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Goodno & Gere - Mechanics of Materials (SI) 9/e (Homework)

James Finch

Engineering, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 35 / 37

Due : Sunday, January 27, 2030 12:00 EST

Last Saved : n/a Saving...  ()

Question
Points
1 2 3 4 5 6 7 8 9 10 11
18/18 3/3 2/2 1/1 0/1 3/3 1/1 2/3 1/1 2/2 2/2
Total
35/37 (94.6%)
  • Instructions

    Give students a rigorous, complete, and integrated treatment of the mechanics of materials—an essential subject in mechanical, civil, and structural engineering. The enhanced ninth edition of Goodno/Gere's Mechanics of Materials, SI edition, published by Cengage Learning, examines the analysis and design of structural members subjected to tension, compression, torsion, and bending—laying the foundation for further study. Available via WebAssign is MindTap Reader, Cengage's next-generation eBook, and other digital resources.

    Question 1 is an Active Example. Active Examples build a bridge between practice and homework through helpful Examples from the textbook that guide students through the process needed to master a concept and include worked-out solutions.

    In Question 2 the maximum normal strain εmax is determined for a steel wire bent around a cylindrical drum.

    Question 3 calculates the maximum bending stress σmax of a simply supported wood beam (linearly elastic material).

    In Question 4 students select a suitable size for a simply supported wood beam subjected to unsymmetrical point loads.

    Question 5 shows how the manner in which the bending stresses vary along the axis of a nonprismatic beam is not the same as for a prismatic beam.

    Question 6 determines the normal stress and the shear stress at point C when a simply supported wood beam is subjected to a uniformly distributed load q.

    Question 7 asks for the maximum shear stress in a pole consisting of a circular tube loaded by a linearly varying distributed force.

    Question 8 determines the maximum permissible load q of a bridge girder constructed of three plates welded to form a cross section.

    Question 9 determines the maximum allowable shear force Vmax for a prefabricated wood I-beam serving as a floor joist with a cross section.

    Question 10 uses weight and wind force to determine the maximum tensile and compressive stresses σt and σc, respectively, of an aluminum pole (at its base) for a street light.

    Question 11 uses the dimensions of a rectangular beam with notches and a hole, along with the bending moment and the maximum allowable bending stress in the material (steel), to calculate the smallest radius Rmin that should be used in the notches, and the diameter dmax of the largest hole that should be drilled at the mid-height of the beam. This demo assignment allows many submissions and allows you to try another version of the same question for practice wherever the problem has randomized values.

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1. 18/18 points  |  Previous Answers GGMechMat9SI 5.AE.007. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1
2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100 2/100
Total
18/18
 

Design of Beams for Bending Stresses

  • A simple beam AB of span length 7 m must support a uniform load
    q = 60 kN/m
    distributed along the beam in the manner shown in the figure below.
    Design of a Simple Beam with Partial Uniform Loads
    A horizontal beam AB is supported at its left end A by a pin support and at its right end B by a roller support. Two uniformly distributed loads with intensity q = 60 kN/m act downwards on the beam. One load begins at A and extends rightwards 4 m. The other load begins at B and extends leftwards 2 m, leaving a 1 m segment without a load. Reaction force RA acts upwards at A and reaction force RB acts upwards at B.
    Considering both the uniform load and the weight of the beam, select a structural steel beam of wide-flange shape to support the loads. Use an allowable bending stress of 111 MPa.
    • Use a four-step problem-solving approach. Combine steps as needed for an efficient solution.
      • In this example, proceed as follows.
        1. Find the maximum bending moment in the beam due to the uniform load.
        2. Knowing the maximum moment, find the required section modulus.
        3. Select a trial wide-flange beam from this table and obtain the weight of the beam.
        4. With the weight known, calculate a new value of the bending moment and a new value of the section modulus.
        Determine whether the selected beam is still satisfactory. If it is not, select a new beam size and repeat the process until you find a satisfactory size of beam.
        Maximum Bending Moment
        To assist in locating the cross section of the maximum bending moment, construct the shear-force diagram (see figure below) using the methods described in Chapter 4. As part of that process, determine the reactions at the supports, as follows.
        A shear diagram depicts V (kN). V starts at 188.6 and goes down and right linearly to zero a horizontal distance x1 to the right of the beginning. V continues down and right with the same slope to 51.4, extends horizontally rightwards a short distance, then continues down and right linearly to 171.4.
        RA = 188.6 kN      RB = 171.4 kN
        Find the distance
        x1
        from the left-hand support to the cross section of zero shear force from
        V = RA qx1 = 0,
        which is valid in the range 0 x 4 m. Solve for
        x1
        to get
        x1
        RA
        q
         = 
        188.6 kN
        60 kN/m
         = 3.14 m,
        which is less than 4 m. Therefore, the calculation is valid. The maximum bending moment occurs at the cross section where the shear force is zero. Therefore, we get the following.
        Mmax = RAx1  
        qx12
        2
         = 296.3 kN · m
      • Required Section Modulus
        Find the required section modulus (based only upon the load q) as obtained from the equation
        S
        Mmax
        σallow
        ,
        as follows.
        S
        Mmax
        σallow
         = 
        (296.3 106 N · mm)
        111 MPa
         = 2.670 106 mm3
        Trial Beam
        Now consider this table and select the lightest wide-flange beam having a section modulus greater than 2,670 cm3. The lightest beam that provides this section modulus is HE 450A with
        S = 2,896 cm3.
        This beam weighs 140 kg/m, or 1.373 kN/m. (Recall that the tables in the above links are abridged, so a lighter beam may actually be available.)
        Now recalculate the reactions, the maximum bending moment, and the required section modulus with the beam loaded by both the uniform load q and its own weight. Under these combined loads, the reactions are
        RA = 193.4 kN      RB = 176.2 kN,
        and the distance to the cross section of zero shear becomes the following.
        x1
        193.4 kN
        (60 kN/m + 1.373 kN/m)
         = 3.151 m
        The maximum bending moment increases to 304.7 kN · m, and the new required section modulus is as follows.
        S
        Mmax
        σallow
         = 
        (304.7 106 N · mm)
        111 MPa
         = 2,739 cm3
      • Thus, the HE 450A beam with section modulus
        S = 2,896 cm3
        is still satisfactory.
        Note: If the new required section modulus exceeded that of the HE 450A beam, you would select a new beam with a larger section modulus and repeat the design process.
    • A steel wide flange beam was selected in this design example (HE 450A, see figure below).
      A cross section of an I beam has a vertical web and horizontal flanges. A horizontal line through the midpoint of the web is axis 11. A vertical line through the midpoint of the web is axis 22. The distance from the top of the beam to the bottom is 440 mm.
      Now consider three additional designs for the cross section of this steel beam. We have rectangular (see figure below),
      The cross section of a beam is a rectangle of height h and width h4.
      circular (see figure below),
      The cross section of a beam is a circle of diameter d.
      and cruciform (see figure below).
      The cross section of a beam is a symmetric cruciform. Each face extends outwards a distance b4 and has a width of b2 centered on the midpoint of the respective face. The maximum height and width are both 4 (b4) = b.
      (i)
      Find the cross section dimension (in centimeters) for each (h for rectangle, d for circle, b for cruciform) so that each has the same cross sectional area as the HE 450A beam used in the example
      (Ax = 178 cm2).
      [Note: each of the four beams has the same area and so also has the same weight per meter,
      m = 140 kg/m or 1.373 kN/m].
      Use known area formulas for each cross section shape.
      rectangle h = Correct: Your answer is correct. seenKey

      26.7

      cm
      circle d = Correct: Your answer is correct. seenKey

      15.1

      cm
      cruciform b = Correct: Your answer is correct. seenKey

      15.4

      cm
      (ii)
      Compute the section modulus S (cm3) about a horizontal centroidal axis for each beam (rectangle
      SR,
      circle
      SC,
      cruciform
      SCr).
      [Recall that
      SW = 2,896 cm3
      for the HE 450A beam].
      Expect the section modulus values for rectangular, circular and cruciform cross sections to be much less than that for the HE shape. Recall that a wide flange shape has its material located as far as practical from the neutral axis so it is the most efficient design among the four shapes considered here.
      SR = Correct: Your answer is correct. seenKey

      792

      cm3
      SC = Correct: Your answer is correct. seenKey

      335

      cm3
      SCr = Correct: Your answer is correct. seenKey

      343

      cm3
      Find ratios
      SR
      SW
      ,
      SC
      SW
      ,
      and
      SCr
      SW
      .
      SR
      SW
      = Correct: Your answer is correct. seenKey

      0.273

      SC
      SW
      = Correct: Your answer is correct. seenKey

      0.116

      SCr
      SW
      = Correct: Your answer is correct. seenKey

      0.118

      Which beams are the most and second most economical? (Recall that the most economical beam is the one having the largest capacity-to-weight ratio.)
      most economical Correct: Your answer is correct. seenKey

      HE 450A

      second most economical Correct: Your answer is correct. seenKey

      rectangle

      (iii)
      What is the maximum moment (Mmax, kN · m) that each beam can carry? Recall that the allowable bending stress for each steel beam is
      σa = 111 MPa.
      (Enter the magnitudes.)
      From the example, the HE 450A beam has moment capacity that exceeds 296 kN · m. Expect the capacities of the rectangle, circle and cruciform shape beams to be much less.
      HE 450A Mmax = Correct: Your answer is correct. seenKey

      321

      kN · m
      rectangle Mmax = Correct: Your answer is correct. seenKey

      87.9

      kN · m
      circle Mmax = Correct: Your answer is correct. seenKey

      37.2

      kN · m
      cruciform Mmax = Correct: Your answer is correct. seenKey

      38

      kN · m
    • Considering both the uniform load q (see the figure below) and the weight of the beam, and also using an allowable bending stress of 111 MPa, find the minimum dimensions of each of the three alternative steel beams to support the loads (both applied load q and self-weight
      w = γA).
      A horizontal beam AB is supported at its left end A by a pin support and at its right end B by a roller support. Two uniformly distributed loads with intensity q = 60 kN/m act downwards on the beam. One load begins at A and extends rightwards 4 m. The other load begins at B and extends leftwards 2 m, leaving a 1 m segment without a load. Reaction force RA acts upwards at A and reaction force RB acts upwards at B.
      To begin, use
      Mmax = 296.3 kN · m
      (based on distributed load q alone), then include the distributed weight w (kN/m) of each beam. Recall that the weight density of steel is
      γ = 77.0 kN/m3
      (see this table).
      Equate the section modulus S formula for each of the rectangular, circular, and cruciform cross sections to the required section modulus, then solve for the minimum required dimension for each shape.
      (i)
      Find the minimum height h (in centimeters) for a rectangular cross section (
      h
      4
      by h, see figure below).
      The cross section of a beam is a rectangle of height h and width h4.
      Correct: Your answer is correct. seenKey

      40.9

      cm
      (ii)
      Find the minimum diameter d (in centimeters) for a circular cross section (see figure below).
      The cross section of a beam is a circle of diameter d.
      Correct: Your answer is correct. seenKey

      31.2

      cm
      (iii)
      Find the minimum dimension b (in centimeters) for a cruciform cross section (see figure below).
      The cross section of a beam is a symmetric cruciform. Each face extends outwards a distance b4 and has a width of b2 centered on the midpoint of the respective face. The maximum height and width are both 4 (b4) = b.
      Correct: Your answer is correct. seenKey

      31.7

      cm


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2. 3/3 points  |  Previous Answers GGMechMat9SI 5.4.001. My Notes
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3/3
 
A steel wire with a diameter of d = 2.3 mm is bent around a cylindrical drum with a radius of R = 1.2 m. (see figure).
A wire of diameter d bends part way around a cylinder of radius R.
(a)
Determine the maximum normal strain εmax.
εmax = Correct: Your answer is correct. seenKey

0.000957

(b)
What is the minimum acceptable radius of the drum (in m) if the maximum normal strain must remain below yield? Assume E = 245 GPa and σY = 690 MPa.
Correct: Your answer is correct. seenKey

0.407

m
(c)
If R = 1.2 m, what is the maximum acceptable diameter of the wire (in mm) if the maximum normal strain must remain below yield?
Correct: Your answer is correct. seenKey

6.78

mm
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A simply supported wood beam AB with a span length
L = 4 m
carries a uniform load of intensity
q = 4.7 kN/m
(see Figure (a) below).
Two figures depict a simply supported wood beam of length L, each carrying a different load. The beam has a pin support on the left end at point A and a roller support on the right end at point B. The cross section of the beam has width b and height h > b.
  • Figure (a). The beam carries a uniform load of intensity q.
  • Figure (b). The beam carries a trapezoidal distributed load where the intensity at the left end is q/2 and the intensity at the right end is q.
(a)
Calculate the maximum bending stress σmax (in MPa) for Figure (a) due to the load q if the beam has a rectangular cross section with width
b = 160 mm
and height
h = 220 mm.
Correct: Your answer is correct. seenKey

7.28

MPa
(b)
Repeat part (a) but use the trapezoidal distributed load shown in Figure (b). (Enter the maximum bending stress σmax in MPa.)
Correct: Your answer is correct. seenKey

5.48

MPa
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A simply supported wood beam having a span length L = 3.6 m is subjected to unsymmetrical point loads, as shown in the figure.
A simply supported wood beam carries two point loads separated by 1.2 m. Point load P1 = 11 kN acts 1.2 m from the left end of the beam and point load P2 = 14 kN acts 1.2 m from the right end of the beam.
Select a suitable size for the beam using the table in Appendix G. The allowable bending stress is 12 MPa and the wood weighs 560 kg/m3.
     Correct: Your answer is correct.
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The following problem pertains to fully stressed beams of rectangular cross section. Consider only the bending stresses obtained from the flexure formula and disregard the weights of the beams.
A cantilever beam AB with rectangular cross sections of a constant width b and varying height
hx
is subjected to a uniform load of intensity q (see figure).
A cantilever beam of horizontal length L is shaped like an isosceles triangle with two long sides and one short side. The short, right side of the beam is attached to a vertical wall and has height hB. Point A is at the left vertex of the beam and point B is at the top right corner of the beam. At a distance x to the right of point A, the beam has height hx < hB.
Above the beam, a uniform load labeled q acts vertically downward along the entire length of the beam.
Two rectangular cross sections are shown of the beam. One has height hx and width b. The other has height hB and width b.
How should the height
hx
vary as a function of x (measured from the free end of the beam) in order to have a fully stressed beam? (Express
hx
in terms of the height
hB
at the fixed end of the beam. Use the following as necessary: hB, x, and L.)
hx =
χhBL
Incorrect: Your answer is incorrect. webMathematica generated answer key
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A simply supported wood beam is subjected to uniformly distributed load q. The width of the beam is 150 mm and the height is 200 mm.
A 4 m long, horizontal, rectangular wood beam is supported under its left end by pin support A and under its right end by roller support B. Point C is located 1 m to the right of its left end and 75 mm below the top of the beam. A uniformly distributed load q = 3.9 kN/m acts downward on the top of the beam, along the entire length of the beam.
A rectangular cross-sectional view of the end of the beam shows that the +y-axis points up and the +z-axis points to the left, where the origin O is in the center of the cross-section. It has height 200 mm along the y-direction and width 150 mm along the z-direction.
Determine the normal stress and the shear stress at Point C. (Enter your answers in MPa. Assume the +x-axis points to the right from A. Indicate the direction with the signs of your answers.)
normal stress Correct: Your answer is correct. seenKey

-1.46

MPa
shear stress Correct: Your answer is correct. seenKey

-0.183

MPa
Show these stresses on a sketch of a stress element at Point C.

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A vertical pole consisting of a circular tube of outer diameter 121 mm and inner diameter 107 mm is loaded by a linearly varying distributed force with maximum intensity of
q0.
A tall, vertically-oriented cylinder has a height of 3 m, inner diameter d1, and outer diameter d2. A linearly varying distributed force acts rightward on the left side of the cylinder. The maximum value q0 = 6.2 kN/m acts at the bottom of the cylinder, and q linearly decreases to a value of zero acting at the top of the cylinder.
Find the maximum shear stress in the pole. (Enter your answer in MPa. Indicate the direction with the sign of your answer.)
Correct: Your answer is correct. seenKey

7.4

MPa
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A bridge girder AB on a simple span of length
L = 32 m
supports a distributed load of maximum intensity q at mid-span and minimum intensity
q/2
at supports A and B that includes the weight of the girder (see figure).
Two diagrams of a bridge girder are shown.
In the first diagram, the bridge girder and supports are viewed from the side, with the full length L = 32 m of the girder spanning from pin support A on the left to roller support B on the right. A distributed load is represented by many arrows above the girder pointing vertically down toward the girder. The greatest load is at the center of the girder and labeled q. The least load is found at either end of the girder and labeled q2. The load increases linearly from either end of the girder to the center of the girder.
In the second diagram, the cross section of a wide flange beam is shown. The beam has a shape similar to a capital I, with a narrow vertical web and wide horizontal flanges above and below the web. The horizontal width of each flange is 450 mm, and the vertical thickness of each flange is 32 mm. The horizontal width of the web is 16 mm, and the vertical height of the web, from the point where it meets the top face of the bottom flange to the point where it meets the bottom face of the top flange, is 1800 mm.
The girder is constructed of three plates welded to form the cross section shown. Determine the maximum permissible load q (in kN/m) based upon the following.
(a)
solely based on an allowable bending stress
σallow = 110 MPa
Incorrect: Your answer is incorrect. seenKey

35.3

kN/m
(b)
solely based on an allowable shear stress
τallow = 50 MPa
Correct: Your answer is correct. seenKey

108

kN/m
(c)
accounting for both an allowable bending stress σallow and an allowable shear stress τallow
Correct: Your answer is correct. seenKey

35.3

kN/m
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A prefabricated wood I-beam serving as a floor joist has the cross section shown in the figure.
The cross section of a wood I-beam is composed of a long vertical web capped on its top and bottom with shorter horizontal flanges, which are centered above and below the web. The origin O is in the center of the cross section, where the +y-axis points up and the +z-axis points to the left. The dimensions of each component of the beam are as follows.
  • The web has height 170 mm and width 15 mm.
  • Each flange has height 24 mm and width 130 mm.
The allowable load in shear for the glued joints between the web and the flanges is 11 kN/m in the longitudinal direction. Determine the maximum allowable shear force Vmax for the beam. (Enter the magnitude in N.)
Correct: Your answer is correct. seenKey

2370

N
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An aluminum pole for a street light weighs 4,400 N and supports an arm that weighs 590 N (see figure).
Two diagrams of an aluminum pole are shown.
In the first diagram, the pole is upright and extends upward from the base on the ground. The weight of the pole is W1 = 4,400 N. At the top of the pole, an arm extends up and to the left to end at a lamp. The weight of the arm is W2 = 590 N, and this weight acts at the center of gravity of the arm at a distance of 1.2 m to the left of the pole. A wind force of P1 = 250 N pushes on the pole to the left at a height of 9 m above the base. The +x-direction points out of the page, the +y-direction points to the right, and the +z-direction points upward.
In the second diagram, a cross section of the pole is seen from above. The cross section is a cylindrical shell with outer diameter 225 mm and thickness 18 mm. The +x-direction points downward and the +y-direction points to the right.
The center of gravity of the arm is 1.2 m from the axis of the pole. A wind force of 250 N also acts in the
(y)
direction at 9 m above the base. The outside diameter of the pole (at its base) is 225 mm, and its thickness is 18 mm.
Determine the maximum tensile and compressive stresses
σt
and
σc,
respectively, in the pole (at its base) due to the weights and the wind force. (Enter your answers in kPa. Include the signs of the values in your answers.)
maximum tensile stress σt = Correct: Your answer is correct. seenKey

4840

kPa
maximum compressive stress σc = Correct: Your answer is correct. seenKey

-5690

kPa
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A rectangular beam with notches and a hole (see figure) has dimensions
h = 132 mm,
h1 = 120 mm,
and thickness
b = 129 mm
(perpendicular to the plane of the figure).
A rectangular beam with vertical height h extends from left to right. Two curved arrows, one to the left of the beam and one to the right, are labeled M and curve up and away, then up and toward the beam. Four notches and a hole of diameter d are bored through the beam and into the page. One notch is U-shaped: the bottom of the notch is similar to the bottom of a U, and this bottom is below the top-front edge of the beam. The beam is bored above the bottom of the notch into the page, and the horizontal width of the top of the U-shaped notch is 2R. The notch is some distance to the right of the top-left corner of the front and back faces.
  • A second notch forms a similar arc and similar bore at an equal distance to the left of the top-right corner.
  • A third notch is shaped like an inverted U: the top of the notch is similar to the top of an inverted U, and this top is above the bottom-front edge of the beam. The beam is bored below the top of the notch into the page, and the horizontal width of the bottom of the inverted U is 2R. The notch is some distance to the right of the bottom-left corner of the front and back faces.
  • A fourth notch forms a similar arc and similar bore at an equal distance to the left of the bottom-right corner.
The bottommost point of each notch along the top edge and the topmost point of the nearest notch along the bottom edge are separated by a vertical distance h1.
The beam is subjected to a bending moment
M = 45 kN · m,
and the maximum allowable bending stress in the material (steel) is
σmax = 290 MPa.
(a)
What is the smallest radius Rmin (in mm) that should be used in the notches? (Use any necessary data found in this figure.)
Correct: Your answer is correct. seenKey

13.2

mm
(b)
What is the diameter dmax (in mm) of the largest hole that should be drilled at the midheight of the beam?
Assume
that the ratio
d
h
 > 
1
2
.
Correct: Your answer is correct. seenKey

96.7

mm
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