WebAssign is not supported for this browser version. Some features or content might not work. System requirements

WebAssign

Welcome, demo@demo

(sign out)

Tuesday, April 1, 2025 05:11 EDT

Home My Assignments Grades Communication Calendar My eBooks

Serway & Jewett - Physics for S&E Tech Update 9/e (Homework)

James Finch

Physics - College, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 19 / 78

Due : Monday, January 28, 2030 00:00 EST

Last Saved : n/a Saving...  ()

Question
Points
1 2 3 4 5 6 7 8 9 10 11 12
9/20 0/15 –/1 4/8 1/15 –/2 1/1 –/2 –/1 1/6 1/5 2/2
Total
19/78 (24.4%)
  • Instructions

    Create your course assignments by selecting questions from our bank of end-of-section exercises, enhanced interactive examples and tutorials.

    While doing their homework, students can link to the relevant interactive examples from the book and work through them again and again for additional practice before answering the question.

    Read It - Every problem includes a link to the appropriate section of a complete interactive eBook.

    Master It - Select problems feature a detailed Master It tutorial, guiding students through prompted steps to solve the specific problem.

    Watch It Students can view 2--5-minute narrated Watch It videos, recorded by Physics instructors to help students solve select problems.

    In this assignment we present several textbook question types found in Chapter 5 on The Laws of Motion in Physics for Scientists and Engineers Technology Update 9/e by Raymond A. Serway and John W. Jewett, Jr., published by Cengage Learning.

    Enhanced for This Technology Update
    Question 1 is an Integrated Tutorial question. It strengthens students' skills by guiding them through the problem-solving steps identified in their textbook. Tutorials take students through the process, asking questions they will learn to ask themselves when faced with new problems.

    Enhanced for This Technology Update
    Question 2 is a PreLecture Exploration. Using HTML5 interactive simulations, students can make predictions, change parameters, and observe results. Each PreLecture Exploration presents an engaging simulation based on a relevant scenario and then asks conceptual and analytic questions, guiding students to a deeper understanding and helping promote a robust physical intuition. This is the perfect resource for a flipped classroom or for professors looking for new ways to increase student engagement and interest in the material prior to lecture.

    Enhanced for This Technology Update
    Question 3 is a problem with a complete solution. Hundreds of end-of-chapter problems include fully worked out solutions to help students better understand problem-solving strategies as applied to specific problems.

    Question 4 is an Active Example which guides students through the process needed to master a concept. A "Master It" question at the end provides a twist on the in-text Example to test student understanding.

    Question 5 is an Analysis Model Tutorial problem, which guides students through every step of the problem-solving process, driving them to see the important link between the situation in the problem and the mathematical representation of the situation.

    Question 6 is a Conceptual Question, designed to help students test their understanding of physical concepts as they work through each chapter.

    Question 7 is an Objective Question.

    Question 8 is a Master It problem with a complete tutorial.

    Questions 9, 10, and 11 are traditional end-of-chapter problems with symbolic answer entry.

    Question 12 is a problem with a Watch It video.

    Click here for a list of all of the questions coded in WebAssign. This demo assignment allows many submissions and allows you to try another version of the same question for practice wherever the problem has randomized values.

    The answer key and solutions will display after the first submission for demonstration purposes. Instructors can configure these to display after the due date or after a specified number of submissions.

Assignment Submission

For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer.

Assignment Scoring

Your last submission is used for your score.

1. 9/20 points  |  Previous Answers SerPSET9 5.IT.002. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
1/1 1/1 1/1 1/1 1/1 1/1 1/1 0/1 /1 1/1 /1 0/1 1/1 /1 /1 /1 /1 /1 /1 /1
2/50 2/50 2/50 2/50 1/50 1/50 1/50 1/50 0/50 1/50 0/50 1/50 1/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
9/20
 
Integrated Tutorial
On April 23, 2002, a passenger train about 35 miles outside of Los Angeles was hit by a freight train. The accident killed two and injured more than 260 people on the passenger train. News reports said that the passenger train came to a complete stop before the collision, and afterward the two trains were locked together moving in the freight train's original direction.

Some people believe the force on the passenger train could have been reduced and perhaps eliminated if it had sped up so that its speed matched that of the freight train instead of stopping before the collision. In this problem we explore that possibility by considering a head-on collision between two particles in two different cases:
Case 1: if particle B was at rest before the collision, and
Case 2: if particle B was moving toward particle A with a speed equal to that of particle A.
In both cases, before the collision particle A is moving at 26.6 m/s toward particle B, the duration of the collision is 1.50 ms, and after the collision particle B is moving at 13.1 m/s in particle A's original direction. Particle B has a mass of 7.26 kg. To keep this problem simple, assume the only force exerted on particle B is due to particle A, and assume the acceleration is constant. Find the magnitude of the force exerted by particle A on particle B. (The mass for particle A can be different in each case.)
Part 1 of 11 - Conceptualize
We are asked to find the magnitude of the force exerted on particle B in both cases. The two final answers should be numerical and have the SI units of force. Our goal is to see if the force in Case 2 in which particle B is moving toward particle A is lower (perhaps even zero) compared to Case 1 in which particle B is at rest before the collision.
Part 2 of 11 - Categorize
This problem involves a special case of one-dimensional kinematics with constant acceleration.

Once we know particle B's acceleration, what principle will we need to apply to find the force?
     Correct: Your answer is correct.
Correct. Since only the force exerted by particle A acts on particle B, we use the acceleration and mass to find this force.
Part 3 of 11 - Conceptualize
In Case 1, particle B is at rest before the collision. We must first find particle B's acceleration. Which sketch best applies to this task?

Correct: Your answer is correct.
Correct. This sketch shows the relevant information: particle B is at rest before the collision and particle B is moving in the same direction as particle A's original direction after the collision. Also, a coordinate system is needed when we solve kinematics problems.
Part 4 of 11 - Analyze
When solving a problem involving constant acceleration, it is best to list the five variables. We create our list using the coordinate system from our sketch. To find the best constant acceleration equation, we only need to know if each variable is known, needed, or not needed; we don't need to know the values of each variable at this time.

Which variables are known? (Select all that apply.)
Correct: Your answer is correct.

Part 5 of 11 - Analyze (cont.)
Which variable will we need to find the value of to solve this problem?
     Correct: Your answer is correct.
Correct.
Part 6 of 11 - Analyze (cont.)
Using the variables we know and need, which equation is best to use for this problem?
     Correct: Your answer is correct.
Correct.
Part 7 of 11 - Analyze (cont.)
Now, we are ready to calculate particle B's acceleration from
vx = v0x + axt.
Solve for ax and substitute values. Remember particle B's initial velocity is zero for Case 1.

The acceleration in Case 1 is given by:
ax =
13.1 Correct: Your answer is correct. seenKey

13.1

m/s
  
0 Correct: Your answer is correct. seenKey

0

m/s
1.5 Incorrect with feedback: Your answer is incorrect. Click to see feedback.

This feedback is based on your last submitted answer, not on your current answer.

Your response is off by a multiple of ten.
seenKey

0.0015

s
= (No Response) seenKey

8730

m/s2.
Part 8 of 11 - Analyze (cont.)
We know particle B's acceleration and mass. So we use Newton's second law to find the net force exerted on particle B. Since only particle A exerts a force on B, the net force equals the force exerted by particle A.

The magnitude of the force in Case 1 is given by:
F = max
=
7.26 Correct: Your answer is correct. seenKey

7.26

kg
(No Response) seenKey

8730

m/s2
= 0.0634 Incorrect with feedback: Your answer is incorrect. Click to see feedback.

This feedback is based on your last submitted answer, not on your current answer.

Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.
seenKey

63400

N.
Part 9 of 11 - Conceptualize
In Case 2, particle B is moving toward particle A before the collision. We must first find particle B's acceleration. Which sketch best applies to this task?

Correct: Your answer is correct.
Correct. Before the collision, particle B is moving toward particle A. Particle B is moving in the same direction as particle A's original direction after the collision. The acceleration is in the same direction as particle B's change in velocity. Finally, a coordinate system is needed when we solve kinematics problems.
Part 10 of 11 - Analyze
We can use the same equation to find the acceleration in this case as we did for Case 1. We can calculate particle B's acceleration from
vx = v0x + axt.
Solve for ax and substitute values. Remember that in Case 2, both particles have the same initial speed. However, remember that the particles are moving in opposite directions.

The acceleration in Case 2 is given by:
ax =
(No Response) seenKey

13.1

m/s
  
(No Response) seenKey

-26.6

m/s
(No Response) seenKey

0.0015

s
= (No Response) seenKey

26500

m/s2.
Part 11 of 11 - Analyze (cont.)
As in Case 1, we use Newton's second law to find the force exerted by particle A.

The magnitude of the force in Case 2 is given by:
F = max
=
(No Response) seenKey

7.26

kg
(No Response) seenKey

26500

m/s2
= (No Response) seenKey

1.92e+05

N.
Finalize
As we expected, we find a numerical answer in newtons in both cases. However, the results contradict some people's intuition that the force on particle B should be smaller and perhaps zero if particle B's speed matches particle A's speed. The force is actually greater if particle B is moving toward particle A. Put in terms of the case study involving the freight train and the passenger train, it is a good thing the passenger train stopped moving. In fact, in the best case scenario, the passenger train would have decelerated, stopped momentarily, and reversed direction. If the passenger train could have moved backward away from the freight train, the collision may have been avoided.
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
2. 0/15 points  |  Previous Answers SerPSET9 5.PLE.002. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
0/1 0/1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1
1/50 2/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
0/15
 
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.

Prelecture Exploration: Atwood Machine
When two massive objects are suspended on opposite sides of a pulley, the arrangement is called an Atwood machine. Two friends, Makena and Dani, are studying physics together, and they decide to delve further into understanding this arrangement.

In this simulation, the cord that connects the two masses is ideal; that is, it is inextensible (does not stretch) and its mass is negligible. Also, the pulley is frictionless with negligible mass, and any air resistance can be neglected. The forces and accelerations of the two masses are shown, along with the tension in the cord.

The sign convention for motion is defined as shown by the arrows. Makena and Dani can change the mass of m1 and m2 by using the sliders. They then can click "start" to set the system in motion.


Click here to open the simulation in a new window.
Part 1 of 13 - Accelerations in an Atwood Machine
Dani and Makena examine the figure shown.
Which of Dani's statements is correct, given what she knows about this system?
     Incorrect: Your answer is incorrect.

Dani is incorrect. She does not realize that the rope connects the masses, so if one accelerates, both will accelerate.
Part 2 of 13 - Accelerations in an Atwood Machine
Now the friends consider the situation for which the mass m1 is initially moving downward. Makena and Dani discuss the acceleration in this case. Which of Makena's statements could be correct?
     Incorrect: Your answer is incorrect.

Makena is incorrect. She has not realized that the rope connects the masses, so if one accelerates, both will accelerate.

Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
3. /1 points SerPSET9 5.P.007. My Notes
Question Part
Points
Submissions Used
1
/1
0/50
Total
/1
 
The distinction between mass and weight was discovered after Jean Richer transported pendulum clocks from Paris, France, to Cayenne, French Guiana in 1671. He found that they quite systematically ran slower in Cayenne that in Paris. The effect was reversed when the clocks returned to Paris. How much weight would a 77.0 kg person lose in traveling from Paris, where g = 9.8095 m/s2, to Cayenne, where g = 9.7808 m/s2?
N
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
4. 4/8 points  |  Previous Answers SerPSET9 5.AE.007. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8
/1 /1 1/1 1/1 1/1 1/1 0/1 0/1
0/50 0/50 1/50 1/50 1/50 1/50 1/50 1/50
Total
4/8
 
Example 5.7 One Block Pushes Another
(a) A force is applied to a block of mass m1, which pushes on the second block of mass m2. (b) The forces acting on m1. (c) The forces acting on m2.
Two blocks of masses m1 and m2, with m1 > m2, are placed in contact with each other on a frictionless, horizontal surface as in figure (a). A constant horizontal force vector F is applied to m1 as shown.

(A) Find the magnitude of the acceleration of the system.

(B) Determine the magnitude of the contact force between the two blocks.
SOLVE IT
(A) Find the magnitude of the acceleration of the system.

Conceptualize Conceptualize the situation by using figure (a) and realize that both blocks must experience the same acceleration because they are in contact with each other and remain in contact throughout the motion.

Categorize We categorize this problem as one involving a particle under a net force because a force is applied to a system of blocks and we are looking for the acceleration of the system.
Analyze First model the combination of two blocks as a single particle under a net force. Apply Newton's second law to the combination in the x direction to find the acceleration (Use the following as necessary: F, m1, and m2):
Fx = F = (m1 + m2)ax
(1)    ax =
Finalize The acceleration given by Equation (1) is the same as that of a single object of mass m1 + m2 and subject to the same force.
(B) Determine the magnitude of the contact force between the two blocks.
Conceptualize The contact force is internal to the system of two blocks. Therefore, we cannot find this force by modeling the whole system (the two blocks) as a single particle.

Categorize Now consider each of the two blocks individually by categorizing each as a particle under a net force.

Analyze We construct a diagram of forces acting on the object for each block as shown in figures (b) and (c), where the contact force is denoted by
P.
From figure (c), we see that the only horizontal force acting on m2 is the contact force
P12
(the force exerted by m1 on m2), which is directed to the right.
Apply Newton's second law to m2:
(2)    
Fx = P12 = m2ax
Substitute the value of the acceleration ax given by Equation (1) into Equation (2) (Use the following as necessary: F, m1, and m2):
(3)    P12 = m2ax =
Finalize This result shows that the contact force P12 is less than the applied force F. The force required to accelerate block 2 alone must be less than the force required to produce the same acceleration for the two-block system.

To finalize further, let us check this expression for P12 by considering the forces acting on m1, shown in figure (b). The horizontal forces acting on m1 are the applied force vector F to the right and the contact force
P21
to the left (the force exerted by m2 on m1). From Newton's third law,
P21
is the reaction force to
P12,
so P21 = P12.
Apply Newton's second law to m1:
(4)    
Fx = F P21 = F P12 = m1ax
Solve for P12 and substitute the value of ax from Equation (1):
P12 = F m1ax = F m1
F
m1 + m2
 = 
m2
m1 + m2
F
This result agrees with Equation (3), as it must.
MASTER IT HINTS: GETTING STARTED | I'M STUCK!
Three blocks are in contact with one another on a frictionless, horizontal surface as in the figure below. A horizontal force vector F is applied to m1, where m1 = 1.52 kg, m2 = 3.73 kg, m3 = 4.92 kg, and F = 18.5 N. (Take the +x direction to be to the right.)
Figure from book
(a) Find the acceleration of the blocks.
Correct: Your answer is correct. seenKey

1.82

m/s2

(b) Find the net force on each block.
F1, net = Correct: Your answer is correct. seenKey

2.76

N
F2, net = Correct: Your answer is correct. seenKey

6.79

N
F3, net = Correct: Your answer is correct. seenKey

8.95

N

(c) Find the magnitudes of the contact forces between the blocks.
P12 = Incorrect: Your answer is incorrect. seenKey

15.7


What force must m1 exert directly on m2 to accelerate the rest of the blocks as calculated in part (a)? N
P23 = Incorrect: Your answer is incorrect. seenKey

8.95


What force must m2 exert directly on m3 to accelerate it as calculated in part (a)? N
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
5. 1/15 points  |  Previous Answers SerPSET9 5.AMT.033. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
1/1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1
2/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
1/15
 
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part.

Analysis Model Tutorial
A bag of cement weighing 361 N hangs in equilibrium from three wires as suggested in the figure. Two of the wires make angles
θ1 = 65.0°
and
θ2 = 44.0°
with the horizontal. Assuming the system is in equilibrium, find the tensions T1, T2, and T3 in the wires.
Part 1 of 8 - Conceptualize:
Look carefully at the figure. Which force do you expect to be larger,
T1 or T2?
Should we expect that
T1 and T2
will each be larger than the weight of the bag because only a component of their magnitude is in the vertical direction? Or should they each be smaller because they work together to hold up the bag? Or could one force be larger than the weight and one smaller? We'll choose a standard coordinate system with x horizontal and y vertical.
Part 2 of 8 - Categorize:
(1) What analysis model correctly describes the knot, that is, the point at which all three forces meet, and is most useful for solving this problem?
     Correct: Your answer is correct.
Correct. The knot is subject to forces but is not moving.
Part 3 of 8
(2) The ring at the top of the strap, where the rope carrying force
T3
is attached, is also a particle in equilibrium. Therefore, the tension
T3 = N.


Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
6. /2 points SerPSET9 5.CQ.007. My Notes
Question Part
Points
Submissions Used
1 2
/1 /1
0/50 0/50
Total
/2
 
A person holds a ball in her hand.
(a) Identify all the external forces acting on the ball and the Newton's third-law reaction force to each one. (Select all that apply.)

(b) If the ball is dropped, what force is exerted on it while it is falling? Identify the reaction force in this case. (Ignore air resistance.)
    
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
7. 1/1 points  |  Previous Answers SerPSET9 5.OQ.002. My Notes
Question Part
Points
Submissions Used
1
1/1
3/50
Total
1/1
 
In the figure below, a locomotive has broken through the wall of a train station. During the collision, what can be said about the force exerted by the locomotive on the wall?
     Correct: Your answer is correct.
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
8. /2 points SerPSET9 5.P.011.MI. My Notes
Question Part
Points
Submissions Used
1 2
/1 /1
0/50 0/50
Total
/2
 
An electron of mass 9.11 10-31 kg has an initial speed of 2.20 105 m/s. It travels in a straight line, and its speed increases to 7.20 105 m/s in a distance of 4.80 cm. Assume its acceleration is constant.
(a) Determine the magnitude of the force exerted on the electron.
N

(b) Compare this force (F) with the weight of the electron (Fg), which we ignored.
F
Fg
=

Need Help? Master It

Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
9. /1 points SerPSET9 5.P.012. My Notes
Question Part
Points
Submissions Used
1
/1
0/50
Total
/1
 
Besides the gravitational force, a 3.75-kg object is subjected to one other constant force. The object starts from rest and in 1.20 s experiences a displacement of (4.55î 3.30ĵ) m, where the direction of ĵ is the upward vertical direction. Determine the other force.
vector F =
N
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
10. 1/6 points  |  Previous Answers SerPSET9 5.P.013. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6
0/1 /1 0/1 1/1 /1 0/1
2/50 0/50 2/50 1/50 0/50 1/50
Total
1/6
 
One or more external forces, large enough to be easily measured, are exerted on each object enclosed in a dashed box shown in the figures below. Identify the reaction to each of these forces. (Select all that apply.)
(a)
Incorrect: Your answer is incorrect.


(b)


(c)
Incorrect: Your answer is incorrect.


(d)
Correct: Your answer is correct.


(e)


(f)
Incorrect: Your answer is incorrect.

Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
11. 1/5 points  |  Previous Answers SerPSET9 5.P.015. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5
0/1 1/1 0/1 0/1 0/1
1/50 1/50 1/50 1/50 1/50
Total
1/5
 
Two forces,
vector F 1 = (2.10î 5.30ĵ) N
and
vector F 2 = (4.05î 5.65ĵ) N,
act on a particle of mass 1.80 kg that is initially at rest at coordinates
(+2.35 m, +4.05 m).
(a) What are the components of the particle's velocity at t = 10.8 s?
vector v =
75.35
Incorrect: Your answer is incorrect. webMathematica generated answer key m/s

(b) In what direction is the particle moving at t = 10.8 s?
Correct: Your answer is correct. seenKey

-60.7

° counterclockwise from the +x-axis

(c) What displacement does the particle undergo during the first 10.8 s?
Δvector r =
406.98
Incorrect: Your answer is incorrect. webMathematica generated answer key m

(d) What are the coordinates of the particle at t = 10.8 s?
x = Incorrect: Your answer is incorrect. seenKey

202


Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. m
y = Incorrect: Your answer is incorrect. seenKey

-351


Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. m
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
12. 2/2 points  |  Previous Answers SerPSET9 5.P.018. My Notes
Question Part
Points
Submissions Used
1 2
1/1 1/1
1/50 4/50
Total
2/2
 
A force F with arrow applied to an object of mass m1 produces an acceleration of 3.30 m/s2. The same force applied to a second object of mass m2 produces an acceleration of 2.00 m/s2.
(a) What is the value of the ratio m1/m2?
Correct: Your answer is correct. seenKey

0.606



(b) If m1 and m2 are combined into one object, find its acceleration under the action of the force F with arrow.
Correct: Your answer is correct. seenKey

1.25

m/s2

Need Help? Watch It

Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.