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Larson - Precalculus with Limits for HS 4/e (Homework)

James Finch

Math - High School, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 15 / 17

Due : Friday, August 16, 2019 20:00 EDT

Last Saved : n/a Saving...  ()

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Question
Points
1 2 3 4 5 6 7 8 9
–/1 –/1 –/1 –/2 –/1 –/4 –/3 –/1 –/3
Total
15/17 (88.2%)

  • Instructions

    Precalculus with Limits, 4th edition (High School Edition), written by Ron Larson and published by Cengage Learning, delivers the same sound explanations and exercises as the market-leading Precalculus, with a laser focus on preparation for calculus. Limits includes a brief algebra review of core topics, coverage of analytic geometry in three dimensions, and an introduction to concepts covered in calculus and is ideal for a two-term course. The WebAssign component for this title engages students with many features, and links to a complete eBook.

    Question 1 grades all solutions written as a list. The prompt alerts the student to enter a comma-separated list of answers.

    Question 2 contains expression grading where any equivalent form of the expression is accepted. Also included are a Master It tutorial, Watch It, and solution.

    Question 3 enforces that the answer is written as a complex number and includes a Watch It.

    Question 4 demonstrates grading for factored expressions in the first answer blank. Also included are a Master It tutorial, Watch It, and solution.

    Question 5 highlights grading used for an expanded logarithm per the question instructions.

    Question 6 is a multi-part question which shows one of many prompts used to indicate to the student what to enter when there is no answer.

    Question 7 requires the evaluations of the the sine, cosine, and tangent of the angle to be entered in simplest form.

    Question 8 features an image with a randomized value in addition to equation grading, which allows any equivalent form of the requested equation.

    Question 9 exhibits an expandable matrix answer blank that grades the matrix as a whole, and also handles answers for matrices that cannot be computed. Also included are a Master It tutorial, Watch It, and solution. This demo assignment allows many submissions and allows you to try another version of the same question for practice wherever the problem has randomized values.

    The answer key and solutions will display after the first submission for demonstration purposes. Instructors can configure these to display after the due date or after a specified number of submissions.

Assignment Submission

For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer.

Assignment Scoring

Your last submission is used for your score.

1. –/1 points LarPCalcLim4HS 1.5.024. My Notes
Question Part
Points
Submissions Used
1
–/1
0/100
Total
–/1
 
Find the zeros of the function algebraically. (Enter your answers as a comma-separated list.)
f(x) = 9x3 − 36x2 − x + 4
x = (No Response) webMathematica generated answer key
Your work in question(s) will also be submitted or saved.
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2. –/1 points LarPCalcLim4HS 1.7.044.MI. My Notes
Question Part
Points
Submissions Used
1
–/1
0/100
Total
–/1
 
Write an equation for the function described by the given characteristics.
The shape of
f(x) = |x|,
 but shifted five units to the left and eight units down
g(x) = (No Response) abs(x + 5) - 8

Solution or Explanation
f(x) = |x| moved 5 units to the left and 8 units down

g(x) = |x + 5| − 8

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3. –/1 points LarPCalcLim4HS 2.4.012. My Notes
Question Part
Points
Submissions Used
1
–/1
0/100
Total
–/1
 
Write the complex number in standard form.
3 + 
−64
(No Response) webMathematica generated answer key

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4. –/2 points LarPCalcLim4HS 2.5.064.MI. My Notes
Question Part
Points
Submissions Used
1 2
–/1 –/1
0/100 0/100
Total
–/2
 
Write the polynomial as the product of linear factors.
g(x) = x2 + 10x + 20
g(x) = (No Response) webMathematica generated answer key


List all the zeros of the function. (Enter your answers as a comma-separated list.)
x = (No Response) webMathematica generated answer key


Solution or Explanation
g(x) = x2 + 10x + 20


By the Quadratic Formula, the zeros of g(x) are as follows.
x = 
−10 ± 
100 − 80
2
 = 
−10 ± 
20
2
 = −5 ± 
5
 

g(x) = (x + 5 + 
5
)(x + 5 − 
5
)

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5. –/1 points LarPCalcLim4HS 3.3.049. My Notes
Question Part
Points
Submissions Used
1
–/1
0/100
Total
–/1
 
Use the properties of logarithms to expand the expression as a sum, difference, and/or constant multiple of logarithms. (Assume all variables are positive.)
ln xyz8
(No Response) webMathematica generated answer key
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6. –/4 points LarPCalcLim4HS 4.1.032. My Notes
Question Part
Points
Submissions Used
1 2 3 4
–/1 –/1 –/1 –/1
0/100 0/100 0/100 0/100
Total
–/4
 
Find (if possible) the complement and supplement of each angle. (If not possible, enter IMPOSSIBLE.)
(a)    50°
complement     (No Response) seenKey

40

 °
supplement     (No Response) seenKey

130

 °

(b)     170°
complement     (No Response) seenKey

IMPOSSIBLE

 °
supplement     (No Response) seenKey

10

 °



Solution or Explanation
(a) Complement:90° − 50° = 40°
Supplement:180° − 50° = 130°
(b) Complement: Not possible, 170° is greater than 90°
     Supplement:180° − 170° = 10°

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7. –/3 points LarPCalcLim4HS 4.4.061. My Notes
Question Part
Points
Submissions Used
1 2 3
–/1 –/1 –/1
0/100 0/100 0/100
Total
–/3
 
Evaluate the sine, cosine, and tangent of the angle without using a calculator. (If an answer is undefined, enter UNDEFINED.)
2π
3
sin θ = (No Response) webMathematica generated answer key
cos θ = (No Response) webMathematica generated answer key
tan θ = (No Response) webMathematica generated answer key
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8. –/1 points LarPCalcLim4HS 4.8.050. My Notes
Question Part
Points
Submissions Used
1
–/1
0/100
Total
–/1
 
A buoy oscillates in simple harmonic motion as waves go past. The buoy moves a total of 3.5 feet from its low point to its high point (see figure), and it returns to its high point every 16 seconds. Write an equation that describes the motion of the buoy if its high point is at t = 0, in terms of its height h.
(No Response) webMathematica generated answer key

3.5 ft


Solution or Explanation
At t = 0, buoy is at its high point  right double arrow implies  h = a cos(ωt).
Distance from high to low = 2|a| = 3.5
|a| = 
7
4
Returns to high point every 16 seconds:
Period: 
2π
ω
 = 16  right double arrow implies  ω = 
π
8
 
h = 
7
4
 cos
πt
8
 

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9. –/3 points LarPCalcLim4HS 8.2.036.MI. My Notes
Question Part
Points
Submissions Used
1 2 3
–/1 –/1 –/1
0/100 0/100 0/100
Total
–/3
 
If possible, find AB and state the order of the result. (If not possible, enter IMPOSSIBLE.)
A = 
0−12
605
7−16
,    B = 
4−1
2−5
16
AB =
seenKey

[0, 17; 29, 24; 32, 34]

State the order of the result. (If not possible, enter IMPOSSIBLE in both answer blanks.)
(No Response) seenKey

3

 × (No Response) seenKey

2

Solution or Explanation
A is 3 × 3, B is 3 × 2 right double arrow implies AB is 3 × 2.
A = 
0−12
605
7−16
,    B = 
4−1
2−5
16
AB = 
0−12
605
7−16
4−1
2−5
16
 = 
017
2924
3234

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