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Larson et al - College Algebra and Calculus 2/e (Homework)

James Finch

Math - College, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 32 / 44

Due : Sunday, January 27, 2030 00:00 EST

Last Saved : n/a Saving...  ()

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Question
Points
1 2 3 4 5 6 7 8 9 10
0/1 –/1 19/19 9/9 1/1 –/1 3/3 –/5 –/1 –/3
Total
32/44 (72.7%)

  • Instructions

    Here are some textbook questions from College Algebra and Calculus: An Applied Approach 2/e by Ron Larson and Anne V. Hodgkins published by Brooks/Cole. Click here for a list of all of the questions coded in WebAssign. This demo assignment allows many submissions and allows you to try another version of the same question for practice wherever the problem has randomized values.

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1. 0/1 points  |  Previous Answers LarCAApCalc2 0.2.038. My Notes
Question Part
Points
Submissions Used
1
0/1
3/50
Total
0/1
 
Identify the rule(s) of algebra illustrated by the statement. (Select all that apply.)
1
5
 (5 · 16) = (
1
5
 · 5)16 = 1 · 16 = 16
Incorrect: Your answer is incorrect.

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2. –/1 points LarCAApCalc2 0.4.042. My Notes
Question Part
Points
Submissions Used
1
–/1
0/50
Total
–/1
 
Rewrite the expression by rationalizing the denominator. Simplify your answer.
5x
√61 − 6

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3. 19/19 points  |  Previous Answers LarCAApCalc2 0.4.044.SBS. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1
1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50
Total
19/19
 
Rewrite the expression by rationalizing the denominator.
2
3√6 − 2
STEP 1: Multiply the numerator and denominator by conjugate.
2
3√6 − 2
=
2
3√6 − 2
×
3√ Correct: Your answer is correct. Incorrect: Your answer is incorrect. Correct: Your answer is correct.
3√ Correct: Your answer is correct. Incorrect: Your answer is incorrect. Correct: Your answer is correct.

STEP 2: Multiply fractions.
2(3√ Correct: Your answer is correct. Correct: Your answer is correct. Correct: Your answer is correct. )
(3√6)2 – ( Correct: Your answer is correct. )2

STEP 3: Simplify.
2(3√ Correct: Your answer is correct. Incorrect: Your answer is incorrect. Correct: Your answer is correct. )
Correct: Your answer is correct. − Correct: Your answer is correct.

STEP 4: Divide out like factors and simplify.
3√ Correct: Your answer is correct. Incorrect: Your answer is incorrect. Correct: Your answer is correct.
Correct: Your answer is correct.
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4. 9/9 points  |  Previous Answers LarCAApCalc2 1.1.028.SBS. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9
1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1 1/1
1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50 1/50
Total
9/9
 
Solve the equation and check your solution.
5(15t − 14) + 4(t − 22) = 0
STEP 1: Expand.
Correct: Your answer is correct. t − Correct: Your answer is correct. + Correct: Your answer is correct. t − Correct: Your answer is correct. = 0
STEP 2: Combine like terms.
Correct: Your answer is correct. t − Correct: Your answer is correct. = 0
STEP 3: Solve for t.
Correct: Your answer is correct. t = Correct: Your answer is correct.
t = Correct: Your answer is correct.
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5. 1/1 points  |  Previous Answers LarCAApCalc2 1.1.030. My Notes
Question Part
Points
Submissions Used
1
1/1
2/50
Total
1/1
 
Solve the equation and check your solution. (If there is no solution, enter NO SOLUTION.)
3[2x – (x + 5)] = 5(x – 9)
x = Correct: Your answer is correct.

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6. –/1 points LarCAApCalc2 1.4.002.MI. My Notes
Question Part
Points
Submissions Used
1
–/1
0/50
Total
–/1
 
Use the discriminant to determine the number of real solutions of the quadratic equation.
4x2 − 3x − 7 = 0
    

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7. 3/3 points  |  Previous Answers LarCAApCalc2 1.6.040. My Notes
Question Part
Points
Submissions Used
1 2 3
1/1 1/1 1/1
1/50 1/50 1/50
Total
3/3
 
Consider the following inequality.
6x + 1 ≤ 2 + 4x
(a) Solve the inequality.
x Correct: Your answer is correct. Correct: Your answer is correct.

(b) Graph the solution set on the real number line.
Use the tools to enter your answer.
Created with Raphaël 2.1.0-10-8-6-4-20246810
Created with Raphaël 2.1.0

NO SOLUTION

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Correct: Your answer is correct.

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8. –/5 points LarCAApCalc2 1.6.066. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5
–/1 –/1 –/1 –/1 –/1
0/50 0/50 0/50 0/50 0/50
Total
–/5
 
Consider the following inequality.
|
2x + 3
3
| ≤ 4
(a) Solve the inequality.
x

(b) Graph the solution set on the real number line.
Use the tools to enter your answer.
Created with Raphaël 2.1.0-20-16-12-8-4048121620
Created with Raphaël 2.1.0

NO SOLUTION

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9. –/1 points LarCAApCalc2 3.1.055. My Notes
Question Part
Points
Submissions Used
1
–/1
0/50
Total
–/1
 
The path of a diver is given by the equation below where y is the height (in feet) and x is the horizontal distance from the end of the diving board (in feet) (see figure).
y = –
4
9
 x2 +
24
9
 x + 9
What is the maximum height of the diver? Verify your answer using a graphing utility.
ft

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10. –/3 points LarCAApCalc2 7.1.070. My Notes
Question Part
Points
Submissions Used
1 2 3
–/1 –/1 –/1
0/50 0/50 0/50
Total
–/3
 
Use the graph to find the limit (if it exists). (If you need to use or –, enter INFINITY or –INFINITY, respectively. If an answer does not exist, enter DNE.)
A = (-1, 0),    B = (-1, 4),    c = -1

(a)
lim x→c+ f(x)



(b)
lim x→c− f(x)



(c)
lim x→c f(x)

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