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Larson & Hodgkins-College Algebra w Apps BLS 2/e (Homework)

James Finch

Math - College, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 32 / 48

Due : Sunday, January 27, 2030 00:00 EST

Last Saved : n/a Saving...  ()

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Question
Points
1 2 3 4 5 6 7 8 9 10 11
–/1 –/1 –/19 –/9 –/1 –/1 –/3 –/5 –/1 –/6 –/1
Total
32/48 (66.7%)

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1. –/1 points LarCAABLS2 0.2.038. My Notes
Question Part
Points
Submissions Used
1
–/1
0/50
Total
–/1
 
Identify the rule(s) of algebra illustrated by the statement. (Select all that apply.)
1
6
 (6 · 12) = (
1
6
 · 6)12 = 1 · 12 = 12

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2. –/1 points LarCAABLS2 0.4.042. My Notes
Question Part
Points
Submissions Used
1
–/1
0/50
Total
–/1
 
Rewrite the expression by rationalizing the denominator. Simplify your answer.
5x
√16 − 1

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3. –/19 points LarCAABLS2 0.4.044.SBS. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
–/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1
0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
–/19
 
Rewrite the expression by rationalizing the denominator.
3
4√21 − 3
STEP 1: Multiply the numerator and denominator by conjugate.
3
4√21 − 3
=
3
4√21 − 3
×
4√
4√

STEP 2: Multiply fractions.
3(4√ )
(4√21)2 – ( )2

STEP 3: Simplify.
3(4√ )
−

STEP 4: Divide out like factors and simplify.
4√

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4. –/9 points LarCAABLS2 1.1.028.SBS. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9
–/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1 –/1
0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
–/9
 
Solve the equation and check your solution.
5(13t − 15) + 2(t − 63) = 0
STEP 1: Expand.
t − + t − = 0
STEP 2: Combine like terms.
t − = 0
STEP 3: Solve for t.
t =
t =
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5. –/1 points LarCAABLS2 1.1.030. My Notes
Question Part
Points
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1
–/1
0/50
Total
–/1
 
Solve the equation and check your solution. (If there is no solution, enter NO SOLUTION.)
3[2x – (x + 5)] = 5(x – 3)
x =

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6. –/1 points LarCAABLS2 1.4.002.MI. My Notes
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1
–/1
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–/1
 
Use the discriminant to determine the number of real solutions of the quadratic equation.
2x2 − 3x − 3 = 0
    

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7. –/3 points LarCAABLS2 1.6.040. My Notes
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1 2 3
–/1 –/1 –/1
0/50 0/50 0/50
Total
–/3
 
Consider the following inequality.
7x + 3 ≥ -6 + 5x
(a) Solve the inequality.
x

(b) Graph the solution set on the real number line.
Use the tools to enter your answer.
Created with Raphaël 2.1.0-10-8-6-4-20246810
Created with Raphaël 2.1.0

NO SOLUTION

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8. –/5 points LarCAABLS2 1.6.066. My Notes
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Points
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1 2 3 4 5
–/1 –/1 –/1 –/1 –/1
0/50 0/50 0/50 0/50 0/50
Total
–/5
 
Consider the following inequality.
|
2x + 2
3
| < 7
(a) Solve the inequality.
x

(b) Graph the solution set on the real number line.
Use the tools to enter your answer.
Created with Raphaël 2.1.0-20-16-12-8-4048121620
Created with Raphaël 2.1.0

NO SOLUTION

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9. –/1 points LarCAABLS2 3.1.055. My Notes
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1
–/1
0/50
Total
–/1
 
The path of a diver is given by the equation below where y is the height (in feet) and x is the horizontal distance from the end of the diving board (in feet) (see figure).
y = –
4
9
 x2 +
24
9
 x + 13
What is the maximum height of the diver? Verify your answer using a graphing utility.
ft

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10. –/6 points LarCAABLS2 2.1.502.XP. My Notes
Question Part
Points
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1 2 3 4 5 6
–/1 –/1 –/1 –/1 –/1 –/1
0/50 0/50 0/50 0/50 0/50 0/50
Total
–/6
 
Complete the table.
y = –2 – x2
x −2 −1 0 1 2
y

Use the resulting solution points to sketch the graph of the equation. (Plot every point and plot the graph.)
No Solution
Help
-10
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Clear Graph
Delete Layer
Fill

Graph LayersToggle Open/Closed

  • After you add an object to the graph you can use Graph Layers to view and edit its properties.
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11. –/1 points LarCAABLS2 2.1.506.XP. My Notes
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–/1
 
Use the diagram of a Ferris wheel to write an equation that models the circular shape of the wheel if d = 520 ft.
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