uses multiple-select mode. All correct answers must be selected for the student to receive credit.
Which of the following numbers are written correctly using scientific notation? (Select all that apply.)
Incorrect: Your answer is incorrect.


⨯ The "✕ 10" component is missing. The exponent belongs on the 10, not on the decimal.


Solution or Explanation
The general form of scientific notation is
m ✕ 10n,
 where m is the decimal component (also called "mantissa"), and n is the exponential term.
Check to make sure the decimal is in the standard position. The absolute value of the decimal should be greater than or equal to 1 and less than 10.
  • The decimal in 1.2 ✕ 102 is in the correct position.
  • The decimal in 12.0 ✕ 102 is not in the correct position.
  • The decimal in 0.12 ✕ 102 is not in the correct position.
Also check for unnecessary zeros before the first non-zero digit.
  • 002.4 ✕ 10−4 is not correct. It should simply be 2.4 ✕ 10−4.
  • 0.024 ✕ 10−4 is not correct. It should be 2.4 ✕ 10−6.
The correct answers are:
  • 4.4 ✕ 105
  • 9.9 ✕ 10−5
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4. –/2 points SeaFundGOB1 1.LC.003. My Notes
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0/100 0/100
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–/2
 
    This question uses multiple-choice mode. Each subpart has only one correct answer.
Classify the substances italicized in the following scenarios as those of an element, compound, homogenous mixture, or heterogeneous mixture.
(a)
An emergency medical technician encounters a patient exhibiting symptoms of carbon monoxide (CO) poisoning (e.g., headache, dizziness, and confusion, amongst others).
    
(b)
Your dietician prescribed more salads in your diet.
    
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5. –/4 points SeaFundGOB1 1.7.E.062. My Notes
Question Part
Points
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1 2 3 4
–/1 –/1 –/1 –/1
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–/4
 
    This question uses multiple-choice grading with pulldown menus.
Write the following measured quantities as you would record them, using the correct number of significant figures based on the device used to make the measurement.
(a)
Exactly 1 mL of water measured with a graduated cylinder that has a smallest scale marking of 0.1 mL.
(b)
A temperature that appears to be exactly 76 degrees using a thermometer with a smallest scale marking of 1°C.
(c)
A time of exactly six seconds measured with a stopwatch that has a smallest scale marking of 0.1 second.
(d)
Nineteen and one-half degrees measured with a protractor that has 1-degree scale markings.
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6. 3/3 points  |  Previous Answers SeaFundGOB1 1.LC.013. My Notes
Question Part
Points
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1 2 3
1/1 1/1 1/1
1/100 1/100 1/100
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3/3
 
    This question is an application of dimensional analysis that uses both multiple-choice pulldown menus and numerical grading with significant figures.
Creatinine is a substance found in blood. An analysis of a blood serum sample detected 9.2 mg of creatinine.
Express this amount in grams by using dimensional analysis.
9.2 mg ✕ 
Correct: Your answer is correct. seenKey

1 g
Correct: Your answer is correct. seenKey

1000 mg
= WebAssign will check your answer for the correct number of significant figures. Correct: Your answer is correct. seenKey

0.0092

 g


Solution or Explanation
Two factors result from the relationship
1 g ≡ 1000 mg.
 The factors are:
1 g
1000 mg
 and
1000 mg
1 g
The first factor is used because it cancels the mg unit and generates the g unit:
9.2 mg ✕ 
1 g
1000 mg
 = 0.009200 g ≅ 0.0092 g
The number of significant figures matches the number in 9.2 because the 1 and 1000 are exact numbers.
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7. 0/1 points  |  Previous Answers SeaFundGOB1 8.4.E.038. My Notes
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0/1
 
    This question uses multiple-select mode where each choice is an image generated by MarvinJS. All correct answers must be selected for the student to receive credit.
Which of the following compounds represent structural isomers of each other? (Select all that apply.)

Incorrect: Your answer is incorrect.

Solution or Explanation
Determine the formulas for each of the compounds. Structural isomers must all have the same molecular formula, in this case C5H10O2.
Compound Formula Isomeric?
Condensed structure of an organic compound.
Five C atoms are connected in a chain with single bonds. One O atom is single-bonded to the fourth C atom in the chain and is also bonded to one H atom. A second O atom is double-bonded to the fifth C atom in the chain. The first C atom has three H atoms. The second and third C atoms each have two H atoms. The fourth and fifth C atoms each have one H atom.
SMILES: [CH3][CH2][CH2][CH]([OH])[CH](=O)
C5H10O2 Isomeric
Condensed structure of an organic compound.
Five C atoms and one O atom are connected in a chain with single bonds in the order: CCCCCO. The O atom has one H atom. A second O atom is double-bonded to the fifth C atom in the chain. The terminal C atom has three H atoms. The second, third, and fourth C atoms each have two H atoms.
SMILES: [CH3][CH2][CH2][CH2]C(=O)[OH]
C5H10O2 Isomeric
Condensed structure of an organic compound.
Five C atoms and one O atom are connected in a chain with single bonds in the order: CCCCCO. The O atom has one H atom. A second O atom is double-bonded to the second C atom in the chain. The terminal C atom has three H atoms. The third, fourth, and fifth C atoms each have two H atoms.
SMILES: [CH3]C(=O)[CH2][CH2][CH2][OH]
C5H10O2 Isomeric
Condensed structure of an organic compound.
Five C atoms and one O atom are connected in a chain with single bonds in the order: CCCCCO. The O atom has one H atom. The terminal C atom has three H atoms. The four non-terminal C atoms each have two H atoms.
SMILES: [CH3][CH2][CH2][CH2][CH2][OH]
C5H12O Not isomeric
Condensed structure of an organic compound.
Five C atoms and two O atoms are connected in a chain with single bonds in the order: OCCCCCO. The two O atoms each have one H atom. The five non-terminal C atoms each have two H atoms.
SMILES: [OH][CH2][CH2][CH2][CH2][CH2][OH]
C5H12O2 Not isomeric
Condensed structure of an organic compound.
Five C atoms and one O atom are connected in a chain with single bonds in the order: CCOCCC. A second O atom is double-bonded to the second C atom in the chain. The two terminal C atoms each have three H atoms. The third and fourth C atoms each have two H atoms.
SMILES: [CH3]C(=O)O[CH2][CH2][CH3]
C5H10O2 Isomeric
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8. –/1 points SeaFundGOB1 8.LC.008. My Notes
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–/1
 
    This question uses fill-in-the-blank grading for nomenclature. The given image is created by MarvinJS.
Provide the correct IUPAC name for the following cycloalkane.
Skeletal structure of a hydrocarbon with the apparent formula C9H18.
Five C atoms are connected to each other in a ring. The C atoms are connected with single bonds. The first C atom in the ring is single-bonded to a sixth C atom, which is further single-bonded to a seventh C atom. The first C atom in the ring is also single-bonded to an eighth C atom. The second C atom in the ring is single-bonded to a ninth C atom.
SMILES: C1(CC)(C)C(C)CCC1
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9. –/1 points SeaFundGOB1 8.2.E.015. My Notes
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–/1
 
    This question asks students to draw "complete" chemical structures with MarvinJS. A starting template is provided.
Glutamine is an essential component of proteins. It has the basic structure shown here.
Complete the structure by adding hydrogen atoms on the basis of the number of covalent bonds possible for each atom.
  • Draw all hydrogen atoms.
  • Assume that the molecule has no formal charges.
  • Use the given template.

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Marvin JS
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10. 0/1 points  |  Previous Answers SeaFundGOB1 8.CT.E.121. My Notes
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0/1
 
    This question asks students to draw "skeleton" chemical structures with MarvinJS.
One of the fragrant components in mint plants is menthene, a compound whose IUPAC name is 1-isopropyl-4-methylcyclohexene.
Draw a structural formula for menthene.
  • You do not have to consider stereochemistry.
  • All hydrogen atoms are implied.

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Marvin JS
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Incorrect: Your answer is incorrect.
Marvin JS


Solution or Explanation
Structural formula for 1-isopropyl-4-methylcyclohexene (menthene) is:
Skeletal structure of 1-isopropyl-4-methylcyclohexene, C10H18.
Six C atoms are connected in a ring. The first and the second C atom in the ring are double-bonded. The other bonds in the ring are all single bonds. The first C atom in the ring is single-bonded to a seventh C atom. The seventh C atom is single-bonded to an eighth C atom, and also single-bonded to a ninth C atom. The fourth C atom in the ring is single-bonded to a tenth C atom.
SMILES: CC(C)C1=CCC(C)CC1
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