- This exercise will let students review and reference question concepts.
- Read It links are available as a learning tool under each question so students can quickly jump to the corresponding section of the eTextbook.
- Students get just-in-time learning support with Watch It videos that contain narrated and closed-captioned videos walking students through the proper steps to solve a similar problem.
Use any necessary data from the figure below.
Several curves are plotted on a coordinate plane, with horizontal axis Time factor Tv and vertical axis Degree of consolidation Uv(%). Each curve represents a different Tc value beginning on the left with Tc = 0 and increasing to Tc = 5 for the rightmost curve.
The curves go down and to the right ending at the x-axis. Curves with larger Tc have a steeper slope in the middle of the curve and flatter slope at the beginning and end of the curve than curves with lower Tc.
Some approximate points are given below for various values of
Tc as (
Tv,
Uv).
- for Tc = 0.04: (0.03, 8.035), (0.067, 24.21), (0.1, 31.83), (0.23, 51.61)
- for Tc = 0.2: (0.2, 33.65), (0.24, 41.19), (0.3, 49.79), (0.42, 62.81)
- for Tc = 1: (1, 69.46), (1.1, 76.47), (1.23, 82.95), (1.3, 85.66)
- for Tc = 2: (2, 83.45), (2.13, 88.16), (2.2, 90.04), (2.3, 92.22)
For a sand drain project (see figure below),
A sand drain is shown in section view and plan view.
- The section view begins at the bottom with a sand layer, above that is a clay layer, and another sand layer above that.
- The groundwater table comes to the middle of the top sand layer.
- A surcharge is applied downward from the top.
- Two vertical sand drains are shown going from the surface downward and ending at the top of the lower sand layer. These drains have radius rw and provide radial drainage.
- Vertical drainage occurs between the sand drains.
- The thickness of the clay layer is Hc.
- The plan view shows that the sand drain is approximately hexagonal with an effective drainage diameter of de (the distance between midpoints of opposite sides of the hexagon) and radius rw.
the following are given.
Clay: Normally consolidated
Hc
=
3.35 m (one-way drainage)
Cc
=
0.3
eo
=
0.74
cv
=
0.015 m2/day
Effective Overburden Pressure at the Middle of Clay Layer = 88 kN/m2
Sand Drain
rw
=
0.07 m
rw
=
rs
de
=
2.8 m
cv
=
cvr
A surcharge is applied as shown in the figure below.
A piecewise function is plotted on a coordinate plane, with horizontal axis Time (days) and vertical axis Surcharge (kN/m2). The function begins at the origin and goes up and right with constant slope to point (30, 70). The function then continues horizontally to the right.
Enter your value for Uv (in percent) from the table above.
%
Calculate the average degree of consolidation (in percent).
%
Calculate the consolidation settlement (in mm) 50 days after the beginning of the surcharge application.
mm