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Zumdahl - Intro Chemistry: A Foundation 4/e (Homework)

James Finch

Chemistry - College, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 5 / 50

Due : Thursday, April 9, 2020 09:00 EDT

Last Saved : n/a Saving...  ()

Question
Points
1 2 3 4 5
Total
5/50 (10.0%)
  • Instructions

    Here are some textbook questions from Introductory Chemistry: A Foundation 4/e by Zumdahl and Zumdahl published by Houghton Mifflin. Click here for a list of all of the questions coded in WebAssign. This demo assignment allows many submissions and makes the answer key available after the first submission so you can see the correct answers. (Typically, the answer key is posted after the due date!)

Assignment Submission

For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer.

Assignment Scoring

Your last submission is used for your score.

1. /8 points ZumIntro4 2.008. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8
0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
/8
 
Express each of the following numbers in standard scientific notation.
(a) 9367549
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9.367549e+06

(b) 7231
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7.231e+03

(c) 0.0005650
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5.650e-04

(d) 5.508
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5.508e+00

(e) 6.63 102
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6.63e+02

(f) 6427 10-2
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6.427e+01

(g) 0.000000007189
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7.189e-09

(h) 0.755
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7.55e-01

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2. /1 points ZumIntro4 2.036. My Notes
Question Part
Points
Submissions Used
1
0/50
Total
/1
 
Why can the length of the pin shown in Figure 2.5 not be recorded as 2.850?


Figure 2.5


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3. /7 points ZumIntro4 5.050. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7
0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
/7
 
Write the formula for each of the following compounds that contain polyatomic ions. Be sure to enclose the polyatomic ion parentheses if more than one such ion is needed. (Type your answer using the format Cr(CN)3 for Cr(CN)3.)
(a) manganese(II) sulfate
(No Response) seenKey

MnSO4


(b) hydrotelluric acid
(No Response) seenKey

H2Te -or- H2Te(aq)


(c) magnesium hydrogen sulfate
(No Response) seenKey

Mg(HSO4)2


(d) cobalt(III) nitrate
(No Response) seenKey

Co(NO3)3


(e) cesium perchlorate
(No Response) seenKey

CsClO4


(f) lithium peroxide
(No Response) seenKey

Li2O2


(g) sodium hydrogen phosphate
(No Response) seenKey

Na2HPO4

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4. /18 points ZumIntro4 7.022. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
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Total
/18
 
For each of the following precipitation reactions, complete and balance the equations. Indicate which product is the precipitate and which ruled apply. (Type your answer using the format (NH4)2S for (NH4)2S.)
(a) (NH4)2S(aq) + CoCl2(aq) (No Response) seenKey

1

(No Response) seenKey

CoS

(s) + (No Response) seenKey

2

(No Response) seenKey

NH4Cl

(aq)
precipitate
(No Response) seenKey

CoS

rule
    


(b) FeCl3(aq) + 3 NaOH(aq) (No Response) seenKey

1

(No Response) seenKey

Fe(OH)3

(s) + (No Response) seenKey

3

(No Response) seenKey

NaCl

(aq)
precipitate
(No Response) seenKey

Fe(OH)3

rule
    


(c) CuSO4(aq) + NaCO3(aq) (No Response) seenKey

1

(No Response) seenKey

CuCO3

(s) + (No Response) seenKey

1

(No Response) seenKey

Na2SO4

(aq)
precipitate
(No Response) seenKey

CuCO3

rule
    
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5. /16 points ZumIntro4 9.024. My Notes
Question Part
Points
Submissions Used
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50 0/50
Total
/16
 
For each of the following unbalanced chemical equations, calculate how many moles of the second reactant would be required to react completely with exactly 21.8 g of the first reactant. Indicate clearly the mole ratio used for each conversion.
(a) Mg(s) + CuCl2(aq) MgCl2(aq) + Cu(s)
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0.897

mol Mg (No Response) seenKey

1 mol CuCl2

/ (No Response) seenKey

1 mol Mg

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0.897

mol CuCl2
(b) AgNO3(aq) + NiCl2(aq) AgCl(s)+ Ni(NO3)2 (aq)
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0.128

mol AgNO3 (No Response) seenKey

1 mol NiCl2

/ (No Response) seenKey

2 mol AgNO3

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0.0642

mol NiCl2
(c) NaHSO3(aq) + NaOH(aq) Na2SO3(aq) + H2O(l)
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0.209

mol NaHSO3 (No Response) seenKey

1 mol NaOH

/ (No Response) seenKey

1 mol NaHSO3

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0.209

mol NaOH
(d) KHCO3(aq) + HCl(aq) KCl(aq) + H2O(l) + CO2(g)
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0.218

mol KHCO3 (No Response) seenKey

1 mol HCl

/ (No Response) seenKey

1 mol KHCO3

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0.218

mol HCl
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