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Camm, et al - Essentials of Statistics - 10/e (Homework)

James Finch

Statistics, section 2, Fall 2019

Instructor: Dr. Friendly

Current Score : 15 / 121

Due : Sunday, January 27, 2030 23:30 EST

Last Saved : n/a Saving...  ()

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Question
Points
1 2 3 4 5 6 7 8 9
12/12 3/43 –/17 0/5 –/2 –/14 0/14 0/6 –/8
Total
15/121 (12.4%)

  • Instructions

    Drawing from the authors' unmatched experience as professors and consultants, Camm/Cochran/Fry/Ohlmann/Anderson/Sweeney/Williams' market-leading ESSENTIALS OF STATISTICS FOR BUSINESS AND ECONOMICS, 10th Edition, published by Cengage Learning, delivers sound statistical methodology, a proven problem-scenario approach, and meaningful applications that clearly demonstrate how statistical information impacts decisions in actual business practice. More than 350 real business examples, relevant cases, and hands-on exercises present the latest statistical data and business information with unwavering accuracy. Step-by-step instructions for Excel® and R guide students in using this business software for data analysis. An all new WebAssign online course management system is available with this powerful business statistics solution.

    Question 1 is a multipart question that steps the student through the construction of a pie chart and frequency bar chart.

    Question 2 is a case problem that uses summarization tools and techniques to gain insight into a dataset.

    Question 3 features multiple question types and guides students through the process of interpreting values.

    Question 4 asks students to derive a formula and then use that formula to calculate probabilities.

    Question 5 includes an interactive applet to determine the sample size necessary for a given margin of error.

    Question 6 guides the student through a hypothesis test and includes a link to calculate a precise p-value.

    Question 7 showcases a full ANOVA table to complete and then use to perform a hypothesis test.

    Question 8 links to a data set and offers multiple question types for linear regression analysis.

    Question 9 displays grading for multiple regression equations and interpretation of an analysis.

    This demo assignment allows many submissions and allows you to try another version of the same question for practice wherever the problem has randomized values.

    The answer key and solutions will display after the first submission for demonstration purposes. Instructors can configure these to display after the due date or after a specified number of submissions.

Assignment Submission

For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer.

Assignment Scoring

Your last submission is used for your score.

1. 12/12 points  |  Previous Answers ASWESBE10 2.E.003.MI.SA. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12
1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1
2/100 7/100 1/100 1/100 1/100 1/100 1/100 1/100 1/100 1/100 1/100 2/100
Total
12/12
 
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.

Tutorial Exercise
A questionnaire provides 59 Yes, 41 No, and 20 No Opinion answers.
(a)
In the construction of a pie chart, how many degrees would be in the section of the pie showing the Yes answers?
(b)
How many degrees would be in the section of the pie showing the No answers?
(c)
Construct a pie chart.
(d)
Construct a frequency bar chart.
Step 1

(a) In the construction of a pie chart, how many degrees would be in the section of the pie showing the Yes answers?

A pie chart displays categorical data as sections of a circle, called sectors. Pie charts depict the frequency, relative frequency, or percent frequency distribution of a set of data. Each sector will cover an area that corresponds to the relative frequency for each class in the data. Recall that the relative frequencies will always sum to 1. Since there are 360 degrees in a circle, each section will cover an area that is 360(relative frequency) degrees.
Therefore, the relative frequency for the Yes answers is needed here. The relative frequency of the Yes answers is the ratio of the Yes answers to the total sample size. The total sample size can be found by taking the sum of the answers from this questionnaire.
total sample size = Yes + No + No Opinion
 = 59 + 41 + 20
 = 120 Correct: Your answer is correct. seenKey

120
Given that there are 59 Yes answers, find the corresponding relative frequency, leaving your answer as a fraction.
relative frequency = 59/120 Correct: Your answer is correct. seenKey

59/120
Step 2
Now that the relative frequency has been found, we can find the number of degrees in the Yes answers portion of the pie chart by multiplying this value,
59
120
,
 by the number of degrees in a circle, 360.
degrees in Yes portion = 
59
120 Correct: Your answer is correct. seenKey

120
360 degrees
 = 177 Correct: Your answer is correct. seenKey

177

 degrees
Step 3

(b) How many degrees would be in the section of the pie showing the No answers?

As in part (a), first find the relative frequency of the No answers. The sample size was found to be 120, so the relative frequency will be the ratio of the number of No answers to the total sample size. There were 41 No answers. Find this ratio, leaving your answer as a fraction.
relative frequency of No answers = 
number of No answers
total number of answers
 
 = 41/120 Correct: Your answer is correct. seenKey

41/120
Step 4
Now that the relative frequency has been found, we can find the number of degrees in the No answers portion of the pie chart by multiplying this value,
41
120
,
 by the number of degrees in a circle, 360.
degrees in No portion = 
41
120 Correct: Your answer is correct. seenKey

120
360 degrees
 = 123 Correct: Your answer is correct. seenKey

123

 degrees
Step 5

(c) Construct a pie chart.

To create a pie chart, the angle for each sector is needed. Recall there are 360 degrees in a circle. The angle corresponding to a Yes answer was 177, and the angle corresponding to a No answer was 123. Since there are three responses in this questionnaire, the sum of these angles can be subtracted from 360.
degrees in the No Opinion sector = 360 − 
177 + 123 Correct: Your answer is correct. seenKey

123
 degrees
 = 60 Correct: Your answer is correct. seenKey

60

 degrees
Step 6
The pie chart for this data will have a sector of 60 degrees representing the No Opinion answer, a sector of 123 degrees representing the No answer, and a third sector of 177 degrees representing the Yes answer. Construct a pie chart that corresponds to this data.

Correct: Your answer is correct.
Step 7

(d) Construct a frequency bar chart.

A bar chart is another way to display categorical data. As with a pie chart, a bar chart can depict frequency, relative frequency, or percent frequency distribution data.
Place each answer type along the horizontal axis and use frequency along the vertical axis. Each answer type will have its own bar. Since there are 3 types of answers on this questionnaire, there will be 3 Correct: Your answer is correct. seenKey

3

 bars.
The height of each bar will correspond to the frequency of each group. There were 59 Yes answers, 41 No answers, and 20 No Opinion answers. Construct a frequency bar chart corresponding to this data.

Correct: Your answer is correct.
You have now completed the Master It.
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2. 3/43 points  |  Previous Answers ASWESBE10 3.CP.001. My Notes
Question Part
Points
Submissions Used
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0/1 0/1 0/1 0/1 0/1 1/1 1/1 1/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1
1/100 1/100 1/100 1/100 1/100 1/100 1/100 1/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100
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3/43
 
  • Pelican Stores, a division of National Clothing, is a chain of women's apparel stores operating throughout the country. The chain recently ran a promotion in which discount coupons were sent to customers of other National Clothing stores. Data collected for a sample of 100 in-store credit card transactions at Pelican Stores during one day while the promotion was running are contained in the "Given Data" tab below. The proprietary card method of payment refers to charges made using a National Clothing charge card. Customers who made a purchase using a discount coupon are referred to as promotional customers and customers who made a purchase but did not use a discount coupon are referred to as regular customers. Because the promotional coupons were not sent to regular Pelican Stores customers, management considers the sales made to people presenting the promotional coupons as sales it would not otherwise make. Of course, Pelican also hopes that the promotional customers will continue to shop at its stores.
    Most of the variables shown in the data are self-explanatory, but two of the variables require some clarification.
    Items: the total number of items purchased
    Net Sales: the total amount ($) charged to the credit card
    Pelican's management would like to use this sample data to learn about its customer base and to evaluate the promotion involving discount coupons.
  • Use the methods of descriptive statistics presented in this chapter to summarize the data and comment on your findings.
    • Consider the complete data set.
      Customer Type of Customer Items Net Sales Method of Payment Gender Marital Status Age
      1 Regular 1 41.50 Discover Male Married 33
      2 Promotional 1 105.40 Proprietary Card Female Married 37
      3 Regular 1 24.50 Proprietary Card Female Married 33
      4 Promotional 5 102.40 Proprietary Card Female Married 29
      5 Regular 2 56.00 MasterCard Female Married 36
      6 Regular 1 46.50 MasterCard Female Married 46
      7 Promotional 2 81.00 Proprietary Card Female Married 32
      8 Regular 1 25.50 Visa Female Married 42
      9 Promotional 2 59.52 Proprietary Card Female Married 47
      10 Regular 1 47.50 Proprietary Card Female Married 38
      11 Regular 1 32.50 Proprietary Card Female Married 50
      12 Promotional 1 33.60 Proprietary Card Female Married 41
      13 Promotional 9 162.40 Visa Female Married 42
      14 Promotional 2 67.50 Visa Female Married 47
      15 Regular 1 51.50 Visa Male Single 26
      16 Promotional 2 73.40 Proprietary Card Male Single 37
      17 Promotional 3 96.00 Proprietary Card Female Single 24
      18 Regular 3 56.50 Discover Female Married 42
      19 Promotional 2 40.50 MasterCard Female Married 34
      20 Promotional 6 46.80 Proprietary Card Female Married 58
      21 Promotional 1 34.60 Proprietary Card Female Single 30
      22 Promotional 4 72.82 Proprietary Card Female Married 39
      23 Promotional 7 268.00 American Express Female Married 52
      24 Regular 2 76.00 Proprietary Card Female Married 44
      25 Promotional 2 41.50 Visa Male Married 50
      26 Promotional 1 32.02 Proprietary Card Female Married 61
      27 Regular 1 47.50 Proprietary Card Female Married 55
      28 Promotional 5 195.80 Proprietary Card Female Single 43
      29 Promotional 3 74.20 Proprietary Card Female Married 34
      30 Promotional 1 20.00 Proprietary Card Female Married 71
      31 Promotional 2 65.20 MasterCard Female Married 29
      32 Regular 1 77.00 Proprietary Card Female Married 54
      33 Promotional 3 65.20 Proprietary Card Female Married 46
      34 Regular 1 42.00 Proprietary Card Female Married 36
      35 Promotional 5 108.50 MasterCard Female Married 58
      36 Regular 1 32.50 MasterCard Male Single 38
      37 Regular 2 104.50 Visa Female Single 44
      38 Promotional 6 119.50 Proprietary Card Female Married 51
      39 Promotional 5 15.23 Proprietary Card Female Married 45
      40 Regular 2 54.50 Proprietary Card Female Married 59
      41 Promotional 13 200.80 Proprietary Card Female Married 43
      42 Promotional 4 21.50 Visa Female Married 47
      43 Regular 2 126.50 Proprietary Card Female Married 50
      44 Promotional 1 64.40 Proprietary Card Female Married 55
      45 Promotional 2 25.80 Proprietary Card Female Married 40
      46 Promotional 2 42.60 Proprietary Card Female Married 62
      47 Regular 1 28.00 MasterCard Female Married 48
      48 Promotional 3 66.64 Proprietary Card Female Married 31
      49 Promotional 1 17.82 Proprietary Card Female Married 34
      50 Promotional 9 147.20 MasterCard Female Married 48
      51 Promotional 6 178.62 Proprietary Card Female Married 39
      52 Promotional 5 121.80 Proprietary Card Male Married 70
      53 Regular 1 61.00 Discover Female Single 79
      54 Regular 2 77.00 Visa Female Single 22
      55 Regular 2 52.50 MasterCard Female Married 33
      56 Promotional 3 144.60 Proprietary Card Female Married 40
      57 Promotional 6 125.10 Proprietary Card Female Married 55
      58 Promotional 2 83.40 Proprietary Card Female Married 50
      59 Promotional 4 67.20 MasterCard Female Married 47
      60 Promotional 4 116.00 Proprietary Card Female Single 51
      61 Promotional 1 110.80 Proprietary Card Female Married 47
      62 Promotional 3 62.91 Proprietary Card Female Single 31
      63 Promotional 5 55.60 Proprietary Card Female Married 56
      64 Promotional 1 34.60 Proprietary Card Female Single 43
      65 Promotional 2 52.50 Proprietary Card Female Married 49
      66 Promotional 1 42.60 Proprietary Card Female Married 64
      67 Promotional 2 61.50 Proprietary Card Female Married 36
      68 Promotional 5 148.80 Proprietary Card Female Married 30
      69 Promotional 2 49.20 Proprietary Card Male Married 48
      70 Promotional 8 98.05 Proprietary Card Female Married 56
      71 Promotional 5 157.32 Proprietary Card Female Married 31
      72 Promotional 4 60.00 MasterCard Female Married 34
      73 Regular 1 71.00 Proprietary Card Female Single 23
      74 Promotional 2 49.50 Proprietary Card Female Married 33
      75 Promotional 2 47.22 Proprietary Card Female Married 75
      76 Promotional 4 86.74 Proprietary Card Female Married 63
      77 Regular 2 42.00 Proprietary Card Female Married 43
      78 Promotional 4 114.14 Proprietary Card Female Married 30
      79 Promotional 3 88.80 Proprietary Card Female Married 40
      80 Regular 2 92.00 Discover Female Married 56
      81 Promotional 2 81.00 MasterCard Female Married 70
      82 Promotional 6 56.20 Proprietary Card Female Single 31
      83 Promotional 4 61.50 Visa Female Married 37
      84 Promotional 3 49.00 Proprietary Card Female Married 46
      85 Regular 2 40.50 Visa Female Married 46
      86 Promotional 1 23.80 Proprietary Card Female Married 64
      87 Regular 6 146.00 MasterCard Female Single 50
      88 Regular 4 110.00 Proprietary Card Female Married 38
      89 Promotional 1 34.60 Proprietary Card Female Single 21
      90 Promotional 6 60.60 Proprietary Card Female Married 43
      91 Promotional 4 98.20 Proprietary Card Female Married 55
      92 Promotional 1 25.42 Proprietary Card Female Married 56
      93 Regular 5 162.75 Proprietary Card Female Married 74
      94 Promotional 17 231.50 Proprietary Card Female Married 31
      95 Regular 3 68.00 American Express Female Married 48
      96 Regular 1 42.50 MasterCard Female Married 45
      97 Promotional 9 255.00 Proprietary Card Female Married 32
      98 Promotional 10 289.59 Proprietary Card Female Married 53
      99 Promotional 2 49.60 Proprietary Card Female Married 32
      100 Promotional 1 31.44 Proprietary Card Female Married 46
    • Compute the mean, median, range, standard deviation, and skewness of net sales for all customers. (Round the mean, median, range, and standard deviation to two decimal places. Round the skewness to three decimal places.)
      mean $ median $ range standard deviation skewness Incorrect: Your answer is incorrect.
      What observations can be drawn from these descriptive statistics?
      Because the skewness is Correct: Your answer is correct. , the data are Correct: Your answer is correct. . This is also evidenced by the mean being Correct: Your answer is correct. the median.
    • Compute the mean, median, range, standard deviation, and skewness of net sales for married, single, regular, and promotional customers. (Round the mean, median, range, and standard deviation values to two decimal places. Round the skewness values to three decimal places.)
      Married Single Regular Promotional
      Mean $ $ $ $
      Median $ $ $ $
      Range
      Standard Deviation
      Skewness
      What observations can be drawn from these descriptive statistics?
      On average, the most amount was spent by customers and the least amount spent was by customers. Based on the skewness value, the distribution of married customers is . The skewness value of single customers indicates the distribution is . The skewness value of regular customers indicates the distribution is . The skewness value of promotional customers indicates the distribution is . The highest variability for net sales occurred for customers and the least variability for net sales occurred for customers.
    • Compute the sample covariance between age and net sales. (Round your answer to two decimal places.)
      Based on the sample covariance, what can be said about the relationship between age and net sales?
      Because the sample covariance is , there is a linear relationship between the age of a customer and the net sales.
      Compute the sample correlation coefficient between age and net sales. (Round your answer to three decimal places.)
      Based on the sample correlation coefficient, what can be said about the relationship between age and net sales?
      The value of the correlation coefficient implies there is linear relationship between the age of a customer and the net sales.
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3. –/17 points ASWESBE10 4.E.033. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
–/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1
0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100
Total
–/17
 
Students taking a test were asked about their undergraduate major and intent to pursue their MBA as a full-time or part-time student. A summary of their responses follows.
Undergraduate Major Totals
Business Engineering Other
Intended
Enrollment
Status 		Full-Time 350 195 249 794
Part-Time 150 159 195 504
Totals 500 354 444 1,298
(a)
Develop a joint probability table for these data. (Round your answers to three decimal places.)
Undergraduate Major Totals
Business Engineering Other
Intended
Enrollment
Status 		Full-Time
Part-Time
Totals 1.000
(b)
Use the marginal probabilities of undergraduate major (business, engineering, or other) to comment on which undergraduate major produces the most potential MBA students.
From the marginal probabilities, we can tell that majors produce the most potential MBA students.
(c)
If a student intends to attend classes full-time in pursuit of an MBA degree, what is the probability that the student was an undergraduate engineering major? (Round your answer to three decimal places.)
(d)
If a student was an undergraduate business major, what is the probability that the student intends to attend classes full-time in pursuit of an MBA degree? (Round your answer to three decimal places.)
(e)
Let A denote the event that the student intends to attend classes full-time in pursuit of an MBA degree, and let B denote the event that the student was an undergraduate business major. Are events A and B independent? Justify your answer. (Round your answers to three decimal places.)
P(A)P(B)
 = and
P(A ∩ B)
 = , so the events independent.
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4. 0/5 points  |  Previous Answers ASWESBE10 6.E.033. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5
0/1 –/1 –/1 –/1 –/1
1/100 0/100 0/100 0/100 0/100
Total
0/5
 
Consider the following exponential probability density function.
f(x) = 
1
5
e−x/5     for x ≥ 0
(a)
Write the formula for
P(x ≤ x0).
5·3
Incorrect: Your answer is incorrect.
Check the subscript of your variable(s).
(b)
Find
P(x ≤ 3).
 (Round your answer to four decimal places.)
(c)
Find
P(x ≥ 5).
 (Round your answer to four decimal places.)
(d)
Find
P(x ≤ 6).
 (Round your answer to four decimal places.)
(e)
Find
P(3 ≤ x ≤ 6).
 (Round your answer to four decimal places.)
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5. –/2 points ASWESBE10 8.AQ.502. My Notes
Question Part
Points
Submissions Used
1 2
–/1 –/1
0/100 0/100
Total
–/2
 
Use the applet "Sample Size and Interval Width when Estimating Proportions" to answer the following questions.
This applet illustrates how sample size is related to the width of a 95% confidence interval estimate for a population proportion.
(a)
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.023?
(b)
As the sample size decreases for any given confidence level, what happens to the confidence interval?
    
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6. –/14 points ASWESBE10 12.E.004. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14
–/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1
0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100
Total
–/14
 
You may need to use the appropriate technology to answer this question.
Benson Manufacturing is considering ordering electronic components from three different suppliers. The suppliers may differ in terms of quality in that the proportion or percentage of defective components may differ among the suppliers. To evaluate the proportion of defective components for the suppliers, Benson has requested a sample shipment of 500 components from each supplier. The number of defective components and the number of good components found in each shipment are as follows.
Component Supplier
A B C
Defective 20 25 45
Good 480 475 455
(a)
Formulate the hypotheses that can be used to test for equal proportions of defective components provided by the three suppliers.
    
(b)
Using a 0.05 level of significance, conduct the hypothesis test.
Find the value of the test statistic. (Round your answer to three decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
    
(c)
Conduct a multiple comparison test to determine if there is an overall best supplier or if one supplier can be eliminated because of poor quality. Use a 0.05 level of significance. (Round your answers for the critical values to four decimal places.)
Comparison
pi − pj
CVij
 		Significant
Diff > CVij
A vs. B
A vs. C
B vs. C
Can any suppliers be eliminated because of poor quality? (Select all that apply.)

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7. 0/14 points  |  Previous Answers ASWESBE10 13.E.008. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14
0/1 –/1 –/1 –/1 –/1 0/1 –/1 –/1 0/1 –/1 –/1 0/1 0/1 –/1
1/100 0/100 0/100 0/100 0/100 1/100 0/100 0/100 1/100 0/100 0/100 1/100 1/100 0/100
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0/14
 
You may need to use the appropriate technology to answer this question.
A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants.
Plant 1
Atlanta 		Plant 2
Dallas 		Plant 3
Seattle
84 72 58
75 74 64
81 72 63
75 75 69
70 70 75
89 87 61
Sample
mean 		79 75 65
Sample
variance 		48.4 37.6 37.2
Sample
standard
deviation 		6.96 6.13 6.10
Set up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)
Source
of Variation 		Sum
of Squares 		Degrees
of Freedom 		Mean
Square 		F p-value
Treatments Incorrect: Your answer is incorrect.
Error Incorrect: Your answer is incorrect.
Total Incorrect: Your answer is incorrect.
Test for any significant difference in the mean examination score for the three plants. Use
α = 0.05.
State the null and alternative hypotheses.
    
Find the value of the test statistic. (Round your answer to two decimal places.)
Incorrect: Your answer is incorrect.
Find the p-value. (Round your answer to four decimal places.)
p-value = Incorrect: Your answer is incorrect.
State your conclusion.
    
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8. 0/6 points  |  Previous Answers ASWESBE10 14.E.006. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6
–/1 0/1 –/1 –/1 –/1 –/1
0/100 1/100 0/100 0/100 0/100 0/100
Total
0/6
 
Data File Available: Download NFLPassing.xlsx
The National Football League (NFL) records a variety of performance data for individuals and teams. To investigate the importance of passing on the percentage of games won by a team, the following data show the average number of passing yards per attempt (Yards/Attempt) and the percentage of games won (WinPct) for a random sample of 10 NFL teams for the 2011 season.†Source: NFL website, February 12, 2012
Team Yards/Attempt WinPct
Arizona Cardinals 6.5 50
Atlanta Falcons 7.1 63
Carolina Panthers 7.4 38
Chicago Bears 6.4 50
Dallas Cowboys 7.4 50
New England Patriots 8.3 81
Philadelphia Eagles 7.4 50
Seattle Seahawks 6.1 44
St. Louis Rams 5.2 13
Tampa Bay Buccaneers 6.2 25
(a)
Develop a scatter diagram with the number of passing yards per attempt on the horizontal axis and the percentage of games won on the vertical axis.

(b)
What does the scatter diagram developed in part (a) indicate about the relationship between the two variables?
     Incorrect: Your answer is incorrect.
(c)
Develop the estimated regression equation that could be used to predict the percentage of games won given the average number of passing yards per attempt. (Round your numerical values to three decimal places.)
ŷ =
(d)
Provide an interpretation for the slope of the estimated regression equation.
    
(e)
For the 2011 season, suppose the average number of passing yards per attempt for a certain NFL team was 6.4. Use the estimated regression equation developed in part (c) to predict the percentage of games won by that NFL team. (Note: For the 2011 season, suppose this NFL team's record was seven wins and nine losses. Round your answer to the nearest integer.)
%
Compare your prediction to the actual percentage of games won by this NFL team.
    
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9. –/8 points ASWESBE10 15.E.035. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8
–/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1
0/100 0/100 0/100 0/100 0/100 0/100 0/100 0/100
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–/8
 
A statistical program is recommended.
A company provides maintenance service for water-filtration systems throughout southern Florida. Customers contact the company with requests for maintenance service on their water-filtration systems. To estimate the service time and the service cost, the company's managers want to predict the repair time necessary for each maintenance request. Hence, repair time in hours is the dependent variable. Repair time is believed to be related to three factors, the number of months since the last maintenance service, the type of repair problem (mechanical or electrical), and the repairperson who performed the service. Data for a sample of 10 service calls are reported in the table below.
Repair Time
in Hours 		Months Since
Last Service 		Type of Repair Repairperson
2.9 2 Electrical Dave Newton
3.0 6 Mechanical Dave Newton
4.8 8 Electrical Bob Jones
1.8 3 Mechanical Dave Newton
2.9 2 Electrical Dave Newton
4.9 7 Electrical Bob Jones
4.7 9 Mechanical Bob Jones
4.8 8 Mechanical Bob Jones
4.4 4 Electrical Bob Jones
4.5 6 Electrical Dave Newton
(a)
Ignore for now the months since the last maintenance service
(x1)
 and the repairperson who performed the service. Develop the estimated simple linear regression equation to predict the repair time
(y)
 given the type of repair
(x2).
 Let
x2 = 0
 if the type of repair is mechanical and
x2 = 1
 if the type of repair is electrical. (Round your numerical values to three decimal places.)
ŷ =
(b)
Does the equation that you developed in part (a) provide a good fit for the observed data? Explain. (Round your answer to two decimal places.)
We see that % of the variability in the repair time has been explained by the type of repair. Since this is 55%, the estimated regression equation a good fit for the observed data.
(c)
Ignore for now the months since the last maintenance service and the type of repair associated with the machine. Develop the estimated simple linear regression equation to predict the repair time given the repairperson who performed the service. Let
x3 = 0
 if Bob Jones performed the service and
x3 = 1
 if Dave Newton performed the service. (Round your numerical values to three decimal places.)
ŷ =
(d)
Does the equation that you developed in part (c) provide a good fit for the observed data? Explain. (Round your answer to two decimal places.)
We see that % of the variability in the repair time has been explained by the repairperson. Since this is 55%, the estimated regression equation a good fit for the observed data.
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