WebAssign is not supported for this browser version. Some features or content might not work. System requirements

WebAssign

Welcome, demo@demo

(sign out)

Tuesday, April 1, 2025 05:30 EDT

Home My Assignments Grades Communication Calendar My eBooks

Serway and Jewett - Principles of Physics 5/e (Homework)

James Finch

Physics - College, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 5 / 28

Due : Monday, January 28, 2030 00:00 EST

Last Saved : n/a Saving...  ()

Question
Points
1 2 3 4 5 6
–/5 –/12 5/6 0/1 –/1 –/3
Total
5/28 (17.9%)
  • Instructions

    The WebAssign content for Principles of Physics: A Calculus Based Text 5e Serway and Jewett includes an extensive bank of more than 3800 questions including end-of-chapter problems, interactive Active Figure questions, and Master It tutorial problems offering feedback and hints to guide students to content mastery.

    What's New in this Edition? Based on their analysis of WebAssign data, the authors identified and enhanced the most frequently assigned problems, ensuring students receive support where they need it most. Denoted in the text by a shaded box around the problem number, each of these problems in Enhanced WebAssign provides students with targeted answer-specific feedback designed to address common misconceptions plus either a Watch It solution video or a Master It interactive tutorial.

    Every problem includes a link to the appropriate section of a complete interactive eBook, (also available through a dynamic table of contents from the student's WebAssign homepage), allowing students to highlight and take notes as they read.

    Key features of this textbook collection
    • Almost every end-of-chapter problem from the textbook
    • Conceptual Questions and Quick Quizzes from the textbook
    • Master It step-by-step tutorials
    • Watch It problem-solving videos
    • Active Figure simulations of key physics concepts
    • Active Example interactive worked examples direct from the text

    Click here for a list of all of the questions coded in WebAssign. This demo assignment allows many submissions and allows you to try another version of the same question for practice wherever the problem has randomized values.

Assignment Submission

For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer.

Assignment Scoring

Your last submission is used for your score.

1. /5 points was SerPOP5 3.AF.007. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5
/1 /1 /1 /1 /1
0/50 0/50 0/50 0/50 0/50
Total
/5
 

Active Figure 4.7 - The Projectile Path

Instructions: The simulation below illustrates the motion of a projectile launched at different speeds and angles.



Display in a New Window | Explore with this Active Figure
Explore
A projectile is launched with a launch angle of 70° with respect to the horizontal direction and with initial speed 44 m/s.

(A) How do the vertical and horizontal components of its velocity vary with time?
(B) How long does it remain in flight?
(C) For a given launch speed, what launch angle produces the longest time of flight?


Conceptualize
Consider the projectile to be a point mass that starts with an initial velocity, upward and to the right, with forces from air resistance neglected. There is no force acting horizontally to accelerate its horizontal motion, while its vertical motion is accelerated downward by gravity. Therefore as the projectile moves to the right at a constant rate, the vertical part of its motion consists of first rising upward and then moving downward until the projectile strikes the ground. Use the simulation to display the projectile motion.

Categorize
The velocity has components in both the x and y directions, so we categorize this as a problem involving particle motion in two dimensions. The particle also has only a y component of acceleration, so we categorize it as a particle under constant acceleration in the y direction and constant velocity in the x direction.


(A) How do the vertical and horizontal components of its velocity vary with time?

Analyze The initial velocity in the x-direction vxi is related to the initial speed by

vxi = vi cos 70°
The constant velocity in the x-direction means that the equation describing the time dependence of x for the particle, with x0 taken as 0, is
x = x0 + vxit = 0 + m/s t
The equation for the vertical coordinate, which is constantly accelerating downward at g = 9.8 m/s2, is
y = y0 + vyit - ½gt2 = ( m/s) t + ( m/s2) t2
Finalize
The -½gt2 term is negative. The other time-dependent term is proportional to t and positive. Which of the two dominates at small t ? Which term's magnitude gets larger faster as t gets large? What effect does that have on the sign of the y coordinate as t starts out small and then gets larger? Is this consistent with the path you expect the projectile to take?
Hint


(B) How long does it remain in flight?

Analyze
The y-component of the projectile's velocity decreases by 9.8 m/s for each second of flight as the projectile rises. Therefore it takes a time of

ty,max =
vyi
g
=
vi sin θ
g
for the vertical component of velocity to reach a value of 0, which occurs at the projectile's maximum height. At each height on the way down the particle has regained the same speed and has the same acceleration as it had on the way up, so that the complete time of flight is twice the time to reach the maximum height, and is equal to
tflight =
2vi sin θ
g
In the present problem, that expression gives
tflight = s


(C) For a given launch speed, what launch angle produces the longest time of flight?
Analyze
The time of flight for a given initial speed vi,

tflight =
2vi sin θ
g
is largest when sin θ is largest, which is at θ = °. What does that correspond to physically?
Finalize
Is the result consistent with experience? Try the simulation for various launch angles and speeds, and check if the computer calculation shows this same result.

Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
2. /12 points SerPOP5 3.AE.002. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12
/1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1 /1
0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
/12
 
Example 4.4 That's Quite an Arm!
A stone is thrown from the top of a building.
A stone is thrown from the top of a building upward at an angle of 21.0° to the horizontal with an initial speed of 23.5 m/s as shown in the figure. The height of the building is 45.0 m.

(A) How long does it take the stone to reach the ground?

(B) What is the speed of the stone just before it strikes the ground?
SOLVE IT
Conceptualize Study the figure, in which we have indicated the trajectory and various parameters of the motion of the stone.

Categorize We categorize this problem as a projectile motion problem. The stone is modeled as a particle under constant acceleration in the y direction and a particle under constant velocity in the x direction.

Analyze We have the information xi = yi = 0, yf = -45.0 m, ay = -g, and vi = 23.5 m/s (the numerical value of yf is negative because we have chosen the top of the building as the origin).
(A) How long does it take the stone to reach the ground?
Find the initial x and y components of the stone's velocity:
vxi = vi cos θi = (23.5 m/s) cos 21.0°
vxi = m/s
vyi = vi sin θi = (23.5 m/s) sin 21.0°
vyi = m/s
Express the vertical position of the stone from the vertical component of the position vector as a function of time:
yf = yi + vyit + ½ayt2
Substitute numerical values:
-45.0 m = (8.422 m/s)t + ½(-9.80 m/s2)t2
Solve the quadratic equation for t:
t = s
(B) What is the speed of the stone just before it strikes the ground?
Use the y component of the velocity vector as a function of time with t = 4.009 s to obtain the y component of the velocity of the stone just before it strikes the ground:
vyf = vyi + ayt
Substitute numerical values:
vyf = 8.422 m/s + (-9.80 m/s2)(4.009 s)
vyf = m/s
Use this component with the horizontal component vxf = vxi = 21.939 m/s to find the speed of the stone at t = 4.009 s:
vf = √vxf2 + vyf2 = √(21.939 m/s)2 + (-30.869 m/s)2
vf = m/s
Finalize Is it reasonable that the y component of the final velocity is negative? Is it reasonable that the final speed is larger than the initial speed of 23.5 m/s?
MASTER IT HINTS: GETTING STARTED | I'M STUCK!
The following questions present a twist on the scenario above to test your understanding.

Suppose another stone is thrown horizontally from the same building. If it strikes the ground 70 m away, find the following values.
(a) time of flight
s

(b) initial speed
m/s

(c) speed and angle with respect to the horizontal of the velocity vector at impact
m/s
°
If the stone were thrown harder, and left with 1.5 times the initial speed, you might expect it to go farther, but how exactly does that happen?
(d) Throwing the stone horizontally at 1.5 times the previous speed multiplies the time to reach the ground by what factor?


(e) The horizontal component of the velocity is multiplied by what factor?


(f) How many times farther does the stone land from the building?

Watch a Video Hint
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
3. 5/6 points  |  Previous Answers SerPOP5 3.P.005.MI. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6
1/1 1/1 1/1 1/1 1/1 0/1
2/50 2/50 2/50 2/50 3/50 4/50
Total
5/6
 
A fish swimming in a horizontal plane has velocity v with arrowi = (4.00 î + 1.00 ĵ) m/s at a point in the ocean where the position relative to a certain rock is r with arrowi = (12.0 î 1.40 ĵ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is v with arrow = (15.0 î 3.00 ĵ) m/s.
(a) What are the components of the acceleration of the fish?
ax = Correct: Your answer is correct. m/s2
ay = Correct: Your answer is correct. m/s2

(b) What is the direction of its acceleration with respect to unit vector î?
Correct: Your answer is correct. ° counterclockwise from the +x-axis

(c) If the fish maintains constant acceleration, where is it at t = 28.0 s?
x = Correct: Your answer is correct. m
y = Correct: Your answer is correct. m

In what direction is it moving?
Incorrect: Your answer is incorrect.
Draw coordinate axes on a separate piece of paper, and then add the velocity vector with its tail at the origin. Write the numerical values for the x and y components and then use this drawing to determine the angle.° counterclockwise from the +x-axis

Need Help? Master It

Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
4. 0/1 points  |  Previous Answers SerPOP5 3.P.017.WI. My Notes
Question Part
Points
Submissions Used
1
0/1
4/50
Total
0/1
 
A soccer player kicks a rock horizontally off a 39.0-m-high cliff into a pool of water. If the player hears the sound of the splash 3.01 s later, what was the initial speed given to the rock? Assume the speed of sound in air is 343 m/s.
Incorrect: Your answer is incorrect.
The time given in the problem can be divided into two intervals: the time for the rock to hit the water and the time for the sound to return to the kicker. m/s
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
5. /1 points SerPOP5 3.P.022. My Notes
Question Part
Points
Submissions Used
1
/1
0/50
Total
/1
 
A fireworks rocket explodes at height h, the peak of its vertical trajectory. It throws out burning fragments in all directions, but all at the same speed v. Pellets of solidified metal fall to the ground without air resistance. Find the smallest angle that the final velocity of an impacting fragment makes with the horizontal. (Use any variable or symbol stated above along with the following as necessary: g for the acceleration due to gravity.)
θ =
Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
6. /3 points SerPOP5 Q1.1.001.Tutorial. My Notes
Question Part
Points
Submissions Used
1 2 3
/1 /1 /1
0/50 0/50 0/50
Total
/3
 
 1.1: SIGNIFICANT FIGURES

  • Part 1 - Multiplication and Division

    Dividing 2.54 by 1.3, a calculator produces 1.9538462. However, it would be very imprecise to report 1.9538462 as the answer because it would be leading others astray since this many significant figures in the result implies that the data used is accurate to at least that same number of significant figures. The least accurate number, 1.3, is known to two significant figures; therefore, the answer should be rounded to two significant figures, 2.0, where 1.95 is rounded up to 2.0.

    A general rule is that your answer from the product or division of two numbers should never have more significant figures than the number possessing the least number of significant figures.

    VIDEO EXAMPLE 1:    EXAMPLE 1-1

    Note that 0.0000356 has only three significant figures. The four zeroes between the decimal point and the 3 show only the position of the decimal point and are not considered significant.



Carry out the following arithmetic operations. (Enter your answers to the correct number of significant figures.)
(a) the sum of the measured values 621, 39.2, 0.70, and 3.5
WebAssign will check your answer for the correct number of significant figures.

(b) the product 1.1 × 2.947
WebAssign will check your answer for the correct number of significant figures.

(c) the product 5.98 × π
WebAssign will check your answer for the correct number of significant figures.

Need Help? Master It

Your work in question(s) will also be submitted or saved.
Viewing Saved Work Revert to Last Response
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number.
Enter a number with the correct number of significant figures.
Enter a number with the correct number of significant figures.
Enter a number with the correct number of significant figures.