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Larson-College Algebra & Calculus:Applied Approach (Homework)

James Finch

Math - College, section 1, Fall 2019

Instructor: Dr. Friendly

Current Score : 5 / 42

Due : Sunday, January 27, 2030 00:00 EST

Last Saved : n/a Saving...  ()

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    Here are some textbook questions from College Algebra and Calculus: An Applied Approach 1/e by Ron Larson published by Brooks/Cole. Click here for a list of all of the questions coded in WebAssign. This demo assignment allows many submissions and allows you to try another version of the same question for practice.

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1. 0/3 points  |  Previous Answers LarCAApCalc1 1.6.036.SBS. My Notes
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Solve the following inequality and graph its solution set on the real number line.
6
5
 x + 1 ≥ 13
STEP 1: Solve the inequality.
6
5
 x ≥
x ≥

STEP 2: Graph the solution on the real number line.
Use the tools to enter your answer.
Created with Raphaël 2.1.002468101214161820
Created with Raphaël 2.1.0

NO SOLUTION

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2. 5/6 points  |  Previous Answers LarCAApCalc1 2.1.026. My Notes
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Complete the table.
y = 4 – x2
x −2 −1 0 1 2
y Correct: Your answer is correct. Correct: Your answer is correct. Correct: Your answer is correct. Correct: Your answer is correct. Correct: Your answer is correct.

Use the resulting solution points to sketch the graph of the equation. (Plot every point and plot the graph.)
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3. –/2 points LarCAApCalc1 2.2.086. My Notes
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Consider the following point and line.
Point Line
(6, 7) x + y = 8
(a) Write the equation of the line through the point parallel to the given line.


(b) Write the equation of the line through the point perpendicular to the given line.

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4. –/2 points LarCAApCalc1 2.3.002. My Notes
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The numbers of working-age civilians (in millions) that were not involved in the labor force from 1995 to 2005 are given by the following ordered pairs.
(1995, 66.2) (1996, 66.6) (1997, 66.7)
(1998, 67.5) (1999, 68.3) (2000, 70.2)
(2001, 71.4) (2002, 72.6) (2003, 74.6)
(2004, 76.0) (2005, 76.9)
A linear model that approximates the data is y = 1.2t + 59.0, 5 ≤ t ≤ 15, where y is the number of civilians (in millions) and t = 5 represents 1995.

Plot the actual data with the model. How closely does the model represent the data?
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5. –/1 points LarCAApCalc1 2.3.034. My Notes
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A salesperson receives a monthly salary of $2600 plus a commission of 7% of sales. Write a linear equation for the salesperson's monthly wage W in terms of the person's monthly sales S.
W =

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6. –/12 points LarCAApCalc1 2.4.032.SBS. My Notes
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Evaluate the function at each specified value of the independent variable and simplify. (If the function is undefined at the specified value, enter UNDEFINED.)
g(y) = 9 − 4y
STEP 1: Evaluate g(0).
g(0) = 9 − 4( )
g(0) = 9 −
g(0) =

STEP 2: Evaluate g(9/4).
g(9/4) = 9 − 4( )
g(9/4) = 9 −
g(9/4) =

STEP 3: Evaluate g(s).
g(s) = 9 − 4(
)
g(s) = 9 − (
)
g(s) =


STEP 4: Evaluate g(s + 1).
g(s + 1) = 9 − 4(
)
g(s + 1) = 9 − (
)
g(s + 1) =


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7. –/4 points LarCAApCalc1 2.4.034. My Notes
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Evaluate the function at each specified value of the independent variable and simplify. (If the function is undefined at the specified value, enter UNDEFINED.)
k(b) = 2b2 + 9b + 4
(a)    k(0)


(b)    k(-1/2)


(c)    k(a)


(d)    k(x + 3)

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8. –/4 points LarCAApCalc1 2.5.082. My Notes
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Consider the following point.
(7, 8)
(a) Find the coordinates of a second point on the graph of a function f if the given point is on the graph and the function is even.
(x, y) = ( , )

(b) Find the coordinates of a second point on the graph of a function f if the given point is on the graph and the function is odd.
(x, y) = ( , )

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9. –/2 points LarCAApCalc1 2.6.006. My Notes
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Describe the sequence of transformations from f(x) = x2 to g. Then sketch the graph of g.
g(x) = (x + 6)2 − 3
    

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10. –/5 points LarCAApCalc1 2.7.006. My Notes
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Consider the functions below.
f(x) = 2x − 4, g(x) = 7 − x
Find the following.
(a)    (f + g)(x)


(b)    (f − g)(x)


(c)    (fg)(x)


(d)    (f/g)(x)

What is the domain of f/g?
    

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11. –/1 points LarCAApCalc1 2.8.066. My Notes
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Use the functions given below to find the composition of functions.
f(x) = x + 6
g(x) = 3x − 3
(g∘f)−1 =

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